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If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, whatis the area of the quadrilateral?3. |
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Answer» A rhombus has four equal sides. The perimeter of a rhombus is 100 cm. 4a=100a=25 The measure of each side is 25. 4a^2=d1^2+d2^2 Where, a is side length and d₁ and d₂ are diagonals. 4(25)^2=(48)^2+d2^22500=2304+d2^2d2=√2500-2304d2=14 The area of rhombus isA=1/2(d1d2)A=1/2(48)(14)A=336cm^2 Therefor the area of quadrilateral is 336 cm². |
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