This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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Name.Q1. Find the Common factors.120 a b, 10 a^{2} b^{2}, 15 a b^{2} |
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Answer» 20ab = 2*2*5*a*b 10a²b² = 2*5*a*a*b*b 15ab² = 3*5*a*b*b common factors = 5ab Thanks |
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| 2. |
Q1. Write down all the integers between -5 and 6.2-- |
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| 3. |
Find the value of(i) log 1/28(11) logs0.008 |
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Answer» log₁ₗ₂8=-3log₅ 0.008=-3 |
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| 4. |
prove that= cotais sin2x- cos2x- tan2xil- cosaxIt LO S 22 |
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| 5. |
10. If the ratio of the zeroes of the expressionx2 + px + 9 is equal to the ratio of the zeroes ofx? + Ix + m, then1) pm=q12) pm2 = q-13)p'l = q m4) p?m=129 |
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| 6. |
itiL s 528 || ProveHak Lo |
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Answer» 2.7^n+ 3.5^n-5 is divisible by 24---- to prove put n=1 14+15-4=24 p(1) true. put n=k 2.7^k+ 3.5^k-5=24m-------1) to prove: n=k+1 is true put n= k+1 2.7.7^k+3.5.5^k-5 from 1) -5=24m-2.7^k-3.5^k 14.7^k+15.5^k+24m-2.7^k-3.5^k 24m+7^k(14-2)+5^k(15-03) 24m+12.7^k+12.5^k 24(m+7^k/2+5^k/2) 24 multiplied by any digit means it is divisible by 24. by p.m.i. it is proved that n is true for N Was this answer helpful |
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| 7. |
A Sum3000 is be given inAYTst och |
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Answer» i want were the boxes are their |
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| 8. |
The polynomials x^3+2x^2-5ax-8 and x^3-ax^2-12x-6 when divided by x-2 and x-3 respectively. Leave the remainder p and q. If q-p=10 find a |
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| 9. |
to leave2. What must be taken from 3to |
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Answer» 7/6 is the answer of this question 7/6is the answer of this question |
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| 10. |
12.If the expression px +3x-3and 2x -5x + p when divided by x - 4leave the same remainder, then the valueof p is(a) 0(c) 2(d) 3 |
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Answer» Given polynomials arepx³+3x²-3and2x³-5x+p It is also given that these two polynomials leave the same remainder when divided byx-4 p(4)³+3(4)²-3 = 2(4)³-5(4)+p 64p+48-3 = 128-20+p 64p-p = 108-45 63p = 63 p = 1 Like my answer if you find it useful! |
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| 11. |
Java program on palindrome of a number |
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Answer» class PalindromeExample{ public static void main(String args[]){ int r,sum=0,temp; int n=454;//It is the number variable to be checked for palindrome temp=n; while(n>0){ r=n%10; //getting remainder sum=(sum*10)+r; n=n/10; } if(temp==sum) System.out.println("palindrome number "); else System.out.println("not palindrome"); } } output |
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| 12. |
LIT (V |
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Answer» 1/(49)-½= (49)½= √49= 7 |
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| 13. |
Harba has some blankets. with him. The cost (in rupees) of a blanket is twice the number of blankets. If he has blankets worth 4608. how many blankets does he have?(1) 52 #2) 48 (3) 58 (4) 96 |
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Answer» Given cost of blanket is twice the number of blanketslet cost of blanket is x and number of blankets is 2xSo given total cost of blanket is ₹4608so Equation will be4608 = 2x × xx² = 2304x = √2304x = 48option (2) is correct 2304 root is 48 sorry for inconvenience check this one,Given cost of blanket is twice the number of blanketslet cost of blanket is x and number of blankets is 2xSo given total cost of blanket is ₹4608so Equation will be4608 = 2x × xx² = 2304x = √2304x = 48option (2) is correct |
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| 14. |
Evaluate(o -(27) Leave your amsve s taction(27)3 Leave your answer as a fraction. |
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Answer» is Ka answers aapko Nahi pata h |
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| 15. |
[P.0.1993)48. 4+3+2= ?20.094 = 44.864(2) 32.755(4) 12.109787 [Bank P.O. 2009)57.78 + ? = 453.072(2) 5(3) 10(4) 46(5)*7$ 7W [P.O. 1991, CBI 2006](2) 235.293(4) 75.148787 [P.O. 1991, CET 2008]-82 = 43.41(2) 11.09(4) 107.91[P.O. 1991, RRB 2005].36 + 450.478(3) 1 2 3 (4)(5)50. 12+13 - = ?[P.O. 1989, SBI 2008)2) 23.032 |
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Answer» questions 50. of the answers 35/20 Amen earns 250 per day working 7 Hata De find his earning after he has worked for 5 days working in in 5 hours |
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| 16. |
39.Two cards are drawn from a pack of 52 cards in succession. Find theprobability that both are kings when,() The first drawn card is replaced(ii) The card is not replaced. |
