Saved Bookmarks
| 1. |
A rectangular field is 20 m long and 14 m wide. There is a path of equal width allaround it having an area of 111 sq. metres. Find the width of the path on the outside |
|
Answer» Area of Reactangular field Ar= length * breadth= 20*14= 280 m^2 Area of Path Ap = 111 m^2 Let width of path be xArea of field with path Ao= (20 + 2x)(14 + 2x)= 280 + 40x + 28x + 4x^2 Now,Ao - Ar = Ap(4x^2 + 68x + 280) - 280= 1114x^2 + 68x - 111 = 04x^2 + 74x - 6x - 111 = 02x(2x + 37) - 3(2x + 37) = 0(2x - 3)(2x + 37) = 0 x = 3/2, - 37/2 Negative value not possible Therefore, Width of path outside reactangular field= 1.5 m |
|