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20 In figure, APB is a semicircle with O as centre and AQO is a semicircle with AOas diameter. If perimeter of the figure is 40 cm find the area of the shaded region.(use-22 / 7)

Answer»

so for this figure, there are 2 semicircles APB and AQO

as AO=OB=r( given)Perimeter of shaded region = circumference of semicircle APB + circumference of semicircle AQO40 =πr +πr/2

80 = 3πrr= 80/3π ...........1

Now Area of shaded region =πr^2 +π(r/2)^2 = (5πr^2)/4

Putting value of r from 1we get area of shaded region as 283.09cm^2



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