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Let no. Of 20 notes be n and no. Of 5 notes be mThen 20n + 5m = 380.....(1)If no. Of notes interchangedThen 5n + 20m = 320.....(2)

On solving given equations20m - 5/4m = 320-9575m = 225x4m = 3x4 = 12

Putting value of m in equation (1)20n + 60 = 38020n = 320n = 16

Number of 20 notes = 16Number of 5 notes = 12

thanks

i) ((1 + i) / √2)²= (1 + i)²/ 2= (1 + 2i + i2) / 2= (1 + 2i - 1) / 2= 2i / 2= i.

so√i = (1 + i) / √2

ii) suppose z2= -i

z is complex and therefore can be represented by x + iy

(x+iy)2= -i

x2- y2+2xyi = -i

xy = -1/2

x2- y2= 0

x = +/-y

Therefore (x,y) = (1/√2,-1/√2),(-1/√2,1/√2)

And z = (1/√2)*(1-i) or (1/√2)*(-1+i)

iii) for this add i+ii √i +√-i = √2

photo is not clear poet it again please

mode = 3 Median - 2 mean

=> 42 = 3×M - 2×49=> 3M = 42+ 98=> M = 140/3 = 46.77 = 47

Thanks bro very much

Let the ratio factor be X.

number of 100 Rs notes = 2Xnumber of 50 Rs notes = 3Xnumber of 10 Rs notes = 5X

A/Q,

2X x 100 + 3X x 50 + 5X x 10 = 400000

200X + 150X + 50X = 400000400 X = 400000 X = 400000/400 X = 1000i.e,number of 100 Rs notes = 2X = 2 x 1000 = 2000 notesnumber of 50 Rs notes = 3X = 3 x 1000 = 3000 notes.number of 10 Rs notes = 5X = 5 x 1000 = 5000 notes (ANS)

28 Feb it's called financial budget

tan 15 + cot 15 = sin 15 / cos 15 + cos 15 / sin 15 = (sin²15 + cos²15) / (sin 15 cos 15) = 1 / (1/2 sin 30) = 2 / sin 30 = 2 / (1/2) = 4

In triangle CBDApplying Pythagoras theorem: 15² = 6²+ BD²225-36 = BD14 = BDAD = 28

Yes,it is a right answer.

cot A = 8/15 = B/P

Using pythagoras theoram H^2 = P^2 + B^2 H^2 = 15*15 + 64H^2 = 225 + 64H^2 = 289H = 17

sin A = P/H = 15/17

sec A = H/B = 17/8

The only problem you have here is fractional ratios!

solution:-Let 1x,3x,5x1x+3x+5x=1809x=180x=180/9x=20:1x=1×20=20:3x=3×20=60:5x=5×20=100This is the correct answer hai

let 1x, 3x , 5x x+3x+5x=180; 9x=180; x=180/9=20; 1x=1×20=20; 3x20=60; 5x20=100

Let the angles be x,3x,5x

We know that,Sum of all angles of triangle = 180x+3x+5x= 1809x = 180x = 203x = 3×20=605x = 5×20 = 100

let ratio be x1x+2x+3x=1806x=180x=30

nth term of g.p J's 5.0.6n1then commom ratjo js

i) 2*0-3*(-2)+0=6

ii)2*(0)-(-1)^2(-2)+0+0=-2

iii) 0+0-4=0-2=-2

iv) 1-4=0=-3

∠DAC = 72°

∠BAC = 3/4(72°) = 54°

∠DAB = ∠ADB = 18°

⇒ x° + ∠BAC = ∠DBA

= 180° - 36° = 144°

⇒ x = 90°

We know √3 is an irrational number

Let2 + √3 be a rational number ,

2 + √3 = r , where r is any rational

√3 = r - 2This is an absurd result because LHS is irrational and RHS is rational so this is a contradiction to our assumption, hence 2 + √3 is an irrational number

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put x =✓2 in the given equationKx²+✓2x-4 = 0so K (✓2)² + ✓2 × ✓2 -4 = 0 2K -2 =0 K = 1

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