Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

How many packets each weighing 1kg can be mde rom 15 kg of swees?

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no. of packets = total weight/( weight of 1 packet)= 15/(1/3)= 45 packets

2.

FRAMSolutionWe have(1) 196 = (2x2)x(77) = 1196 = 120225 = (3x3)(5x5) → 1225 = (3x313Show that (i) V64 = 8 (ii) 781 = 9 (iii) Vio109.X2)X(7123)x(5x5) = (3x5) = 157) = 12x7) = 14100 = 10 (tv) 121 =11.EXERCISE 5COBJECTIVE QUESTIONSer in each of the following:statick (/against the correct answer in each of the follo1. (6-1-8-1-1=?1(b) -2(c) 24(d) 24la)2

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24 is the correct answer

3.

2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. Thediameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find te Framinner surface area of the vessel.a shesurmhare of same rdi

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4.

(3)If n (A) = 15, n(Au) B) = 29, n(A n B)7, then n(B) =?

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5.

Prove that < BOC = 900-02 n.24. In Δ ABC, <A = 50° and BC is produced to a point D. The bisectors of 4 ABC andZ ACD meet at E and AB || CE. Find ZE.RG CA and AB of

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6.

, Find the sum of n terms of the series12+ (12 + 22)(12+ 22 + 32)+

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Like my answer if you find it useful!

7.

Find the area of sector of angle P (in degree) of a circle with radius R.

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8.

23) In the given figure, O is the centre of thecircumcircle ABC. Tangents at A and Cintersect at P. Given angle AOB 140° andangle APC = 80°, find the angle BAC.

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9.

6.The angles of a triangle are in A. P. and its greatest angle is 75°. Find theleast angle of the triangle in radian

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10.

t to buy 5 kg of salt She got two s sta went to buy 58 Jay.t The rest of the salt she boughe in kg packets Hissesamany 2-kg packets did she buy?

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Jaya bought two packets of 3/4 kg packet

Let she bought x packets of 1/2 kg salt.

Then,2*(3/4) + x*(1/2) = 53/2 + x/2 = 53 + x = 10x = 10 - 3 = 7

Therefore, she buy 7 packets of 1/2 kg salt

11.

5. A packet can hold 4560 pins. How many pins can 287 such packets hold?

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one packet can hold 4560 pinsthen for 287 packets4560*287=1,308,720

12.

6. The angles of a triangle are in A. P and its greatest angle is 75o. Find theleast angle of the triangle in radian.

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13.

n(A)-15, n(AUB) 29, n(AnB)-7 then n(B)above sets(1) If

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14.

Q.2 Which is an ariithmetic progression from the following progressions, give reasons:(a) a, a,a',a.(b) /2, /8,v18, 32,..12 22 2 72 02(e) 16,18,20,23,ion 9 51.-3.

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(d) is in APbecause difference=-4-0=-8-(-4)=-4

15.

8 (09 (рел 02 0 bt] babk 3

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(C) 7

11² = 12112² = 14413² = 16914² = 19615² = 22516² = 25617² = 289

16.

का... 3: के» के, by SR 028073 नel (9 3०3 - 6 ००५००) 81९६० PRकि

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17.

iv)023 505 4 -9

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|A| = 1(-9+12) -1(-18+15)-2(8-5) = 3+3-6= 0

18.

a 28. Find gravitational force of a bus having mass 2500 kg which drivesthrough a curve road with radius 100 m at speed 40 km/h. / 2500 kg HTवाली एक बस का गुरुत्वाकर्षण बल ज्ञात करे जो 40 km/h. की गति से 100 m त्रिज्या केसाथ क्र सड़क से गुजरती है।

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The correct answer of this question is 1000

19.

8. An alloy contains 20% copper, 35% zinc and the rest is nickel. How much is nickel in 1.5 kg aloy?

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1.5 kg = 1500 gquantity of copper = 20*1500/100 = 20*15 = 300 gquantity of zinc = 35*1500/100 = 35*1500 = 525 gquantity of nickel = 1500 - (300+525) = 1500 - 825 = 675 g = 0.675 kg

20.

An alloy contains 40% copper, 32% nickel and rest zinc. Find the mass of zinc in one kg ofthe alloy.

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21.

-24,00,000mThe total weight of a box of 5 biscuit packets of same size is skg 400grams. Whais the weight of each packet?6.

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The weight of 5 packets of biscuit = 8kg 400 grams

1 kg = 1000 g

8kg 400 =8000 + 400 = 8400 grams

Weight of 1 biscuit = 8400 / 5= 1680 grams= 1.68 kg

22.

18. An alloy contains 40% copper, 32% nickel and rest zinc. Find the mass of zinc in one kg ofthe alloy

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280 is the correct answer of the given question

23.

18. An alloy contains 40% copper, 32% nickel and rest zinc. Find the mass of zinc in one kg ofthe alloy.

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24.

An alloy contains 32% coper, 40% nickel and rest zinc. Find the mass of the zinc in 1 kg of the alloy.-

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an alloy contains 40% copper, 32% nickel and rest zinc. find the mass of zinc in one kilogram of the alloy.

25.

the ratio of copper and zinc is 8:5 in the alloy. if the weight of zinc in the alloy is 9.5 then the weight of copper in the alloy is

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zinc in 2kg of new alloy=(5/13)+(5/8)=105/104kg

coppper in 2kg of new alloy=(8/13)+(3/8)=103/104kg

ratio of zinc and copper in the resulting alloy is'

=(105/104)/(103/104)

=105/104

weight of copper in the alloy 15.2

weight of copper in the alloy = 15.2

weight of copper = 15.2

15.2 is the right answer

weight of copper in the alloy =15.2 answer

26.

