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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Example 2 : ABCD is a trapezium with AB DCE andFare points on non-parallel sides AD and BCrespectively such that EF is parallel to ABAE BF(see Fig. 6.14). Show that -FC |
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| 2. |
कीजिए--दे 31- 620 -09+ 5-23 |
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Answer» (31-62) - (19+3-21)= -31 - 0= -31. Please hit the like button if this helped you |
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| 3. |
135*(text*(825*(a*(d*n)))) |
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Answer» 135 + 225 =360is correct answer of following question |
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| 4. |
प्रश्न 5. एक रलगाड़ा 9७ 1कसा/ घटा काऔसत गति से 2 दर घण्टे तक चलती हैऔर उसके बाद 70 कि.मी. /घण्टां कीगति से 1; घण्टे चलती है, तदनुसार, उसपूरी यात्रा में उस रेलगाड़ी की औसत गतिकितने किमी /घण्टा है?825 (3) 575 |
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Answer» Avg velocity = total distance/total time= औसत चाल बराबर कुल विस्थापन भाग/ कुल समयS1= 50km/hr, 2.5 hourयहां हमें समय तथा चाल दी गई है इससे हमने विस्थापन ज्ञात किया तथा फिर उस विस्थापन को इस फार्मूले में रख दियाD1= 125 kmS2= 70km/hr, 1.5 hourD2= 105kmnow = 105+175/4 में कुल दूरी मिल गईकुल दूरी को हमने कुल समय से भाग दे दियाइससे हमको औसत गति मिल गई= 230/4= 57.5 |
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| 5. |
Army GD(d)925(a)625(b) 825(c) 725 |
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Answer» 45 percentage= 675तब 1 percentage= 675/45= 1555 percentage= 15*55825Opti on= B |
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| 6. |
(a) 300(b) 620(c) 720(d) 500 |
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| 7. |
S A truck covers the distance of 825 km in 15 hours. Calculate the speed of |
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Answer» Speed = distance/time Here,distance = 825 kmtime = 15 hrsspeed = 825/15 = 55km/hr |
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| 8. |
s6 The arithmetic mean of the series is 30.5. Find the missing figure.40501082010X:20157 |
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Answer» Let the missing value be x. Mean = sum of all values / sum of frequency of every value.=> 30.5 = [ 10*8 + 20*10 +x*20 + 40*15+50*7] / (8+10+20+15+7)=> 30.5 = [1230+20x] / 60=> 1830 = 1230+20x=> 600= 20x=> x = 30. PLEASE HIT THE LIKE BUTTON hii hello you ignoring me |
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| 9. |
7. Find the point on the x-axis which is equidistant from (2,-5) and (-2,9).tho points P2 -3) and O(1 |
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| 10. |
7. Express |
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Answer» Firstly consider L.H.S ; NOW rationalise √ 1 +SinA √ 1+ SinA--------------- x ----------------√ 1- SinA √1 + SinA √ ( 1+ SinA)² 1+ SinA------------------ = --------------√ 1² - Sin²A Cos² A Now consider RHS = Sec A + Tan A =1/ Cos A + SinA / CosA =1 + SinA / CosA Hence proved .... |
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| 11. |
CBSE 2015]4. Find the ratio in which the line segment joining (-2,-3) and (5,6) is divided by (i) r-axis(i) y-axis. Also, find the coordinates of tho |
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| 12. |
·The base ofan isosceles triangle is 1 0 cm and one ofits sides is 8 cm. Find the area ofthe triangle. |
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Answer» But the ans is 31.22 sqcm |
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| 13. |
7. Express as a single matrix : |
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| 14. |
7. In a city, 30% are females, 40% are males and remaining are children, what percentare children? |
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Answer» I don't clearly understand |
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| 15. |
8. Fig. 12.26 depicts a racing track whose left and right ends aFig. 12.26Tho dit |
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| 16. |
nterext of goo |
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Answer» If you like the solution, Please give it a 👍 |
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| 17. |
Find the [ HCF Ă LCM ] for tho numbers 100 and 190. |
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Answer» We know LCM × HCF = Product of numbers, So, LCM × HCF = 100 × 190 = 19000,0 |
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| 18. |
(11) 49000 + 4200 + 620 + 54 |
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Answer» Sum of 49000 + 4200 +620 + 54= 49000 + 4200 + 674= 49000 + 4874= 53874 |
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| 19. |
(1) CP = 620 and SP = 713 |
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| 20. |
piller has a diameter of S6 cm andthothe building Find the cost of |
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| 21. |
4. If the lateral surface of a cylinder is 94.2 cm and its height is 5 cm. then find(i)radius ofits base(ii) its volume. (Use π3.14) |
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| 22. |
Find tho dointile2 |
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Answer» (a+b÷b+c)×sec^2x ........................................... |
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| 23. |
You have read the lesson "Attitude is Altitude". You have known about the coursechallenging, valiant, optimistic, sociable and self-motivated nature of Nick to quethe hurdles he faced in his life. |
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Answer» which food materials do we consume to obtain these nutrients |
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| 24. |
The height of a parallelogram is one third of its base. If the area of the parallelogram is192cm, find its height and base. |
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Answer» Let base of Parallelogram = xThen height of Parallelogram = x/3 Area of pallelogram = Base * Height192 = x*x/3x^2 = 576x = 24 Base = 24 cmHeight = 24/3 = 8 cm |
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| 25. |
