me ingangus 28is6Mussthenitsmod foamITeachers Signature

1.	me ingangus 28is6Mussthenitsmod foamITeachers Signature
Answer» Let terms of AP are a, a + d, a + 2d, a + 3d, a + 4d Then,a(a + 4d) = 28.... (1) As per given condition(a + 2d) - a = 62d = 6d = 3 Put value of d in eq(1)a(a + 43) = 28a^2 + 12a - 28 = 0a^2 + 14a - 2a - 28 = 0a(a + 14) - 2(a - 14) = 0(a - 2)(a + 14) = 0a = 2, - 14 Thus, For a = 2, d = 3AP is 2, 5, 8, 11, 14 For a = - 14, d = 3AP is - 14, - 11, - 8, - 5, - 2

Answer»

Let terms of AP are a, a + d, a + 2d, a + 3d, a + 4d

Then,a*(a + 4d) = 28.... (1)

As per given condition(a + 2d) - a = 62d = 6d = 3

Put value of d in eq(1)a(a + 4*3) = 28a^2 + 12a - 28 = 0a^2 + 14a - 2a - 28 = 0a(a + 14) - 2(a - 14) = 0(a - 2)(a + 14) = 0a = 2, - 14

Thus, For a = 2, d = 3AP is 2, 5, 8, 11, 14

For a = - 14, d = 3AP is - 14, - 11, - 8, - 5, - 2

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