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37. A train has to negotiate a curve of radius 400 m. By how much should theouter rail be raised with respect to the inner rail for a speed of 48 kmh-1? Thedistance between the rails is 1 m.(Ans: 0.0454 m) |
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Answer» Radius of curved path is r. width of path is b m. the outer edge is raised by h w.r.t inner edge so that a car with speed v can pass safe over it. the value of h is tanθ = v²/rg=h/bh =v ²b/rg substituting the values according to given question, v=48km/h =(48x 1000)/60x60m/s⇒40/3 m/s b=1m r=400mg=9.8m/s2h=(40/3)²x1/400x9.8 ⇒0.0454 m ∴⇒4.54cm Like if you find it useful! |
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