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18+6 under root 3 is the answer

(3+√3) (2+√2)²= (3+√3) (2)²+ 2(2)(√2) +(√2)²= (3+√3) (4+4√2+2)= (3+√3) (6+4√2)= 18+ 12√2 + 6√3+4√6

i) 6:9 = 2:3ii) 36:8 = 9:2iii) 96:36= 16: 6 = 8:3iv) 4:12 = 1:3v) 21:35= 3:5

1/(OA)² + 1/(TA)² = 1/36

Multiply both sides by (OA)² (TA)²(TA)² + (OA)² = (OA)² (TA)² / 36

Since TA is a tangent of the circle, then TA is perpendicular to OA, so △OAT has a right angle at A. By Pythagorean theorem:(TA)² + (OA)² = (OT)²

Therefore:(OT)² = (OA)² (TA)² / 36OT = OA * TA / 6

AB is perpendicular to OT. Therefore, AC is perpendicular to OTSince △OAT is a right triangle, dropping perpendicular from right angle A to side OT (at C) creates 2 right triangles that are both similar to △OAT

△OAT ~ △OCA ~ △ACT

By similar triangles:AC/OA = TA/OTAC = OA * TA / OTAC = OA * TA / (OA * TA / 6)AC = 6

AB = 2 * ACAB = 12

Option 2)12 cm is correct.

tq

1 m = 100cmso27.5 m = 27.5 × 100 cm = 2750.0 cm

TA and TB are tangents which are equal.Hence, angle ATO will be 30° as equal lines makes equal angleORTaking both the triangles OAT and OBT,OA = OB (radius of the circle)angle OAT = angle OBT = 90OT=OT (common side)hence by SAS congruence, the triangles are congruent with each other.Therefore angle BTO = ATO = 30

correct answer is (8a + 6b)²

correct answer is (8a+6b)

suppose 5rs passengers are x and 7.5rs passengers are yso x+y=405x+7.5y=230so x+1.5y=46x+1.5y-x-y=46-40so 0.5y=6 so y=12so x=28so 5rs passengers are 28

suppose 5rs passengers are x and 7.5rs passengers are yso x+y=405x+7.5y=230so x+1.5y=46x+1.5y-x-y=46-40so 0.5y=6 so y=12so x=28so 5rs passengers are 28

a) 10b) 27c) 201d)49

Political science is called science because it has scientific reasoning and its studied and taught in arts stream also called as humanities because arts study about the society and behavior of individuals,which helps political science in understanding the rules,laws and institutions in the society and life of individuals.

Following the pattern, 55,55=100

4. √144 + √196 - √36

12 + 13 - 6

= 19

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We know, i² = -1So, i⁴ = (-1)² = 1

So, i⁴ + i² + i = 1 - 1 + i = i

40×60=240075×days =2400days=2400÷75days=32

in 6 2/3 hours he covers 15km6 2/3 =20/3in 1 hr he will cover distance=15/(20/3)=15×3/20=9/4 km

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Speed=distance/time18km/hr=d/190min18km/hr=d/3.16hrd=18km/hr *3.16hr=56.88km

if he covers the same distance in 3 hours then speedspeed= distance/timespeed=56.88km/3hrspeed=18.96km/hr

Speed = Distance/time = 28/2 kmph =14 kmph.Now, Time to cover 56 km = 56/14 = 4 Hours.

how many triagnles can be drawn having it's Angles as 60.90.30.

Infinitely many triangles.

1. d&2. b are the right answer.. 👍

HCF=45 IS CORRECT ANSWER

135/5=27/3=9/3=3; 225/5=45/5=9/3=3; 5×3×3=45 ;

HCF = 45 IS THE CORRECT ANSWER.

45 is the right answer of given question.

Your Question is not complete

107.945 is the correct answer of the given question

107.945 is the best answer.

7/√(5)=7/√(5)*√(5)/√(5)=7√(5)/5

21/3√5+√321/3√5+√3*3√5-√3/3√5-√3=21(3√5-√3)/45-3=21/42(3√5-√3)=3√5/2-√3/2

3.06 3.57 3.6 4.08 4.18 4.2

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135 and 225

correct answer is 45

135/3=45/5=9, 225/5=45

45 is the correct answer of the given question

45 is the correct answer

225=135×1+90135=90×1+4590=45×2+0 45is the correct answer

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thank you

area= 1/2* (sum of parallel sides)*height or distance between them1/2*(10+12)*41/2*22*41/2*8844

multiply and divide by 3√5-√3hence21(3√5-√3)/9*5-321(3√5-√3)/423√5-√3/23/2√5-√3/2

i) 57/100ii) 176/1000 or 22/125iii) 100001/100000

1,0.57=57/1002,0.176=176/10003,1.00001=100001/100000

(1) 57/100. (2) 176/1000. (3) 100001/100000

(i) 0.57 = 57/100(ii) 0.176= 176/1000(iii) 1.00001 = 100001/100000

1. 57/1002. 176/1000 or 22/1253. 100001/100000

(57/100 ) 2q ( 176/1000) 3q 100001/100000

To Prove: AE/ED = BF/FC

Proof: Given AB||DC and EF||ADSo, EF||DC (Since, lines parallel to same line are parallel to one another)

Now, join A and C. And let AC intersect EF at point G.

Therefore, in triangle ADC,EG|| DC

So, AE/ED = AG/GC (Since, lines drawn parallel to one side of triangle intersects the other two sides in distinct points. Then it divides the other two side in the same ratio)

Hence, Proved

Consider,

2√3 + √11

Squaring,

( 2√3 + √11 )^2

This is of the algebraic expression ( a + b )^2

( a + b )^2 = a^2 + 2 ( a ) ( b ) + b^2

Substituing,

We get,

( 2√3 )^2 + 2 ( 2√3 ) ( √11 ) + ( √11 )^2

4 ( 3 ) + 4 ( √3 ) ( √11 ) + 11

23 + 4√33

Here,

4 = √16

Substituting,

We get,

23 + √16 * √33

23 + √528

Taking square root on both sides,

√23+√528

Hence, √23 + √528 = 2√3 + √11

Let us join AC to intersect EF at G .

AB // DC and EF // AB ( given )

=> EF // DC

[ Lines parallel to the same line are

parallel to each other. ]

In ∆ADC , EG // DC

AE/ED = AG/GC ---- ( 1 )

[ By Basic Proportionality theorem ]

Similarly ,

In ∆CAB , GF // AB

CG/GA = CF/FB

[ By basic Proportionality theorem ]

AG/GC = BF/FC ---( 2 )

from ( 1 ) and ( 2 ) ,

AE/ED = BF/FC

=> AE/BF = ED/FC

Hence proved.