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tau O. ton 90

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now cleared question sir

The Formulas to be used in this Questions are:=>cos(90 - x) = sin x e.g. cos 22 = cos(90-68)= sin 22=>tan(90 - x) = cot x e.g. cot 15 = cot(90-75) = tan 15=>tanx.cotx = 1

Now Question is, 2sin68/cos22 - 2cot15/5tan75 - (3/5)tan45 tan20 tan40 tan50 tan70=2sin68/sin68 - 2tan75/5tan75 - (3/5)1 tan20 tan40 cot40 cot 20

=2 - 2/5 - 3/5= 1This is the Answer


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