Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Name.Q1. Find the Common factors.120 a b, 10 a^{2} b^{2}, 15 a b^{2}

Answer»

20ab = 2*2*5*a*b

10a²b² = 2*5*a*a*b*b

15ab² = 3*5*a*b*b

common factors = 5ab

Thanks

2.

Q1. Write down all the integers between -5 and 6.2--

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3.

Find the value of(i) log 1/28(11) logs0.008

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log₁ₗ₂8=-3log₅ 0.008=-3

4.

prove that= cotais sin2x- cos2x- tan2xil- cosaxIt LO S 22

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5.

10. If the ratio of the zeroes of the expressionx2 + px + 9 is equal to the ratio of the zeroes ofx? + Ix + m, then1) pm=q12) pm2 = q-13)p'l = q m4) p?m=129

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6.

itiL s 528 || ProveHak Lo

Answer»

2.7^n+ 3.5^n-5 is divisible by 24---- to prove

put n=1

14+15-4=24

p(1) true.

put n=k

2.7^k+ 3.5^k-5=24m-------1)

to prove: n=k+1 is true

put n= k+1

2.7.7^k+3.5.5^k-5

from 1) -5=24m-2.7^k-3.5^k

14.7^k+15.5^k+24m-2.7^k-3.5^k

24m+7^k(14-2)+5^k(15-03)

24m+12.7^k+12.5^k

24(m+7^k/2+5^k/2)

24 multiplied by any digit means it is divisible by 24.

by p.m.i. it is proved that n is true for N

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7.

A Sum3000 is be given inAYTst och

Answer»

i want were the boxes are their

8.

The polynomials x^3+2x^2-5ax-8 and x^3-ax^2-12x-6 when divided by x-2 and x-3 respectively. Leave the remainder p and q. If q-p=10 find a

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9.

to leave2. What must be taken from 3to

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7/6 is the answer of this question

7/6is the answer of this question

10.

12.If the expression px +3x-3and 2x -5x + p when divided by x - 4leave the same remainder, then the valueof p is(a) 0(c) 2(d) 3

Answer»

Given polynomials arepx³+3x²-3and2x³-5x+p

It is also given that these two polynomials leave the same remainder when divided byx-4

p(4)³+3(4)²-3 = 2(4)³-5(4)+p

64p+48-3 = 128-20+p

64p-p = 108-45

63p = 63

p = 1

Like my answer if you find it useful!

11.

Java program on palindrome of a number

Answer»

class PalindromeExample{ public static void main(String args[]){ int r,sum=0,temp; int n=454;//It is the number variable to be checked for palindrome temp=n; while(n>0){ r=n%10; //getting remainder sum=(sum*10)+r; n=n/10; } if(temp==sum) System.out.println("palindrome number "); else System.out.println("not palindrome"); } }

output

12.

LIT (V

Answer»

1/(49)-½= (49)½= √49= 7

13.

Harba has some blankets. with him. The cost (in rupees) of a blanket is twice the number of blankets. If he has blankets worth 4608. how many blankets does he have?(1) 52 #2) 48 (3) 58 (4) 96

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Given cost of blanket is twice the number of blanketslet cost of blanket is x and number of blankets is 2xSo given total cost of blanket is ₹4608so Equation will be4608 = 2x × xx² = 2304x = √2304x = 48option (2) is correct

2304 root is 48

sorry for inconvenience check this one,Given cost of blanket is twice the number of blanketslet cost of blanket is x and number of blankets is 2xSo given total cost of blanket is ₹4608so Equation will be4608 = 2x × xx² = 2304x = √2304x = 48option (2) is correct

14.

Evaluate(o -(27) Leave your amsve s taction(27)3 Leave your answer as a fraction.

Answer»

is Ka answers aapko Nahi pata h

15.

[P.0.1993)48. 4+3+2= ?20.094 = 44.864(2) 32.755(4) 12.109787 [Bank P.O. 2009)57.78 + ? = 453.072(2) 5(3) 10(4) 46(5)*7$ 7W [P.O. 1991, CBI 2006](2) 235.293(4) 75.148787 [P.O. 1991, CET 2008]-82 = 43.41(2) 11.09(4) 107.91[P.O. 1991, RRB 2005].36 + 450.478(3) 1 2 3 (4)(5)50. 12+13 - = ?[P.O. 1989, SBI 2008)2) 23.032

Answer»

questions 50. of the answers 35/20

Amen earns 250 per day working 7 Hata De find his earning after he has worked for 5 days working in in 5 hours

16.

