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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
10. Which number is nearest to 457 which is divisible by 11? |
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Answer» When 457 divided by 11 we get Qqotient 41 and remainder 6 So nearest number to 457 which is divisible by 11= 457 - 6= 451 |
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| 2. |
(ii) 33789 +50311.By suitable arrangements, find the sum of(i) 311, 528, 2893. |
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Answer» 528+(311+289)528+600=1128 |
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| 3. |
2*(z - 1) %2B z(z - 1) |
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Answer» z (z-1)+2 (z-1)z^2-z+2z-2z^2+z-2 z(z-1)+2(z-1)=>(z+2)(z-1) (z-1)(z+2) . both are factor of given equation |
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| 4. |
528 㥠|
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Answer» Sorry we are currently taking questions in English language only |
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| 5. |
1) Find the intersection of the following sets.A (1, 2, 4,5,7), B (2, 3, 4, 8) |
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Answer» A intersection B = { 2, 4} |
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| 6. |
1024+5245 |
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Answer» The solution would be 6269 |
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| 7. |
square root of 1024 |
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Answer» 32 is the square root of 1024 |
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| 8. |
ng Situaions Ih the form of quadratic equationsG) The area of a rectangular plot is 528 m2. The length of528 m2. The length of the plot (in metres) is onemore than twice its breadth. We need to find the length and breadth of the plot. |
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Answer» Let the breadth =b mlength = l =(2b+1)marea =528m² l*b= 528(2b+1)b-528=0 2b²+b-528=02b²+33b-32b-528=0b(2b+33)- 16(2b+33)=0(2b+33)(b-16)=02b+33=0 or b-16=0 b should not be zerothereforeb-16=0b=16 breadth = 16mlength =l= 2b+1=2*16+1=32+1=33m |
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| 9. |
\sqrt{23+\sqrt{528}}=2 \sqrt{3}+\sqrt{11} |
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| 10. |
64.In what time 3500 will become 4130 whenannual rate of interest is 6%.(1) 4 yr(2) 3yr (3) 6 yr (4) 5yr |
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| 11. |
10. Ifo, β, γ are zeroes of the polynomial f(x)x 3-ax 2 + bx-c then find the value of- a +-+αβ βγ γα |
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Answer» Like if you find it useful |
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| 12. |
Prove :√(23 + √528) = 2√3 + √11 |
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| 13. |
2 x ^ { 2 } + x - 528 = 0 |
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| 14. |
XIfo, increases by y %, what is the final quantity?(A) (1+r 0)-(B) (Ex100)-(C)x+0% ofx) (D)x(100+1 |
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| 15. |
Evaluate the following4571) 1ii) 52811) 1 |
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| 16. |
Sh. 520tendthe valve &followinx 528 Y 25 |
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Answer» I do not see your questions please send another question please like 52,000 is correct answer 52000 is the answer of the following 52800 is the correct answer of the given question 52,000 is the correct answer |
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| 17. |
By suitable arrangements, find the sum of:v311, 528, 289 |
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Answer» 528+(311+289)528+600=1128 |
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| 18. |
14. Polar form of z 1+ |
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Answer» z = 1+ i argument is tan = 1 so = 45thereforez = r( cos+ i sin), where r= |z|so z = sqrt2 ( cos45 + i sin45) |
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| 19. |
12.ड्ि10242= है. |
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Answer» √(36.1/102.4) = √(361/1024) = 19/32 |
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| 20. |
7. A bank offered its depositor an interest rate of6% per annum and loans to borrowers at 18%p.a. If the entire amount of Rs 50000, deposited,is loaned out for 3 years, how much does the bankearn at the end of 3 years? |