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Answer» There are 4 Kings in a deck.(i) So the probability of drawing a king is 4/52if the card is replaced, then again the probability would be 4/52.so joint probability would be= (4/52)x(4/52)=1/169(ans)(ii) the probability of drawing a king out of 52 cards is 4/52.the probability of drawing a king out of 51 cards is (3/51)so joint probability is (4/52)x(3/51)=1/221(ans) |
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| 17. |
How is oxygen replaced ? |
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| 18. |
29. (i) A hemisphere of maximum possible diameter is placed over acuboidal block of side 7 cm. Find the surface area of the solid soformed.(CBSE 2017] |
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Answer» Surface area of solid= Surface area of Cuboid having side 7 cm + Surface area of Hemisphere having maximum diameter = 6×(Side)² + 3 πR² where R is radius of sphere. = 6×7² + 3×22/7×(7/2)² = 6×49+ 3×22/7×49/4 =294 +115.50 = 409.50 cm² If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid. |
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| 19. |
A train starts from rest and moves with a constantceleration of 20 m/s for half a minute. The brakesapplied and the train comes to rest in onete. Find the total distance moved by the train,aximum speed attained by the train and (c) theO acminub) theposition(s) of the train at half theelet travelling with a velocity of e |
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| 20. |
3) Ifx-3 is a root of equation kr-10x+302,then k-(a) -3 (b) 3 (c) 9 (d)4) Adie is rolled then ti |
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| 21. |
A transmitting antenna at the top of a tower has32 m and the height of the receiving antenna is 50 m. What ismaximum distance between them for satisfactory communicationLOS mode? Given radius of earth 6.4 x 10^6 m |
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| 22. |
12. The ratio of distance moved by the effort to the distance by the load is calleda. Efficiencyb. Velocity ratioc. Mechanical advantaged. All of these |
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Answer» Velocity ratio= distance moved by effort _____________________ distance by loadAns:b |
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| 23. |
42. The polynomials p(x)x3x+5 and q(x)+ k when divided by x-2 leavehe polynomials px)-2+o-3x+5 and g(x)k when divided by x -2 leavethe remainder ri and r2 respectively. Find the value of k, if ri -12-0(a) k=-1(b)ăŤ-2(c) k=-53(d) k=- |
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| 24. |
17. A muset 25% of his money to his mother, 55% to his daughter and the remainingマ9000 to his broHow much money did he leave? Find the shares of his mother and dauthter |
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| 25. |
9.There were 4312 bags of cement in a godown. If 3425 bags weresold out, how many bags were left in the godown? |
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Answer» 887 bags were left in the godown 887 is the answer of the following 887 is right ans . |
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| 26. |
Rearrange my digit to write the smallest number of 5 digit |
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Answer» 11111 is correct answer 10000 is correct answer 12345 is the correct answer |
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| 27. |
5. The following table shows the weight of 12 players:nuia,Calculateits mode.Weight (in kg)Number of players48505254584322Find the median and mean weights.Using empirical formula, calculate its mode. |
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| 28. |
525458Weight (in kg)Number of players48502243Find the median and mean weights.Using empirical formula, calculate its mode. |
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| 29. |
гкpost mod went do dvad R-ans lepuo aves - amaga ) Rt omgee or |
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| 30. |
Find Mod of -4 |
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Answer» mod of -4 is 4 like my answer |
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| 31. |
me ingangus 28is6Mussthenitsmod foamITeachers Signature |
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Answer» Let terms of AP are a, a + d, a + 2d, a + 3d, a + 4d Then,a*(a + 4d) = 28.... (1) As per given condition(a + 2d) - a = 62d = 6d = 3 Put value of d in eq(1)a(a + 4*3) = 28a^2 + 12a - 28 = 0a^2 + 14a - 2a - 28 = 0a(a + 14) - 2(a - 14) = 0(a - 2)(a + 14) = 0a = 2, - 14 Thus, For a = 2, d = 3AP is 2, 5, 8, 11, 14 For a = - 14, d = 3AP is - 14, - 11, - 8, - 5, - 2 |
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| 32. |
The scale on a map is 1mm :4 m Find the distance on the map for an actualdistance of 84m |
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Answer» On map 4m is equal to 1mm scaleActual distance 1m = 1/4mm scale Distance on map for 84 m actual distance= 84/4 mm= 21 mm scale |
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| 33. |
Find the value of k, for which one root of the quadratic equation kr. 14x+8-02- |
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| 34. |
LosXFind X. |
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Answer» Sum of all the angles of triangle is 180° So, 105°+57°+x = 180° 162°+x = 180° x = 180° - 162° x = 18° |
