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165=11×151001=11×912552=11×232∴Option 1) is correct as only 3773 is divisible by 11 , same as others.

Hopey answer has helped you

To divide a line segmentABin the ratio,m:n,a rayAXmaking an acute ∠BAX,is drawn and thenm + npoints are marked at equal distances on the rayAX.

Here,m =5,n =7

Therefore, minimum number of points to be marked onAX=m+n= 5 + 7 = l2.

thankyou soo much

but diagonals of a rhombus are equal

on rhombus all sides are equal

750grams=750/1000=0.75kg

5x + 9=5+3x5x-3x=5-95x-3x=-42x=-4X=-4/2X=-2

x+1/x =3(x²+1)/x=3sox/(x²+1)=1/3

You have to only add them, it's simple addition which you can do easily 2020 + 2020 = 4040

the answer of your question is 4040

Answer is 2020+2020 =4040

thank you very much

as angle 136and 44 are corresponding angles they should be equal if l is parallel to m but the angles are not equal so line l is not parallel to m

2 tan^-1x=tan^-1*2x/1-x^2

2tan^-1(cos x) =tan^-1*2(cos x)/(1-cos^2x)

=tan^-1(2 cosx/sinx)

=tan^1(2*cosec x)

tan^-1(2 cos x/sin^2 x)=2 cosec x

cos x/sin^2x=cosec x=1/sin x

cos x=sin^x/sin x

cos x=sinx

1=sin x/cos x

tan x=1

tan x=tan π/4

therefore

x=π/4

right answer bhai........

(D) 2 : 3

The ratio of the width of the flag to its length is 2 : 3.

Let the original price be Rs x∴x(1-(15/100))=360=>x×(85/100)=360=>x=360×(100/85)=423.53

∴Original pricw=Rs 423.53

it is 69 not 169

the answer is A 10280

The base A0 size of paper is defined as having an area of 1m2and a dimension ratio of 1 to√2.Option C

So ,Reduce in price = 5488-4802= 686And,Percentage reduce in price = 686/5488×100%= 1/8×100%= 1/2×25%= 12.5%

12.5% is the right answer of the following

yes here yet it will be this we take it to her teeth to if the red we the following to the to we the

let a be any positive integerby EDLa = bq +r0 ≤ r < bpossible remainders are 0, 1, 2 , 3this shows that a can be in the form of 4q, 4q+1, 4q+2, 4q+3 q is quotientas a is odd a can't be the form of 4q or 4q+2 as they are evenso a ill be in the form of 4q + 1 or 4q+3hence proved

(11x + 2)/3x = 4

11x + 2 = 12x

12x - 11x = 2

x = 2

Therefore, value of x = 2

∠ABC + ∠ABG = 180° ( linear pair)∠ABG = 180° - 150° = 30°

Now, in ∆ ABG ∠A + ∠ABG + ∠AGB = 180°∠AGB = 180° - 60° = 120°

As given, BC || DE , and BC is part of CH therefore CH||ED, where AD is transversal.

So, ∠AGB = ∠GDE ( Alternate angle)

x = 120°

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Thanx Keshika Halder😀😀😀

Suppose x notes are of 10 Rs. and y notes are of 20 Rs. x + y = 70 10x + 20y = 900 x + 2y = 90 x + 2y - x - y = 90 - 70 y = 20 x = 50 50 notes are of 10 Rs. and 20 notes are of 20 Rs.

{(3/7)^-2 * (7/36)^-1}^-1

= {(7/3)^2 * (36/7)}^-1

= {49/9 * 36/7}^-1

= (7*4)^-1

= 1/28