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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
C Exercises1. Show graphically that the system of linear equation:2x - 3y = 5 and 6y - 4x3 |
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| 2. |
Find the joint equation of the lines xty-3-0 and 2xty-1-Findif y cos sin x |
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| 3. |
Q.6. In the given figure, PA and PB are tangents to a circle with centreO. If <APB = (2x + 3)" and <AOB = (3x + 7)。, then find the value of[Ans. 34] |
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| 4. |
1)2XTy| Find the value of k if x-2,y-l is a solution of the equation 2x+3y |
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Answer» how |
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| 5. |
(8) जि (D2 L =0 L34. 100 सन्तरे ₹350 में खरीदे गए तथा X48 uidदर्जन की दर से बेच दिए गए, प्रतिशत लाभ मांहानि है '(4) 15% हानि (0)15% लाभ(2 142% हानि... (20 145% लाभनस शा... |
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| 6. |
(b) Solve the equations graphically 3x + 4y = 10 and 4 - 3y = 5. |
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| 7. |
14. (a) Draw the graph of the polynomial plx) = x - 7x + 12. then find itszeroes from the graph.OR(6) Solve the equations graphically 3x + 4y = 10 and 4x - 3y = 5. |
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| 8. |
Exercise 2.3Raman earns 62740 and Saran earns 71032each in a month. How much do they earn each montlhtogether? |
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Answer» Raman earns= Rs.62740Saran earns= Rs.71032Total Earning= 62740+71032=Rs.133772 62740+________ 71032 _________ 133772:Answer.. _________Thanks.. |
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| 9. |
1L ब्गून शोधो . 6+4 \sqrt{2} |
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Answer» 6+4√26+4*1.41411.656 |
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| 10. |
6. A labourer earns 156 in 3 hours. Howrer earns r156 in 3 hours. How much will he earn in 7 hours? |
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Answer» labour earn in 3 hours = ₹ 156labour earn in 1 hour = ₹156÷3 = ₹51so ,labour earn in 7 hours = 7× ₹51 =₹357 in 3 hours = 156 RS. in 7 hours= ? 3/7 = 156/x 3×x = 156× 7 3×x = 1092 x = 1092/3 x = 364 he will earn 364rs in 7hours. |
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| 11. |
olve 2x1+2x+1denosits Rs 1000 every mo |
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Answer» 2x + 1 + 3/(2x + 1) = 4(4x^2 + 1 + 4x + 3) = 4(2x + 1)4x^2 + 4x + 4 = 4(2x + 1)x^2 + x + 1 = 2x + 1x^2 - x = 0x(x - 1) = 0x = 0, 1 |
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| 12. |
1L 277 & q—p के रूप में बदलें। |
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| 13. |
truct the folloQuadrilateralMO = 6 cmOR 4.5 cmM = 60°O = 1 050< R = 1050 |
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Answer» Kindly post the entire question please. |
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| 14. |
कल 0.8 Tt vDJfi; T D end छि फिकि(0 Mo Grug |
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Answer» 0.9 in p/q form=9/10 |
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| 15. |
Ex. 8. A pipe can fill a cistern in 3 hours. Due to a leak in the bottom it is filled in 4 hours. When thecistern is full, in how much time will it be emptied by the leak? |
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| 16. |
\cos ^{2} 112 \frac{1}{2}-\sin ^{2} 52 \frac{1^{0}}{2} |
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Answer» (cos225/2+ sin 105/2)(cos225/2-sin105/2)(cos112.5+sin52. 5)(cos112.5-sin52.5) |
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| 17. |
the probability of selecting a vowel from the list a,e,i,o,u is 1 |
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Answer» It will be 1/5 not 1 |
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| 18. |
1] वी जले:XXAl1l |
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Answer» If you like the solution, Please give it a 👍 |
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| 19. |
1L tanA + cotA = Vsec?A + cosecâA |
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Answer» We know that:sec²x = 1 + tan²xAndcosec²x = 1 + cot²xAndtan x .cot x = 1 Solution:-Taking LHS..=√(sec²A + cosec²A)=√ { (1 + tan²A) + ( 1 + cot²A) }=√ ( tan²A + cot²A + 2)=√( tan²A + cot²A + 2 tan A .cot A ) Using(a² + b² +2ab) = (a + b)² =√(tan A + cot A)²= tan A + cot A = RHS Like my answer if you find it useful! |
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| 20. |
16. The solution set of the inequationlx-1l+x-2+x-32 6, is |
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Answer» thanks Bhai g |
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| 21. |
GoodLuckDate1l |
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Answer» 2NaOH+H2SO4‐‐> 2H2O + Na2SO4 |
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| 22. |
gkl 1L =3, hionddho valdo uqEL- 1 |
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Answer» (u+1/u)²=u²+1/u²+29-2=u²+1/u²u²+1/u²=7 (u²+1/u²)²=u⁴+1/u⁴+249-2=u⁴+1/u⁴u⁴+1/u⁴=47 |
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| 23. |
3-1io5find tha mo |
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Answer» P |
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| 24. |
11.a) A letter is chosen from English alphabet. Find the probability of the letterchoosen isi) a consonantii) both consonant and voweliii) a letter comes beforeMi v) not a vowel |
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Answer» Total letters = 26 1) Total consonant = 21Probability of choosen letter is consonant = 21/26 2) All alphabets except vowels are consonant.So, probability of choosen both alphabet and consonant is 0. 3) Number of letters before Mare 12Probability of choosen letter before M = 12/26 = 6/13 4) Number of vowel = 5Probability of choosen not a vowel = 1 - 5/26 = 21/26 |