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| 35. |
47ioshow that los, bd-30 |
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Answer» tnx 👍 |
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| 36. |
A farmer obtained a yielding of 1720 bags of cotton last year. This year she expects hercrop to be 20% more. How many bags of cotton does she expect this year? |
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Answer» Last year number of bags 1720Increase in % = 20%so, 1720 of 20% = 1720×20/100 = 172×2 = 344Total bags = 1720+344 = 2064 |
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| 37. |
3. For what value of P, the quadratic equationPx+ 8x - 2 = 0 has real roots. |
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Answer» p Greater than -8 is the correct answer P=-8 is the right answer.. -8is correct answer...... a+B=-b/a , so p= -8/-1=-8 ,this is the right answer please like -8 is the correct answers.... |
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| 38. |
Find the value of p, so that the quadratic equationpx(x-10)+ 75-0, have two equal roots. |
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| 39. |
Find the value of p so that the quadratic equation px(r 3)+9 0 has twoequal roots. |
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Answer» px(x-3) = 9 px*x - 3px - 9 = 0 comparing it with ax*x + bx + c = 0 Two roots equal means b*b = 4ac in pur case 3p*3p = 4*p*(-9) 9p*p = -36p p*p + 4p = 0 p(p+4) = 0 p=0 , -4 If you find this answer helpful then like it. |
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| 40. |
Due to heavy floods in a state, thousands were rendered homeless. 50 schoolscollectively offered to the state government to provide placefor 1500 tents to be fixed by the government and decided to share the wholeexpenditure equally. The lower part of each tent is cylindrical of base radius2.8 m and height 3.5 m, with conical upper part of same base radius but ofheight 2.1 m. If the canvas used to make the tents costs ? 120 per sq.m, findthe amount shared by each school to set up the tents. What value is generatedand the eanvasby the above problem ? (Use- |
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| 41. |
ST ¥ Gy 2 8 T09500 + 0g WIS + T§00 = — —— oo 1o€ 0% 500 + 09 WIS e |
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Answer» sin60=√3/2 cos30=√3/2sin30=1/2 cos60=1/2hence√3/2+√3/2/1+1/2+1/2=√3/1+1=√3/2=cos30 |
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| 42. |
monde smo oneisshe goсол |
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Answer» sum of angle of quadrilateral = 360°50°+120°+110°+x=360°280°+x=360°x=80° given :three angles are. 120;130 and 50. to find: angle x. so,total angles in afoor |
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| 43. |
Find the value of p, for which one root of the quadratic equationpx"-14x + 8 = 0 is 6 times the other. |
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| 44. |
2uldty.9. Find the value of p, for which one root of the quadratic equation px-14 + 8 0 is 6times theother |
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| 45. |
8. Give multiples of:(a) 15 between 50 and 100 |
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Answer» 60,75,90. multiple of15 b/w 50&100 60,75,90 multiple of 15 b/2 50&100 60,75,90 .multiple of 15b/w50&100 60,75,90are the multiples of 15 between 50 and 100 60,75,90 is the multiple of 15between 50and 100 Multiples of 15- 15, 30, 45, 60, 75, 90, 105 etc....multiples between 50 and 100 are:- 60, 75, and 90 |
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| 46. |
(b) Perimeter = 300 cm, breadth= 50 cm |
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Answer» Given perimeter= 300cmbreadth = 50 cm length=? let x be the lengthFormula: perimeter= 2(l+b)300=2(50+x)150=50+xx=150-50x=100Therefore length= 100 cm |
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| 47. |
The entire graph ot the expl(A) k < 7(B)-5 < k < 7If a, b e R, a : O and the quadratic equation ax2-bx + 1-0 has imaginary roots then a + b(A) positiveD-5.(B) negative(C) zero(D) depends on the sign o(15JM110401)of y2+ ax + b = 0, then the least value of x2+ax + b is |
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Answer» please post the complete question..last term is not visible here. Ok so option (b) is correct. sorry option (a) is correct Thank u |
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| 48. |
The quadratic equationp x^{2}+q x+r=0 has imaginary roots. if(A) q2 = 4pr(C) q = 4pr(B) $ q^{2}>4 p r $$ (D) q^{2}<4 p r $ |
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Answer» For Imaginary roots, q² - 4pr <0q² < 4prD) is correct |
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| 49. |
()Tf wis imaginary cube-roots of unity then find the value of w+w+w |
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Answer» 0 is the correct answer of the given question |
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| 50. |
15. If ω is an imaginary cube roots of unity, then(1 + ω-02)7 equals128 h -/28128128024 |
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Answer» The answer is -128 w^2 tq so much... |
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