39.Two cards are drawn from a pack of 52 cards in succession. Find theprobability that both are kings when,() The first drawn card is replaced(ii) The card is not replaced.

Answer»

There are 4 Kings in a deck.(i) So the probability of drawing a king is 4/52if the card is replaced, then again the probability would be 4/52.so joint probability would be= (4/52)x(4/52)=1/169(ans)(ii) the probability of drawing a king out of 52 cards is 4/52.the probability of drawing a king out of 51 cards is (3/51)so joint probability is (4/52)x(3/51)=1/221(ans)

17.

How is oxygen replaced ?

Answer»
18.

29. (i) A hemisphere of maximum possible diameter is placed over acuboidal block of side 7 cm. Find the surface area of the solid soformed.(CBSE 2017]

Answer»

Surface area of solid= Surface area of Cuboid having side 7 cm + Surface area of Hemisphere having maximum diameter

= 6×(Side)² + 3 πR² where R is radius of sphere.

= 6×7² + 3×22/7×(7/2)²

= 6×49+ 3×22/7×49/4

=294 +115.50

= 409.50 cm²

If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid.

19.

A train starts from rest and moves with a constantceleration of 20 m/s for half a minute. The brakesapplied and the train comes to rest in onete. Find the total distance moved by the train,aximum speed attained by the train and (c) theO acminub) theposition(s) of the train at half theelet travelling with a velocity of e

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20.

3) Ifx-3 is a root of equation kr-10x+302,then k-(a) -3 (b) 3 (c) 9 (d)4) Adie is rolled then ti

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21.

A transmitting antenna at the top of a tower has32 m and the height of the receiving antenna is 50 m. What ismaximum distance between them for satisfactory communicationLOS mode? Given radius of earth 6.4 x 10^6 m

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22.

12. The ratio of distance moved by the effort to the distance by the load is calleda. Efficiencyb. Velocity ratioc. Mechanical advantaged. All of these

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Velocity ratio= distance moved by effort _____________________ distance by loadAns:b

23.

42. The polynomials p(x)x3x+5 and q(x)+ k when divided by x-2 leavehe polynomials px)-2+o-3x+5 and g(x)k when divided by x -2 leavethe remainder ri and r2 respectively. Find the value of k, if ri -12-0(a) k=-1(b)き-2(c) k=-53(d) k=-

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24.

17. A muset 25% of his money to his mother, 55% to his daughter and the remainingマ9000 to his broHow much money did he leave? Find the shares of his mother and dauthter

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25.

9.There were 4312 bags of cement in a godown. If 3425 bags weresold out, how many bags were left in the godown?

Answer»

887 bags were left in the godown

887 is the answer of the following

887 is right ans .

26.

Rearrange my digit to write the smallest number of 5 digit

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11111 is correct answer

10000 is correct answer

12345 is the correct answer

27.

5. The following table shows the weight of 12 players:nuia,Calculateits mode.Weight (in kg)Number of players48505254584322Find the median and mean weights.Using empirical formula, calculate its mode.

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28.

525458Weight (in kg)Number of players48502243Find the median and mean weights.Using empirical formula, calculate its mode.

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29.

гкpost mod went do dvad R-ans lepuo aves - amaga ) Rt omgee or

Answer»
30.

Find Mod of -4

Answer»

mod of -4 is 4 like my answer

31.

me ingangus 28is6Mussthenitsmod foamITeachers Signature

Answer»

Let terms of AP are a, a + d, a + 2d, a + 3d, a + 4d

Then,a*(a + 4d) = 28.... (1)

As per given condition(a + 2d) - a = 62d = 6d = 3

Put value of d in eq(1)a(a + 4*3) = 28a^2 + 12a - 28 = 0a^2 + 14a - 2a - 28 = 0a(a + 14) - 2(a - 14) = 0(a - 2)(a + 14) = 0a = 2, - 14

Thus, For a = 2, d = 3AP is 2, 5, 8, 11, 14

For a = - 14, d = 3AP is - 14, - 11, - 8, - 5, - 2

32.

The scale on a map is 1mm :4 m Find the distance on the map for an actualdistance of 84m

Answer»

On map 4m is equal to 1mm scaleActual distance 1m = 1/4mm scale

Distance on map for 84 m actual distance= 84/4 mm= 21 mm scale

33.

Find the value of k, for which one root of the quadratic equation kr. 14x+8-02-

Answer»
34.

LosXFind X.

