11. In the given figure, find the value of x, if BC 11 DE and LABC = 1

1.	11. In the given figure, find the value of x, if BC 11 DE and LABC = 150Â° and <BAD = 30Â°.150
Answer» ∠ABC + ∠ABG = 180° ( linear pair)∠ABG = 180° - 150° = 30° Now, in ∆ ABG ∠A + ∠ABG + ∠AGB = 180°∠AGB = 180° - 60° = 120° As given, BC \|\| DE , and BC is part of CH therefore CH\|\|ED, where AD is transversal. So, ∠AGB = ∠GDE ( Alternate angle) x = 120° Please hit like if you find my solution useful Thanx Keshika Halder😀😀😀

11. In the given figure, find the value of x, if BC 11 DE and LABC = 150Â° and <BAD = 30Â°.150

Answer»

∠ABC + ∠ABG = 180° ( linear pair)∠ABG = 180° - 150° = 30°

Now, in ∆ ABG ∠A + ∠ABG + ∠AGB = 180°∠AGB = 180° - 60° = 120°

As given, BC || DE , and BC is part of CH therefore CH||ED, where AD is transversal.

So, ∠AGB = ∠GDE ( Alternate angle)

x = 120°

Please hit like if you find my solution useful

Thanx Keshika Halder😀😀😀