(2.7 Express 0.975 in the form p q, where p and q are integers and q#08 What is tho |
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| 26. |
- $द्वि व बाल-कं) 8/)4st) 8q)2 |
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Answer» cube root 8 As 2³ = 8 So, cube root 8 = 2 |
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| 27. |
Q.16Find the values of the unknowns in the following figures:25 |
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Answer» y = 80° ( opposite angle are equal in parallelogram) z = 80° ( corresponding angle) x = 180° - 80° x = 100° ( adjacent angles) Next question angle 1 = 180° - 125° = 55° Similarly angle 2 = 55° angle a = angle 1 + angle 2 ( exterior angle theorem) angle a = 55° + 55° = 110° |
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| 28. |
Calculate the values of p, q and r in each ofthe following figures:goo620 |
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Answer» answer Sum of all angles of the triangle = 180 Thus,80 + 62 + r = 180r = 180 - (142)r = 38° q = 80°(Alternate angles) Now,p + q + r = 180(Linear Pair)p + 80 + 38 = 180p = 180 - 118 = 62° |
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| 29. |
Q.8 whatshould be addedto st to get |
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Answer» the answer is always true 19/4=4 3/4 is the correct answer yhomework app is good to solve such questions 19/4 is the right answer..... |
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| 30. |
then find tho vnluo of sinoandCot |
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| 31. |
6.Find the radius of a sphere whose surface area is 154 cmi |
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| 32. |
The height of a parallelogram is one third ofits base. If the area of the parallelogram is192cm2, find its height and base. |
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Answer» thanks answer thappu |
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| 33. |
4.Expand: (1) (3x - 2y)? |
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Answer» (a-b)^2=a^2+b^2-2abhence(3x-2y)^2=9x^2+4y^2-12xy |
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| 34. |
4. Expand the following.og1000(ii) |
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| 35. |
1. Expanda) (k + 4) |
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Answer» .( k+4)^3=k^3+64+3k4( k+4); = k^3+64+12k(k+4) |
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| 36. |
Expand (4-1/3x)^3) |
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| 37. |
POLYNOMALS4Expand each of the followingi) x + 2y +43) |
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| 38. |
6. In the fig. 11.18 if EFİDClIABFig. 11.18then prove thatAE BFED FC |
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| 39. |
In the given figure, If ABCD is a trapezium in which AB | ICD | |EF, then proveAE BFthatED FC8 |
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| 40. |
The aumhey ofst q nificantfigures ina(a) Tuob) ThreeC) nfiteel) one |
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Answer» Trailing zeros in a whole number with no decimal shown are NOT significant. Writing just "410" indicates that the zero is NOT significant, and there are only TWO significant figures in this value. hence, option (a) is correct. |
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| 41. |
z9 Find the area of a trapezium whose parallel sides are 11 m and 2long, and the nonparallel sides are 15 m and 13 m long.40. The difference between the lengths of the parallel sides of a trapezis 8 cm, the perpendicular distance between these sides is 24 cm andarea of the trapezium is 312 cm . Find the length of each of the parsides.2 |
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Answer» 39) here is a similar ques- |
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| 42. |
Palaiel sides is 84m, ind the otherpaThe area of a trapezium is 405 cmi 2 . Its parallel sides are in the ratio 4 : 5 and theFind the length of each of the parallel sides.thecm.6d etween them is 18 cm. |
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| 43. |
7 The area of atrapezium of altitude 3 m is 12 m2. If one of the parallel sides is 2 mthmore than the other, then find the lengths of parallel sides of the trapezium.8 Find tho |
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Answer» ........ ........ .. . .. . |
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| 44. |
by 14Each of the two equal sides of an isosceles triangle is three times as large as the third side.If the perimeter of the triangle is 28 cm, find each side of the trianglefn square is represented by 4x -7 and the adjacent side is represented by 3x + 5, find the |
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Answer» Let the third side be y cmthen A/Q the other two equal sides are 3y cmHence,Perimeter=sum of all sides28= y+3y+3y=>28=7y=>y=4hence the sides are 4cm,12cm,12cm |
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| 45. |
Find the area of trapezium whose parallel sides are 10 cm and 2 m and its altitude is 1.5 m14fn trnnum is 15 cm and the lengths of parallel sides are 26 |
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| 46. |
= § cos’ 60° + 4 sec’ 30° —tan” 45°sin’ 30° + cos’ 30° T A W row W |
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| 47. |
(2) D, E and F are the midpoints of the sides AB, BC and CA respectively ofΔ ABC.A(ADEF)A(AABC)Find |
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| 48. |
ite in digits) Eight hundred forty nine |
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Answer» In digits eight hundred forty nine will be 849 |
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| 49. |
Write the numerals for these nameFour hundred forty fiveSix hundred seventy one |
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Answer» (a) Four hundred forty five = 445(b) six hundred seventy one = 671 Four hundred forty five=445Six hundred seventy one=671 |
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| 50. |
A rectangular carpet has an area of 60 sq.m its diagonal and longer side together equal 5 times the shorter side. The length of the carpet is |
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