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1L tanA + cotA = Vsec?A + cosecâA |
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Answer» We know that:sec²x = 1 + tan²xAndcosec²x = 1 + cot²xAndtan x .cot x = 1 Solution:-Taking LHS..=√(sec²A + cosec²A)=√ { (1 + tan²A) + ( 1 + cot²A) }=√ ( tan²A + cot²A + 2)=√( tan²A + cot²A + 2 tan A .cot A ) Using(a² + b² +2ab) = (a + b)² =√(tan A + cot A)²= tan A + cot A = RHS Like my answer if you find it useful! |
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