%of a sum of money is? 42. What is 20% of the same sum?129,/02 % of a weight is 0.25 kg. What is 45% of this weight?

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27.

the ratio of zinc and copper in an alloy is 7:8 if the weight of copper in the alloy is 11.7 kg find the weightof zinc in the alloy.

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or easy method hai

28.

The ratio of copper and zinc in an alloy is 9:5. If the weight of copper in the alloy is48.6 grams, find the weight of zinc in the alloy16.

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29.

(ii) number of studellls11. The ratio of the copper and zinc in an alloy is 4:7. If thetotal weight of the alloy is 12.100 kg find the weight ofeach in the alloy.

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30.

the ratio of copper and zinc in an alloy is 4:7.if the total weight of the alloy 7.7kg.find the weight of copper and zinc

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answer is wrong.

31.

A triangle ABC is drawn to circumscribe a circle of radius 4cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8cm and 6 cm respectively. find the sides AB and AC

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Thank you

32.

rThe ratio of zinc and copper in an alloy is 7:9. If the weight of copper in the alloy is 11.7kgfind the weight of zinc in it.

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33.

10. A circular park of radius 15 m has a path of10 m width around its outer side. Find thearea of the road

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34.

2.Find the area of a rectangular park, whose one side is 15 m and its diagรณnal is 39 m.

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35.

3. If an bIf anangle4.angle is 30° more than one half of its complement, find the measure of the

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36.

1. Find the angle between two vectors a and B with magnitudes 3 and 2,respectively having a b 6

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37.

5. In an alloy, ratio of copper and zinc is 7: 2.If bell of weight 45 kg is made from this alloywhat quantity of copper will be used?

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let the ratio be xcopper will be 7xzinc will be 2xTotal weight = 45 kg7x + 2x = 45 9x = 45x = 45/9x = 5so copper weight will be 7×5 = 35 kg

38.

9:4.FindthequantityofzinctoberAn alloy is to contain copper and zinc in the ratio2 kg of copper, to get the desired alloy.THINGS TO REMEMBER

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9x/11 = 12/5

x = 121/45

zinc = 4*(121/45) / 11

= 4*121/45*11

= 48/45

39.

33. H Tetlanğular field is 20 m long and14 m wide. There is a path of equal widthall around it, having an area of 111 sq.metres. Find the width of the path.

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40.

the base and altitude of a triangle are 15 cm and 8cm respectively. area of triangle is

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41.

“ रे ०६६८८. 6 नकल [8 g it G लण्डCove of ७» ooy Aer o ool be e ... eकक की हिट न e T

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42.

A rectangular field is 20 m long and 14m wide. There is a path of equal width allaround it having an area of 111 sq. metres. Find the width of the path on the outside.

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43.

A rectangular field is 20 m long and 14 m wide. There is a path of equal width allaround it having an area of 111 sq. metres. Find the width of the path on the outside

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Area of Reactangular field Ar= length * breadth= 20*14= 280 m^2

Area of Path Ap = 111 m^2

Let width of path be xArea of field with path Ao= (20 + 2x)(14 + 2x)= 280 + 40x + 28x + 4x^2

Now,Ao - Ar = Ap(4x^2 + 68x + 280) - 280= 1114x^2 + 68x - 111 = 04x^2 + 74x - 6x - 111 = 02x(2x + 37) - 3(2x + 37) = 0(2x - 3)(2x + 37) = 0 x = 3/2, - 37/2

Negative value not possible

Therefore, Width of path outside reactangular field= 1.5 m

44.

width of the room is7.garden.The area of the 4 walls of a room is 540 sq m. If the length and width of the12 m respectively, find the height of the room.in 2575 sm If a girl runs around the most

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The correct ans in 270 sq m.

270 is the correct answer

area of 4 wall=2h(l+b)2h(l+b)=5402h(15+12)=540h=10m is the right answer

we know that lateral surface area of is 2(l+b) h and its equal to 540.put the values 2(15+12) h. According to the question, 2(27) h=54054h=540h=(540/54) mh=10m

10 m is hight of room

10 m is the best answer

10 m is the correct answer.

45.

In Fig, 6.28, find the valucs of r and y and thenshow that AB||CD.50°130°Fig. 6.28

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x+50 = 180°..... ( linear pair)so, x = 180-50 = 130°

and y = 130° ... ( vertically opposite angle)

and since x = y ,forms alternate interior angles .. so, AB || CD

46.

6.28,find the values of x and y and thenFig.1.show that AB || CD50°130°Fig. 6.28

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47.

One block of cement weighs 7 3/4 kg. Find the weight of 10 blocks of cement.

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48.

. Without actual division, prove that 2r* - 57°+2r? - x+2 is divisible by2-3x+2.ulticy actly

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Factorize:

x²-3x+2x²-2x-1x+2x(x-2)-1(x-2)(x-2)(x-1)Therefore,(x-2)(x-1)are the factors.

i) (x-2)x-2=0x=2So,p(x)=2p(x)=2x⁴-5x³+2x²-x+2p(2)=2(2)⁴-5(2)³+2(2)²-2+2=32-40+8= -40+40=0Hence,it proves that (x-2) is a factor .

ii) (x-1)x-1=0x=1So,p(x)=1p(x)=2x⁴-5x³+2x²-x+2p(1)=2(1)⁴-5(1)³+2(1)²-1+2=2-5+2-1+2=6-6=0Hence,it proves that (x-1) is a factor.

Thus 2x⁴-5x³+2x²-x+2 is divisible by x²-3x+2

49.

Construct a quadrilateral ABCD, whereAB = BC = 30 cm, AD = CD = 50 cm andZABC = 120°.

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50.

The length of the minute hand of a clock is 7 cm. Find the area swept by the minutehand from 6.00 pm to 6.10 pm.

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