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| 25. |
6. If f| x+-|=x2+ー, x#0 then mention thefunction f(x). |
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| 26. |
to n terms-118. 13 7+15+31a) 2+1c) " -1112d)2 |
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| 27. |
\lim _{x \rightarrow 1} \frac{1-x^{-1 / 3}}{1-x^{-2 / 3}} |
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| 28. |
\lim _{x \rightarrow 1} \frac{x^{4}-1}{x-1} |
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| 29. |
\lim _{x \rightarrow-1} \frac{x^{3}+1}{x+1} |
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Answer» wrong answer is 3 |
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| 30. |
\lim _{x \rightarrow 1} \frac{x^{3}-1}{x-1} |
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Answer» iam not satisfied with |
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| 31. |
BAFindxsuch that [1 2 112 0 11121=0. |
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| 32. |
Fig. 9.46In Fig 9.47, for which value of x is l ll 2?(a) 371112(b) 43(c) 45(d) 4778°35° |
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Answer» b)43as l1||l2 and BC transverse.then( B =78°)=(A=78°-35°)therefore X°=43° |
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| 33. |
8, Mr Tandon borrowed a certain sum from a bank at the rate of 12% per annum. After 2 years, he returned3100 to the bank. Calculate the sum of money he borrowed from the bank. |
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Answer» 3100 = p(1+ 12x2/100)3100 = p(1+.24)3100/1.24 = pp= 2500rs |
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| 34. |
Iff(x)=xe* sin x,then find fl(x)/ |
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| 35. |
कक =0) ~tancot(90° - ) (sin? 350tan10° tan 20° tan 45° an 70° tan §0°R +sin’ 55 |
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Answer» Like if you find it useful |
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| 36. |
\lim _ { z \rightarrow 1 } \frac { z ^ { \frac { 1 } { 3 } } - 1 } { z ^ { \frac { 1 } { 6 } } - 1 } |
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| 37. |
\int_{0}^{\pi / 2} \int_{0}^{a \sin \theta} \int_{0}^{\left(a^{2}-r^{2}\right) / a} r d \theta d r d z |
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Answer» thanks |
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| 38. |
10. A sound source produces 40 compressions and 40 rare factions in 0.4 sec. Find the(100 Hz]frequency of the wave |
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Answer» One compression and and one rarefaction constitutes one cycle. 40 compressions and 40 rarefactions involves 40 cycles. Time taken for one cycle is called time period. So, Time period = 0.4 s / (40) = 0.01 s Frequency = 1 / Time period = 1 / (0.01 s) = 100 Hz Please hit the like button if this helped you. |
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| 39. |
.R T'बिन्दुओं (त ८05 0, 0(A) a(©) asin®gen (0, a sin 0) के बीच की दूरी हैं-®) acos 0 |
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| 40. |
\left. \begin{array} { l } { \text { Vumber of Solution of equation } \operatorname { sin } ^ { 2 } x - 6 \operatorname { sin } x + 8 = 0 \text { in } R \text { is } } \\ { 0 } & { ( c ) 4 } \end{array} \right. |
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Answer» let sinx = t so, the equation is reduced to t²-6t+8 = 0=> t²-4t-2t+8 = 0=> t(t-4)-2(t-4) = 0=> (t-4)(t-2) = 0=> t = 2,4 but since t = sinx and it ranges from [-1,1] so, there is no. solution option a. thank you very much. it's good solution |
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| 41. |
how many arrangements can be made out of the letters of the word BANK. |
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Answer» 4!=4×3×2×1=24 arrangements |
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| 42. |
SP/ x - xe =(x)d (IIA) omontred to serve prior |
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Answer» (1).p(a)=p(-1÷root3)=p(-1÷root3)=3×(-1÷root3)square-1=(3×1÷3)-1=1-1=0zero of the polynomial (2).p(a)=p(2÷root3)p(2÷root3)=3×(2÷root3)square-1=(3×4÷3)-1=4-1=3not |
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| 43. |
lim z^1/3 - 1 / z^1/6-1z-1 |
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| 44. |
Express 429 as a product of its prime factors.0/3112 |
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| 45. |
Arrange the given numbers in columns and adda) 128 and 251 b) 236 and 452 c) 355 and 422e) 229 and 654 ) 457 and 374 g) 552 and 698i) 125, 367 and 356 ) 457, 677 and 822 |
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| 46. |
कद... किए il1, शानित 53 Y23+/528 =2/3+/11 |
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| 47. |
457 - 222 -111 = ?? |
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Answer» 124 is correct answer of this 124 is the right answer 124 is the correct answer to this question =457-222-111=457-(222+111)=457-333=124 |
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| 48. |
Prove that 53 457 is an Greationalnumber? |
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Answer» Let us assume that √3+√7is rational.Thatis,wecanfindcoprimesaandb(b≠0) such that Therefore, |
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| 49. |
Prove that the distance between the points (a+ r cos , b+ r sin 0) and (a, b) isindependent of 0 |
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| 50. |
Solve for z : (a-b+r) = at,[aメ0, bメ0.2メ0, xメー(a + b)](a+b+z) a ba |
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