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angle 1 = 155° - (x + 15°)

(By exterior angle theorem)

angle 1 = 155° - x - 15° = 140° - x

As L is staright line so,

angle 1 + x + x = 180°

140 - x + x + x = 140°

x = 40°

(2) option is correct

option b is the correct answer of the given

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Option B ie crrct answer

The given figure is a trapezium are the points B and Q mid points of their respective sides.

We know that sum of parallel sides is equal to twice of the line joining the mid points of non parallel sides.

You can use the mid point theorem and its conversefor solving the question.

In triangle ACP,X is mid point of PC [converse of mid point theorem]

Also BX =1/2 AP [mid point theorem].(1)

​Similarly by using both theorems in triangle CRP,We can prove

XQ=1/2 CR .(2)(1)+(2)= BX +XQ= 1/2(AP+CR)​This implies AP+CR=2 BQ

80=2a (alternate interior angles )2a=80a=80/2a=40°angle which is adjacent to 80 =110 (angle of straight line is 180)angle b=110°(alternative interior angle)

crop the question properly otherwise how can we answer it

As both sides are equal so angle must be equal x + x + 80° = 180°2x = 180° - 802x = 100°x = 50°

thanks you daily answer me please please

Use exterior angle theoremA) a = 80° + 60° = 140°

B) a = 70° - 35° = 35°

C)a = 145° + 25° = 170°

Let the other number be X. Then, (-4/3)X = (-9/16)=> X = (9*3)/(16*4)=> X = 27/64.

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Radius of curved path is r. width of path is b m. the outer edge is raised by h w.r.t inner edge so that a car with speed v can pass safe over it. the value of h is

tanθ = v²/rg=h/bh

=v ²b/rg substituting the values according to given question,

v=48km/h =(48x 1000)/60x60m/s⇒40/3 m/s

b=1m

r=400mg=9.8m/s2h=(40/3)²x1/400x9.8

⇒0.0454 m

∴⇒4.54cm

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y + 25° = 75° ( Alternate angle)y = 75° -25°y = 50°x + 25° = 180°x = 180° - 25°x = 155°

great sir

since PR is the bisector of angle APQ , so angle APQ = 2× RPQ = 2*38 = 76°

now angle PQD + 104° = 180°.. ( linear pair)

so angle PQD = 180° -104° = 76°

and since angle PQD = APQ , so, we can say that they form an alternate interior angle pair..Hence AB || CD

average =4.2+3.8+7.6/3=5.2

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Wire 1 = 44 cm diameter

Therefore radius = d/2 =44/2 = 22cm

Area = π r^2 = 1,521.147 cm^2

Wire 2 = 44 cm Length

Therefore Area of sq. = L times L = 44 times 44 = 1,936 sq. cm

Difference = 414.85sq. cm

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the limt is from 0 to π not o to π÷2

Here CD is the tower and AB is the pole.

In △CDB, CD/BC = tan 60°

=> 50m/BC = √3

=> BC = 50/√3m

AE = BC

AE = 50/√3m

In △ADE, DE/AE = tan 30°

=> DE/50/√3m = 1/√3

=> DE = 50/3m

so the height of the pole is 50/3m

-36; is the correct answer of the given question

-36 is a right answer

-36 is the correct answer

-36 is the correct answer

-,36,is the right answer

-36is correctanswer

this is correct option

x²-5x+k=0...(i)one of the zero is -4so let x=-4putting in (i) we get(-4)²-5(-4)+k=016+20+k=036+k=0thereforek=-36so option (b) is the correct answer

360/60 = 6