Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Q.15 Find the sum of all those integers between 100 and 800 cach of which on division by 216, leaves the remainder7P ry

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2.

(x^3 %2B 1/(x^3))*(x^4 %2B 1/(x^4))

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X cube and X to the four will be cancelled and they will become 1and 1+1= 22×2=4 henceforth the answer will be 4

3.

3. What will be the angle of reflection if a ray of light strikes a plane mirror at an angle of 907

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4.

7 The divisor and the quotient of the number6123 are same and the remainder is half theMar 16]divisor. Find the divisor.

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5.

iii) When the dividend and divisor are of opposite signs, the quotient has a .................... sign.

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as both are of opposite this quotient is of negative sign

negative sign is right answerplease like my answer

negative sign is the right answer

negative sign is right answer

6.

Q2.Let α ßbe the roots ofx2 + bx + 1 = 0 Then find the equation whose roots are-(a+)and-β+

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7.

16. Find sum and no. of divisor of 100 is17,9b) 216, 12c) 217, 6

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Divisors of a number- These are those numbers which divide the number perfectly.for eg->divisors of 8 will be - 1,2,4,8.so similarly for 100 the divisors are- 1,2,4,5,10,20,25,50,100.that is,9.Hence sum is 1+2+4+5+10+20+25+50+100=217

8.

In the given figure. Find the value of reflex angle POR.74°

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thank u so much

9.

3. PQRS is a rectangle with sides PS 5 cm andPQ = 12 cm. Find the length of QR, SR and thetwo diagcnals PR and QS.12 cm

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qr = ps = 5cmsr = pq = 12cm

diagonal length will be√(12^2 + 5^2)13cm

10.

Construct a quadrilateral PQRS in which sides PQ 3 cm, QR 4 cm, RSSP = 4 cm and diagonal PR = 5 cm. Measure <PQR using a protractor.3.5 cm,

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11.

and the houf hand Ui & CIOUIAt 5 o'clock, what are the obtuse angle and the reflex angle between the minute hand the hour hand of a clock?andSosoh of the following

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The minute hand travels 360°/60 = 6° per minute and the hour hand travels 360°/(60 x 12) = 0.5° per minute

The time reference for such questions is always 12:00 hours when both minute and hour hands point towards 12 and make an angle of 0°.

At 5:00, the minute hand would have effectively travelled for 0 minutes covering (0 * 6 = 0°) from reference point.

The Hour hand would have travelled for 5 x 60 = 300 minutes. It covers an angle of 300 x 0.5 = 150°

The angle between the two handsnowis 150°-0° = 150°

12.

sqrt(x/169 %2B 1)=(14/13)*text

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x=27 is the right answer

27 is the right answer

25

the answer is 27 of root of 1+27/169

इसका उत्तर 27 होगा। पूरा solve Karne pr 27 hi aayega.

sabse pahle dono pakkcchho ka varg karege. uske. baad. pahla pakkchha ka root hat jayega aur dusre. pakcchhha ka varg hojayega 196/169. eshi parkar slove ho jayega.

x=27 is right answer

x=27is right answer of this question

X = 27 Is the correct answer. please like and comment me

the answer of this question is 27 if we solve full question then our answer will came 27 first we will divide both the the questions into lhs and RHS means right hand side and left hand side then the the right hand side route will automatically cut down and 196 upon 169 will will be after cutting aur division method the answer will come 27

169+x/169=14/13169+X=14×169/13169+X=14×13X=192-169X=23

1+×/169=196/169169+×/169=196/169169+×=196×=27

this answer is x =27

The value of x=27 so, 27 is the right answer

87 is the right answer

13.

. In a division sum, the divisor is 9, the quotient is 41 and the remaindethe dividend.

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Formula:dividend=Divisor×quotient+RemainderGiven:divisor=9; quotient=41; remainder=7

dividend=(9×41)+7=369+7=376

14.

sqrt(27/169 %2B 1)=x/13 %2B 1

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sqrt(1 + 27/169) = (1 + x/13)

sqrt(196/169) = (1 + x/13)

(14/13) = 1 + x/13

x/13 = 14/13 - 1

x/13 = (14 - 13)/13

x/13 = 1/13

x = 1

Therefore, value of x = 1

the value of the x is one1

15.

3. A field is in the shape of a trapeziumwhose parallel sides are 25 m and 10 m.The non-parallel sides are 14 m and 13 m.Find the area of the field.(A) 196 cm2 (B) 186 cm2(C) 169 cm2 (D) 199 cm2

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16.

tersect each other and form fourangles A, B, C and D.Prove that ZC and ZD are vertically oppositeangles and are equal in measure.A.B. If the measure of ZA is increased by 10°, whawould happen to 4C?

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17.

in triangle PQR is right angle at Q has been inscribed in triangle if PQ= 12cm and QR= 5cm. find radius of circle

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your figure is wrong. it is said in question that "circle is inscribe the circle"please don't give a wrong answer please!!

Sorry for overlooking the question.Here is the correct solution.

18.

18.A and B are points on the sides PQ and QR of a trianglePQR, right angled at Q. Prove that AR? + PBP = AB? +PR?

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Given, PQ = 12.5 cm, PA = 5 cm, BR = 6 cm and PB = 4 cm

19.

