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find the value of m if the HCFof 65 and 117 |
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Answer» According to Euclid’s division algorithm,b = a × q + r, 0 ≤ r < a [using, dividend = divisor × quotient + remainder]⇒117 = 65 × 1 + 52⇒65 = 52 × 1 + 13⇒52 = 13 × 4 + 0∴HCF (65, 117) = 13 (i)Also given that, HCF (65, 117) = 65 m – 117⇒65 m – 117 = 13 [from (i)]⇒65 m = 130⇒m = 2 answer of this question is m =2 m=2 is the right answer of following questions m=2 is the answer of following question |
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