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Q.1. In the given figure AB = CD, LABD = <CDB.Prove that AD = CB. [Board Term 1, 2012, Set-35]

Answer»

In ∆ABD and ∆CDB AB = CD (given)∠ABD = ∠CDB (given) BD = BD (common)∴ ∆ABD ≅ ∆CDB (SAS congruence)=> AD = CB (CPCT)



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