\left. \begin{array} { l } { \text { Vumber of Solution of equation }

1.	\left. \begin{array} { l } { \text { Vumber of Solution of equation } \operatorname { sin } ^ { 2 } x - 6 \operatorname { sin } x + 8 = 0 \text { in } R \text { is } } \\ { 0 } & { ( c ) 4 } \end{array} \right.
Answer» let sinx = t so, the equation is reduced to t²-6t+8 = 0=> t²-4t-2t+8 = 0=> t(t-4)-2(t-4) = 0=> (t-4)(t-2) = 0=> t = 2,4 but since t = sinx and it ranges from [-1,1] so, there is no. solution option a. thank you very much. it's good solution

\left. \begin{array} { l } { \text { Vumber of Solution of equation } \operatorname { sin } ^ { 2 } x - 6 \operatorname { sin } x + 8 = 0 \text { in } R \text { is } } \\ { 0 } & { ( c ) 4 } \end{array} \right.

Answer»

let sinx = t

so, the equation is reduced to

t²-6t+8 = 0=> t²-4t-2t+8 = 0=> t(t-4)-2(t-4) = 0=> (t-4)(t-2) = 0=> t = 2,4

but since t = sinx and it ranges from [-1,1]

so, there is no. solution

option a.

thank you very much. it's good solution