Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
rhombus shuped field bas greenhombus is 30 m and its longer diagonal i5 45 mhow mucth area of grass ficldwill eachow be getting?grass for iscowsgze i each side of the |
| Answer» | |
| 2. |
In a trapezium, the lengths of its parallesides are a and b. The length of the linejoining the midpoints of its non-parallelsides 1s2) a+ b22(3) ab24) aba+ b |
|
Answer» The length of the line joining the midpoints of its non-parallel sides is (a+b)/2. Length of the line = a + (b - a)/2 = (2a+b-a)/2= (a+b)/2 HOPE THIS HELPS YOUPLEASE HIT THE LIKE BUTTON |
|
| 3. |
BC. Prove thatIn an equilateral Δ ABC, D is a point on side BC such that BD9(AD)2 - 7(AB)2OR |
| Answer» | |
| 4. |
1. P, Q, R and S are respectively the midpoints of thesides AB, BC, CD and DA of a quadrilateral ABCD.Show that(i) PQIAC and PQ-TAC |
| Answer» | |
| 5. |
I find the wroes of following polynomialI by factorisation method & verify theCelation Blw the efficient of polynomias28²_(1+2 12/st2.♡ 4.2_4506-15 |
| Answer» | |
| 6. |
11. Rakesh's age is 10% that,of Mohan's age and 20% that of Shyam's age.Whąt percentage of Mohan's age is Shyam's age ? |
|
Answer» R = 10%MR =20%S10%M = 20%SS = 1/2Mor M =2SHence Mohan is 200% of Shayam's age !! |
|
| 7. |
2No.2 Aslam's father present age is 3 times Aslam's ageAslam's grandfather's age is 13 years more than thesome of Avlam's age and Aslam's father's age HoYou find Aslam's grandfather's age? |
| Answer» | |
| 8. |
36. In how many weeks will x horses eat 100 kg of grain if one horseeats y kg a week? |
| Answer» | |
| 9. |
If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, whatis the area of the quadrilateral?3. |
|
Answer» A rhombus has four equal sides. The perimeter of a rhombus is 100 cm. 4a=100a=25 The measure of each side is 25. 4a^2=d1^2+d2^2 Where, a is side length and d₁ and d₂ are diagonals. 4(25)^2=(48)^2+d2^22500=2304+d2^2d2=√2500-2304d2=14 The area of rhombus isA=1/2(d1d2)A=1/2(48)(14)A=336cm^2 Therefor the area of quadrilateral is 336 cm². |
|
| 10. |
A photo frame is in the shape of a quadrilateral. Withone diagonal longer than the other. It is a rectangle? Why orwhy not? |
|
Answer» it is not a rectangle because the diagonal of rectangle are always equal |
|
| 11. |
1. P, Q, R and S are respectively the midpoints of thesides AB, BC, CD and DA of a quadrilateral ABCDShow that(u) PQISR(i) PORS is a parallelogram. |
| Answer» | |
| 12. |
any triangle ABC, prove that,)2bc |
| Answer» | |
| 13. |
A, B, C are interior angles of ABC. Prove that cosec (-2-)-ec2 |
| Answer» | |
| 14. |
2.A wheel of circumference C is at rest on theground. When the wheel rolls forward throughhalf revolution, then, the displacement of initialpoint of contact will be |
| Answer» | |
| 15. |
प्रश्न 4. मान निकालिए (Evaluate):tan 26° - cot 64° |
|
Answer» 0 is the correct answer me to be 0. is a correct answer 0 is the correct answer 0 is the correct answer of the given question 0 is the correct answer answer is 0 because if tan is changed to cot,they will be sameand same subtracted by same is always0 0 is the right answer 0 is the answer of this question 0 is the correct answer the correct answer is 0 the correct answer is 0 0 is correct answer according to me 0 is the correct answer 0 is the correct answer me to be 0 is the correct answer |
|
| 16. |
find the angle blw the surfaces.fax + y +2²9 g = x +y +-320at (21-12) |
| Answer» | |
| 17. |
For any triangle ABC, prove thatA Bcosa + b3.sin2 |
| Answer» | |
| 18. |
प्रश्नावली- 7.41. किसी शहर की जनसंख्या वृद्धि दर 5% है। यदि शहर की वर्तमान जनसंख्या 64000 है तो 3वर्ष पश्चात की जनसंख्या ज्ञात करो ? |
|
