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15ⁿ = (3×5)ⁿ = 3ⁿ × 5ⁿ

We know that a number will end with zero if and only if it has 5 and 2 has prime factors i.e 2 × 5 = 10 , which will eventually makes a number to end with 0.

In 15ⁿ , factor 2 is not present therefore 15ⁿ can not end with 0

if you have any confusions comments meand please like it

Any 2 rational numbers between -2and 5 are1 and 2

Two rational numbers between -2 and 5 are 0 and 1

480 * 75/100 + 540*x/100 = 603 540 x = 60300- 36000x = 24300/ 540 =/45

45 is the right answer of following questions

[(1/2)^2 - (1/4)^3] *2^3= (1/4 - 1/64)*8= (16 - 1)/8= 15/8

-5/6=-5×3/6×3=-15/18-15/18

-5/6=-5×3/6×3=-15/18

-5/6= - 5x3/6x3= - 15/18

please answer my English question

tnqu

i) x ={ A,E,G,I,M,R}

ii) x ={0,1,2,3,4}

ii) x = { set of all even numbers =>>2,4,6,8.... }

i)The elements of the set are the letters in 'MARRIAGE'. While writing a set we choose only distinct letters. Therefore, set = {M,A,R,I,G,E}

ii) x lies between -0.5 and 4.5 and is an integer. Therefore, set ={0,1,2,3,4}

iii)x is a multiple of 2. Therefore, set ={2,4,6,8,.......}

In Roaster form

i) { M,A,R,I,G,E}

ii) {0, 1, 2, 3, 4 }

iii) { 2, 4, 6, ....}

write the rational number

write number Indian system 20480 next 1980000

there are many rational no. between 3 and 5 like 4 or 7/2 or 9 /2

rational number in between 3and 5are3=3/1=3×10 1×10=30/105=5/1=5×10 1/10=50/10number between 3and5are31/10,32/10,3310,34/10to49/10

there are many rational numbers between _ 3and 5we have to find 1 rational number ,so we can write 1+2 as denominator =_ 3 = 9/_3 , 5= 15/39/3 and 15/3rational numbers between _3 and 5 are=10/3,11/3,12/3,13/3,14/3

3×6/6 is equal to 18/65×6/6 is equal to 30/6Answer 19/6,20/6,21/6,22/6,23/6

19/6,20/6,21/6,22/6,23/6 is the correct answer

31.004 - 17.2386= 31.0040 - 17.2386------------------ 13.7654

Positive IntegersDefinition. Theset of positive integersis the same as thesetof natural numbers. Thepositive integersare the numbers 1, 2, 3, 4, ... , sometimes called the natural numbers or counting numbers.Positive integersare denoted as Z+.

Let fourth propotional be x

We know,Product of means = Product of extremes

Hence, 21*22 = 14 * xx = 21 * 22/14x = 3*11 = 33

Therefore, Fourth propotion is 33

suppose fourth proportional is x now 1 5/7 = 12/7 2 3/14 = 31/14 3 3/5 = 18/5 so 31/14 * 18/5 = 12/7 * x so x= (31×18×7)/(14×5×12) = (31×6)/(2×5×4) = 93/20

14/21 = 22/x462 = 14xx = 33 .

In ∆ABD and ∆CDB AB = CD (given)∠ABD = ∠CDB (given) BD = BD (common)∴ ∆ABD ≅ ∆CDB (SAS congruence)=> AD = CB (CPCT)

make some big steps to understand

i) x ={ A,E,G,I,M,R}

ii) x ={0,1,2,3,4}

ii) x = { set of all even numbers }

3) ans is wrongAns is C={2,4,6,8,.......}

and what are 2,4,6,8 ..... ?? ain't they even number ??

2,4,6, 8.... are indeed even numbers only as far as i know.

540+(6/7)*540=540+462.86=₹ 1002.86

answer is 630rupees

answer of this question is = 30

let X be the common multiplehence 2x+3x+6x=8811x=88X=8hence shortest is 2x=2*11=22cmlongest is 6x=6*11=66cm

sum of ten numbers=35×10=350sum of nine numbers=300so tenth number=350-300=50

1/2 and 1/3now lcm = 66/12 and 6/18now multiple by50300/60 and 300/90now 10 rational number300/61 ,300/62,300/63,300/64,300/65,300/66,300/67,300/68,300/69,300/70

1/8 + 3/16 + 5/24

Take LCM of 8, 16, 24

= (6 + 9 + 10)/48

= 25/48

The correct answer is 25/48

78%=78/100=78/100=39/50

Least five digit number = 10000L.C.M. of 20,25,30 is 300.But we want the least five digit number which is divisible by 20, 25, 30.So, we will multiply the L.C.M. by a number that makes it the least five digit number divisible by 20, 25, 30.300××31 = 9300300××32 = 9600300××33 = 9900300××34 = 10200So, theleast five digit number divisible by 20, 25, 30 is 10200.

The least five digit number divisible by 20,30,25 is 10200

10000 is the least 5-digit number whch is exactly divisible by 20 ,25 ,30

5 is the answer of the following

5 is the correct answer of the given question

Number of students = 100number of boys = 60Then number of girls = 100 - 60= 40

Given, Mean Height of class = 150 cmMean Height of boys = 70 cm

Sum of height of all students= 150*100= 15000 cm

Sum of height of all boys= 70*60= 4200 cm

Sum of height of girls= 15000 - 4200 = 10800

Mean Height of girls= 10800/40 = 270 cm

mean = all of observation total no. of observation = 18+100+150+60+70 2 =. 199

Here was the gaping of 2 number so obiusly each number are not be used only once

1.81= since 1^2 ends up having 1 as the digit at its unit place so 81^2 has 1 as the unit digit. ans=12. 272=Since, 22= 4, therefore, square of 272 will have 2 at it's unit place.So, 2722will have 4 at unit’s place3. 779^2=Since, 92= 81, So, 7992will have 1 at unit’s place4. 3853^2=Since 32= 9, so, 38532will have 9 at unit’s place.

square a number last digit will be square of last digit of numberi) 1² = 1ii) 2² = 4iii) 9² = 1