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Answer» Depositer gets 6% interest per annumBank gets 18% interest on loan amountBank earn 18-6 = 12% per annum on loan SI = P*R*T/100 = 50000*12*3/100 = 18000 Bank earns Rs 12000 at the end of 3 yrs Type errorBank earns Rs 18000 at the end of 3 yrs |
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| 21. |
50000+50007654 |
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Answer» 50000+50007654=50057654 |
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| 22. |
s.Standard form of 900000000 + 800000 + 50000 + 3000 + 60+ 5 is(1) 900,00,85,363(2) 9,85,03,363(3) 90,08,53,363(4) 90,08,53,065 |
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Answer» 4 th is the wright answer |
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| 23. |
t will be thecompoundinterest on a sum ofWha3yr at the rate of 12% per annum?50000 |
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Answer» Given, P = 50000, R = 12%, n = 3 We know,A = P(1 + R/100)^n = 50000(1 + 12/100)^3 = 50000(1.12*1.12*1.12) = 50000(1.405) = 70250 Compound Interest= 70250 - 50000= Rs 20250 Given, P = 50000 , R = 12% , Time = 3 yrs A=P(1+R/100)^n=50000(1+12/100)^3=50000(112/100)^3=50000(28/25)^3=50000(28/25*28/25*28/25)=16(28*28*28/5)=16(4390.4)=70246.4 CI= A - P=70246.4 -- 50000= 20246.4 |
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| 24. |
4. Find the difference between the compound interest and simple interest on a sum of(50000 at 10% pa. for 2 years. |
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| 25. |
(1024)10decimal to binary |
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| 26. |
write the folloning sets n r=eananda,-4)an+2 an+1 + an, a |
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Answer» I) First term= 4Second term = 4*4= 16Third term = 4*16= 64 Hence A={4,16,64,256,..............} |
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| 27. |
11 Renu sold an article at a loss of 8 percent.Had she bought it at 10% less and sold for36 more: she would have gained 29%.Find the cost price of the article. |
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Answer» Let the c.p. of the article be Rs 100. Renu sold it at loss of 8% i.e; in Rs 92. If she had purchase it at 10 % less than new C.P. is Rs 90. also if gained 20% on it the new S.P. is 90+ 18=108 The differece in s.p. is 108-92=16 the initial C.P. = 100 the difference in S.P. is 36 ( given) the initial C.p. =100*36/16=225 (ans) |
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| 28. |
ITUCLIC2CIUCS.Find c ifo is a 'zero' of p(x) = ax + bx + c.1. |
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Answer» 0 is the correct answer of the given question p(x)=ax^2+bx+c=ax^2+bx+0=0 p(x)= ax^2+bx+Cp(0)= a(0)^2+b(0)+C = CC=0is the answer c=0 is the correct answer c is equal to zero is the answer correct answer is 0 . hope it helps you ax^2+bx+c=0; c=0; ax^2+bx+0= |
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| 29. |
367+ 5 |
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| 30. |
472 %2B 367 %2B 528 |
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Answer» 528+367=897=897+472=1367 528+367= 897897+ 472= 1367 528 + 367 = 895895 + 472 = 1367 (528+367)+472. 895+427Ans=1367 1367 is answer for question 1367 is answer this question 1367 is the right answer 1367 is the best answer 1367 is the right answer 1367 is the right answer 528 + 367 + 472 ka total 1367 528 + 367 + 472 _______ 1367 528+367+472=1367 right answer |
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| 31. |
367 \frac { 2 } { 7 } |
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| 32. |
By selling a wooden table at a loss of 20%, a shopkeeper makes a loss of 90nd its (i) selling price (ii) cost price. |
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Answer» Loss is 20% and i.e Rs.90. To know C.P:(Using percentage) (C.P/100)*20 = 90C.P * 20 = 90 *100C.P * 20 = 9000C.P = 9000/20C.P = 450 Loss: Loss= C.P - S.PS.P = C.P - LossS.P = 450 - 90S.P = 360 |
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| 33. |
Solvewithout multiply367 x 989 |
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| 34. |
What is water resources |