Answer» 64000*5%=32003200*3=960064000+9600=73600 people's 73600 is the right answer of the following 73600 is the right answer of the following 73600 is the right answer of the following 73600 is the correct answer of the given question may be 14000answer of this question |
|
| 19. |
2. In a quadrilateral one diagonal divides the other in the ratio of 1: 2 at the point of intersectionL itparallelogram? If yes, why? If not, why? |
|
Answer» LetABCDbethequadrilateralinwhichACandBDarethediagonalsthatintersectatO.Now,AOOC=12 Weknowthatdiagonalsofaparallelogrambisecteahother. So,forABCDtobeaparallelogram,AOOC=11ButhereAOOC=12. So,thequadrilateralcan'tbeaparallelograminwhichpointofintersectionofthediagonalsdivideonediagonalintheratioof1: 2. |
|
| 20. |
whose vcriougiven triangle.4. Find the area of the quadrilateral whose vertices, taken in order, are(4-2), (-3,-(3,-2) and (2,3)or0 Eyamnle 3) that a median of a triangle divides |
| Answer» | |
| 21. |
. If E, F G and H are respectively themidpoints ofthe sides AB, BC, CD and ADof a parallelogram ABCD, show thatar(EFGH)ar(ABCD) |
| Answer» | |
| 22. |
anya has a piece of land which is in the shape of a rhombus13). She wants her one daughter and one son to work on the land andthe land in two equal parts. If the perimeter of490 m and one of the diagonals is 160 m, how much area each of them wills theEam. theproduce different crops. She dividedthe langet for their crops?d is |
|
Answer» Let ABCD be the field. Given perimeter = 400 m So, each side = 400/4 = 100 m Diagonal BD = 160 m Let a = 100 m, b = 100 m, c = 160 m ∴s = (a + b + c)/2 = (100 + 100 + 160)/2 = 180 m. Therefore, Area of△ABD = root under (√s(s - a)(s - b)(s - c)) =root under (√180(180 - 100)(180 - 100)(180 - 160)) =root under (√180 x 80 x 80 x 20) = 4800 m2 Like if you find it useful |
|
| 23. |
Mhe. Find tonrational number blw-2and |
| Answer» | |
| 24. |
(d) Ina A ABC prove thatsin |
|
Answer» let A=B=C= 60degree and solve the sum u'll get 1.... let A=B=C=60degree and solve the sum you will get 1 |
|
| 25. |
Ton 26Cotspo Evaluate. |
|
Answer» tan 26°/ cot 64° = tan 26°/tan(90 - 64)° = tan 26°/ tan 26° = 1 |
|
| 26. |
anya uses 18 m of lace to make 2 dresses (of the same size and design). Howuch lace will she need to make 16 such dresses? |
|
Answer» Lace for 2 dresses=18 mLace for 1 dress=18/2=9mLace for 16 dresses=9*16=144m |
|
| 27. |
ProjectUnder the guidance of your teachersmake a 'free-energy generator |
|
Answer» Magnet Enginefree energy generatoris an easy device to generate electricalenergy. It works on the principle of Neodymium Magnets. In a simple motor, magnetic field is created by theelectriccoils generally Cu, Al coils. These motors continuously need electrical supply to produce magnetic field. |
|
| 28. |
ton 2. (ot 62 = gec?92 |
|
Answer» answer of this question is -1 |
|
| 29. |
Whot is Applied Mechonics ?ay 15 |
|
Answer» Applied mechanics(alsoengineering mechanics) is a branch of thephysical sciencesand the practical application ofmechanics.Applied mechanics describes the behavior of a body, in either a beginning state of rest or of motion, subjected to the action of forces.Applied mechanics, bridges the gap between physical theory and its application totechnology. It is used in many fields ofengineering, especiallymechanical engineeringandcivil engineering. |
|
| 30. |
Solve ton :- |
| Answer» | |
| 31. |
ㅡ ㅡ.ㅡ form-anequatioL footu fallauintLa ses,The Sum af twe consecutive numbers is 51 |
|
Answer» Let first number be x. x+(x+1)=512x+1=512x=50x=50/2x=25 Therefore the two numbers are 25 and 26 |
|
| 32. |
42) Write an example of an irreversiblereaction. |
|
Answer» The neutralization of sodium hydroxide with hydrochloric acid. |
|
| 33. |