Answer»

Sum of all the angles of triangle is 180°

So, 105°+57°+x = 180° 162°+x = 180° x = 180° - 162° x = 18°

35.

47ioshow that los, bd-30

Answer»

tnx 👍

36.

A farmer obtained a yielding of 1720 bags of cotton last year. This year she expects hercrop to be 20% more. How many bags of cotton does she expect this year?

Answer»

Last year number of bags 1720Increase in % = 20%so, 1720 of 20% = 1720×20/100 = 172×2 = 344Total bags = 1720+344 = 2064

37.

3. For what value of P, the quadratic equationPx+ 8x - 2 = 0 has real roots.

Answer»

p Greater than -8 is the correct answer

P=-8 is the right answer..

-8is correct answer......

a+B=-b/a , so p= -8/-1=-8 ,this is the right answer please like

-8 is the correct answers....

38.

Find the value of p, so that the quadratic equationpx(x-10)+ 75-0, have two equal roots.

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39.

Find the value of p so that the quadratic equation px(r 3)+9 0 has twoequal roots.

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px(x-3) = 9 px*x - 3px - 9 = 0 comparing it with ax*x + bx + c = 0 Two roots equal means b*b = 4ac in pur case 3p*3p = 4*p*(-9) 9p*p = -36p p*p + 4p = 0 p(p+4) = 0 p=0 , -4

If you find this answer helpful then like it.

40.

Due to heavy floods in a state, thousands were rendered homeless. 50 schoolscollectively offered to the state government to provide placefor 1500 tents to be fixed by the government and decided to share the wholeexpenditure equally. The lower part of each tent is cylindrical of base radius2.8 m and height 3.5 m, with conical upper part of same base radius but ofheight 2.1 m. If the canvas used to make the tents costs ? 120 per sq.m, findthe amount shared by each school to set up the tents. What value is generatedand the eanvasby the above problem ? (Use-

Answer»
41.

ST ¥ Gy 2 8 T09500 + 0g WIS + T§00 = — —— oo 1o€ 0% 500 + 09 WIS e

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sin60=√3/2 cos30=√3/2sin30=1/2 cos60=1/2hence√3/2+√3/2/1+1/2+1/2=√3/1+1=√3/2=cos30

42.

monde smo oneisshe goсол

Answer»

sum of angle of quadrilateral = 360°50°+120°+110°+x=360°280°+x=360°x=80°

given :three angles are. 120;130 and 50. to find: angle x. so,total angles in afoor

43.

Find the value of p, for which one root of the quadratic equationpx"-14x + 8 = 0 is 6 times the other.

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44.

2uldty.9. Find the value of p, for which one root of the quadratic equation px-14 + 8 0 is 6times theother

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45.

8. Give multiples of:(a) 15 between 50 and 100

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60,75,90. multiple of15 b/w 50&100

60,75,90 multiple of 15 b/2 50&100

60,75,90 .multiple of 15b/w50&100

60,75,90are the multiples of 15 between 50 and 100

60,75,90 is the multiple of 15between 50and 100

Multiples of 15- 15, 30, 45, 60, 75, 90, 105 etc....multiples between 50 and 100 are:- 60, 75, and 90

46.

(b) Perimeter = 300 cm, breadth= 50 cm

Answer»

Given perimeter= 300cmbreadth = 50 cm length=? let x be the lengthFormula: perimeter= 2(l+b)300=2(50+x)150=50+xx=150-50x=100Therefore length= 100 cm

47.

The entire graph ot the expl(A) k < 7(B)-5 < k < 7If a, b e R, a : O and the quadratic equation ax2-bx + 1-0 has imaginary roots then a + b(A) positiveD-5.(B) negative(C) zero(D) depends on the sign o(15JM110401)of y2+ ax + b = 0, then the least value of x2+ax + b is

Answer»

please post the complete question..last term is not visible here.

Ok

so option (b) is correct.

sorry option (a) is correct

Thank u

48.

The quadratic equationp x^{2}+q x+r=0 has imaginary roots. if(A) q2 = 4pr(C) q = 4pr(B) $ q^{2}>4 p r $$ (D) q^{2}<4 p r $

Answer»

For Imaginary roots, q² - 4pr <0q² < 4prD) is correct

49.

()Tf wis imaginary cube-roots of unity then find the value of w+w+w

Answer»

0 is the correct answer of the given question

50.

15. If ω is an imaginary cube roots of unity, then(1 + ω-02)7 equals128 h -/28128128024

Answer»

The answer is -128 w^2

tq so much...