29. (i) A hemisphere of maximum possible diameter is placed over acubo

1.	29. (i) A hemisphere of maximum possible diameter is placed over acuboidal block of side 7 cm. Find the surface area of the solid soformed.(CBSE 2017]
Answer» Surface area of solid= Surface area of Cuboid having side 7 cm + Surface area of Hemisphere having maximum diameter = 6×(Side)² + 3 πR² where R is radius of sphere. = 6×7² + 3×22/7×(7/2)² = 6×49+ 3×22/7×49/4 =294 +115.50 = 409.50 cm² If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid.

29. (i) A hemisphere of maximum possible diameter is placed over acuboidal block of side 7 cm. Find the surface area of the solid soformed.(CBSE 2017]

Answer»

Surface area of solid= Surface area of Cuboid having side 7 cm + Surface area of Hemisphere having maximum diameter

= 6×(Side)² + 3 πR² where R is radius of sphere.

= 6×7² + 3×22/7×(7/2)²

= 6×49+ 3×22/7×49/4

=294 +115.50

= 409.50 cm²

If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid.