1.

वा, + /2= 825 +€T) : 5 PR °T

Answer»

Consider,

2√3 + √11

Squaring,

( 2√3 + √11 )^2

This is of the algebraic expression ( a + b )^2

( a + b )^2 = a^2 + 2 ( a ) ( b ) + b^2

Substituing,

We get,

( 2√3 )^2 + 2 ( 2√3 ) ( √11 ) + ( √11 )^2

4 ( 3 ) + 4 ( √3 ) ( √11 ) + 11

23 + 4√33

Here,

4 = √16

Substituting,

We get,

23 + √16 * √33

23 + √528

Taking square root on both sides,

√23+√528

Hence, √23 + √528 = 2√3 + √11



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