1.

Find the value of p so that the quadratic equation px(r 3)+9 0 has twoequal roots.

Answer»

px(x-3) = 9 px*x - 3px - 9 = 0 comparing it with ax*x + bx + c = 0 Two roots equal means b*b = 4ac in pur case 3p*3p = 4*p*(-9) 9p*p = -36p p*p + 4p = 0 p(p+4) = 0 p=0 , -4

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