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ABCD is a trapezium with AB | I DC. E and F are points on non-parallel sides AD and BC respectivelysuch that EF is parallel to AB¡Show that =". |
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Answer» To Prove: AE/ED = BF/FC Proof: Given AB||DC and EF||ADSo, EF||DC (Since, lines parallel to same line are parallel to one another) Now, join A and C. And let AC intersect EF at point G. Therefore, in triangle ADC,EG|| DC So, AE/ED = AG/GC (Since, lines drawn parallel to one side of triangle intersects the other two sides in distinct points. Then it divides the other two side in the same ratio) Hence, Proved |
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