x^{2} \times x^{4} |
| Answer» | |
| 34. |
ses 18 m of lace to make 2 dresses (of the same stze and densipi, Hoch lace will she need to make 16 such dresses?4 Tanya uses 18 |
|
Answer» Lace for 2 dresses=18mLace for 1 dress=18/2=9mLace for 16 dresses=9*16=144 m |
|
| 35. |
are 6saGoo this ina Schoole hatisthe pÄ.cenaneSchool |
|
Answer» Total number of students= 600+650 =1250 So % of girls = no. of girls ×100/total students=600×100/1250 =48% iska ans ye nahi hai mem |
|
| 36. |
RILA TON |
|
Answer» Apopulationis the number of living things that live together in the same place. A city'spopulationis the number of people living in that city. These people are called inhabitants or residents. |
|
| 37. |
^ { 2 } \varphi + 2 = \operatorname { sec } ^ { 2 } \varphi \operatorname { cosec } ^ { 2 } \varphi |
| Answer» | |
| 38. |
22. Find the value of K such that the points. A(K.3), B(2-5).C(-K+2,-2) are coliinear. |
|
Answer» its wrong answer is 6/11 |
|
| 39. |
H) The lengths of parallel sides of a trapezium are in the ratio 7:5 and the distancebetween them is 14 cm. If the area of the trapezium is 252 cm2, find the lengths ofits parallel sides. |
| Answer» | |
| 40. |
11 Piove COSA- §'nA t)= 094 प ने (09६ हैCosA t §inA -| |
|
Answer» like if you find it useful cosA-sinA+1/cosA+sinA-1=(cosA-sinA+1)(cosA+sinA+1)/(cosA+sinA-1)(cosA+sinA+1)=(cos²A-cosAsinA+cosA+cosAsinA-sin²A+sinA+cosA-sinA+1)/{(cosA+sinA)²-(1)²}=(cos²A-sin²A+2cosA+1)/(cos²A+2cosAsinA+sin²A-1)={cos²A+2cosA+(1-sin²A)}/(1+2cosAsinA-1) [∵, sin²A+cos²A=1]=(cos²A+2cosA+cos²A)/2cosAsinA=(2cos²A+2cosA)/2cosAsinA=2cosA(cosA+1)/2cosAsinA=(cosA+1)/sinA=cosA/sinA+1/sinA=cotA+cosecA=cosecA+cotA (Proved) |
|
| 41. |
14.Ina△ABC medianAD is produced to X such thatAD-DX. Prove thatABXcis aparallelogan. |
| Answer» | |
| 42. |
of the triangle with vertices (4, 6), С7, 10) and (1,-2) remains invariantthe translation of aes when the origin is shifted to the point(-2.1)INCERTIthat the areaVerityundet |
| Answer» | |
| 43. |
y taken away from 4 times x. |
|
Answer» equation will be4x-y |
|
| 44. |
Discuss:. How many 2s have been taken away when you reach zero? |
|
Answer» Please post the complete question. Some part of the question is missing. |
|
| 45. |
= \tau %2B \varphi |
|
Answer» the answer is 4 ok brother |
|
| 46. |
tau O. ton 90 |
|
Answer» Question you have submitted is incomplete. Please post a complete question. now cleared question sir The Formulas to be used in this Questions are:=>cos(90 - x) = sin x e.g. cos 22 = cos(90-68)= sin 22=>tan(90 - x) = cot x e.g. cot 15 = cot(90-75) = tan 15=>tanx.cotx = 1 Now Question is, 2sin68/cos22 - 2cot15/5tan75 - (3/5)tan45 tan20 tan40 tan50 tan70=2sin68/sin68 - 2tan75/5tan75 - (3/5)1 tan20 tan40 cot40 cot 20 =2 - 2/5 - 3/5= 1This is the Answer |
|
| 47. |
\frac { 9 } { I } \times \frac { S } { \varepsilon } - \frac { \tau } { S } + \frac { S } { \varepsilon } \times \frac { \varepsilon } { Z } - |
|
Answer» -2/3*3/5+5/2-3/5*1/6-2/5+5/2-1/10-4+25/10-1/1021/10-1/10=20/10=2 thanks |
|
| 48. |
kample 8.8: What percent of 360 is 144? |
| Answer» | |
| 49. |
If lines AB, AC, AD and AE are parallel to a line l,show that A,B,CD,E arecoliinear |
|
Answer» But we can see that all four lines are have one common point A , And we can't draw 4 different lines as they parallel to each other ,But If A , B , C , D and E are on same line than they can satisfied our given condition and as well as properties of parallel line ...... Thanks |
|
| 50. |
ards marked with number 3, 4, 5,..., 50 are placed in a box and mixed thorouA card is drawn at random from the box. Find the probability that the selected cardbears a perfect square number.Delhil |
| Answer» | |