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Answer» Water resources are natural resources of water that are potentially useful. Uses of water include agricultural, industrial, household, recreational and environmental activities. All living things require water to grow and reproduce |
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| 35. |
63. Amod sold a plot ofland to binoy at 15% profit and Binoy sold it to carolin at 15% loss. If the costrice of the land for Amod was Rs 50000, How much did carolin pay to buy the land? If amod wasto sell the land directly to carolin, what would have been his profit or loss percent? |
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| 36. |
3.Which of the following statement is correct?AJ I MB = 1024 bytes[C] I MB = 1000 kilobytes[B] 1KB.= 1024 bytes[DJ 1 KB = 1000 bytes |
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Answer» B is the correct answer.... B correctly the first time Answer is B................ b is the right answer |
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| 37. |
The length of a rectangle is increased by 60 %. By what percent would the width have to be decreased to maintain the same area? |
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| 38. |
14. By selling a table for 3168, Rashid loses 12%. Find its cost price. What percentwould he gain or lose by selling the table for Rs 3870? |
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Answer» Sp = 3168loss= 12%cp × loss= spcp(1-12/100)=3168cp×88/100=3168cp=28800/8cp=72×50cp=3600 now sp=3870profit=3870-3600=270p%=270/3600 ×100p%=30/4p%=15/2p%=7.5% thank you |
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| 39. |
जावुड b 1 bl 2 SR 0=€ X0+ X melph PR3 Tg, |
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Answer» x² + 2x - 3 = 0 x² -x + 3x - 3 = 0 x ( x - 1) + 3 ( x - 1) = 0 ( x - 1) ( x + 3) = 0 And , so x = 1 and -3 |
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| 40. |
o)slove the linear in-equation |
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Answer» Thanks |
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| 41. |
A shopkeeper makes a profit of 151. byselling a book for Rs 230 What is the c?and the profit |
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| 42. |
Factorise the following by any method.\left. \begin{array} { l l } { a ^ { 2 } b ^ { 3 } c ^ { 3 } - a b c ^ { 2 } } & { b ) 49 a ^ { 2 } b ^ { 4 } - 7 a b c } \\ { 16 a ^ { 2 } - 144 b ^ { 2 } } & { \text { d) } 64 a ^ { 2 } - 64 a + 16 } \end{array} \right. |
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Answer» abc^2(ab^2c-1)7ab(7ab^3-c)(4a+12b)(4a-12b)=16(a+3b)(a-3b)16(4a^2-4a+1)=16(2a-1)^2 |
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| 43. |
If there are 1024 relations from a set A = {1, 2, 3, 4,5} to a set B, then the number ofelements in B is(1) 3(2) 2(3) 4(4) 8 |
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| 44. |
by selling a stool for rupees 67.50 a carpenter loses 10% how much percent would he gain or lose by selling it for 82.50 rupees |
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Answer» CP of stool = 67.50×100/100-106750/90=675/9=$75Of he sold it on 82.50 then gain would be82.5-75=$7.5gain % would be = 7.5/75×100=10% |
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| 45. |
1. Find the area of the triangle ABC formed by the points A(-4,-3), B(-1, - 6) and C (4, 5).[P.S.E.B. 2016 Set-B] |
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| 46. |
1.Find the SP., when M. P.= Rs 990 and discount=10% |
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Answer» SP= 990-(990*10/100)990-99891 will be the selling price |
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| 47. |
1. Find the area of the triangle ABC formed by the points A(-4,-3), B(-1, -6) and C (4.5)[P.S.E.B. 2016 Set-B] |
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| 48. |
itstS 3Ceper allows her customer a 10% discount on the marked price of the goods and still gets a profitAlady shopkeeper0125%. What is the cost price of a fanfor her marked price a1250? |
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Answer» yes you are right |
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| 49. |
1 A carpentercharged 2500 for making a bed. The cost of materials used is 1100 and thecharges are 200/hr. For how many hours did the carpenter work. |
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| 50. |
\tan 75^{\circ}+\cot 75^{\circ} |
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