(a) 5(b) 11(d) 35. If the equation kx(r-2)+6+ 6 = 0 has two equal roots, then thevalue of k is-혀-0(b) 6(c) 2(d) 12

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Thank you.

20.

Find the area of a segment of a circle of radius 7cm if the arc of the segment has measure 90°.

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It will be area of sector- area of the triangleas the triangle is right angled we can calculate its area as 0.5×7×7=24.5the area of segment = 0.25×3.14×7×7 - 24.5=38.465 - 24.5=13.965

21.

11. Find the value of K, if x=-1&y= 1is a sofution of equation Kx-2y = 0

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k=-2Is the CORRECT answer;

x=-1;y=+1

22.

A Hemisphere Of lead Of radius 7cm is Casted into a Right Circular Cone Of Height 49cm. Find the Radius of Base.

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23.

Find the value of k for which the equation kx²-5x +k=0has equal roots

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4√3 x² +5x -2√3 =0⇒4√3 x² +8x -3x -2√3=0⇒4x(√3 x+2) -√3(√3x +2) =0⇒(√3x +2)(4x -√3) =0⇒(√3x +2) =0 or (4x-√3) =0⇒x = -2/√3 or√3/4

tq

24.

2.| Find thc value ofk, for which one root of the quadratic equation kx-14x+ 8-0 is 2.

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25.

16. For what value of k, the roots of the quadratic equation kx(2 V5) + 10 0 are equal ?

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26.

Reflex Angle

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Thereflex angleis the largerangle. It is more than 180° but less than 360°

27.

EXERCISE 112Construct a triangle ABC in which BC 7em, 2B 75 and AB+AC 13cm.2 Construct a triangle ABC in which BC 8cm 4B45 and AB-AC-35cm.Construct a triangle POR in which QR-6cm, LQ-60" and PRCinstruct a triangle XYZ in which CY-30. anwand XY +YZ+ZX=11crn.Construct a right triangle whose base is 12cm and sum of its hypotenuseside is 18 cm2cm.3.4.5.PQand other

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28.

(OR)b) Construct parallelogram PORS with PQ 4.5 em, QR 3 cm andPOR-60

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29.

33.How many times is the greatest divisor of 52 is that of smallest divisor ?(1) 26(2) 13(3) 4(4) 52

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smallest = 1greatest = 52Option = D

30.

Mathematics1. If HCF(26,169)-13, then LCM is (a) 26(b) 52 (c)338(d)1

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HCF*LCM = 26*169LCM = 26*169/HCF = 26*169/13LCM = 338

31.

EXEHCISE 13 (Asure of one angle of a parallelogram is 80. Whaeaining angles?lelogram is 80o. What are the measures oftheadiacent angles of a parallloudiacent angles of a parallelourthe measure o

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32.

The measures of two angles of a triangle are 72 and 58°. Find the measure of the third angle.

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Let the third angle =xGiven, 1st angle=72° 2nd angle=58°We know that,x+72°+58°=180°x+130°. =180° x. =180°-130° =50°Therefore ,the measure of the third angle=50°

33.

Question 3the size of each lettered angle in the following figure.72°

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34.

The perimeter of a parallelogram is 102 cm. If one side is greater than the other by9of all the sides of the parallelogramcm, finá thele9.doc f a parallelogram are in the ratio 3:5, If the nerimeter of tho

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thank u soo much

35.

10) Find the area of a sector of a circle with radius 7cm and angle of the sector is 60

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36.

x-3/5+2x+1/3=22/15

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x - 3/5 + 2x + 1/3 = 22/153x = 22/15 + 3/5 - 1/33x = (22 + 9 - 5)/153x = 26/15x = 26/45

37.

Quadratic Equaion12. Find the value of k for which the roots of the quadratic equation kx'-10x+5 0areequal.

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Since roots aare equal then Discriminant=0

b^2-4ac=0

100-4*5*k=0100/20=kk=5

38.

Hoe many rectangles can be drawn with 18 cmas the perimeter?

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39.

EXERCISE6.I,In Fig 6.13, lines All and CD interseet at . If2 HOE and reflex zcot

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40.

Q.2. If the quadratic equation kx - 2kx 3-0 has equal roots, then find the value of k2

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41.

Find the valuc of k, for which one root of the quadratic equationkx^2-14x+8 = 0 is 2.

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If 2 is root of of p(x) = kx² - 14x + 8

Then p(2) = k×2² - 14 × 2 + 8 = 0

4k - 28 + 8 = 0

4k = 20

k = 20/4 = 5

k = 5

42.

Find the value of k, for which one root of the quadratic equation kx -14x#8 0 is 2.is 2.ORFind the value(s) of k for which the equation x2 + 5kx + 16 = 0 has real and equal roots.

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2 is a root so if we put x=2 we will get o as an answer 4k-28+8 = 0 4k = 20 k = 5

x*x+5kx+16 = 0 equal roots so b*b = 4ac 25k*k = 64 k*k = 64/25 k = 8/5 or -8/5

thanks yr

43.

Find the area of sector, whose radius is 7cm. with the given angle:60 ii. 30ili 72v. 90° v. 120°

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44.

Find the value of k for one root of the quadratic equation kx^2 - 14x +8 = 0 is six times the others

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Let roots beα andβA/qα = 6βnow, ifα andβ are roots then equation will be (x -α)(x -β) =0(x -α)(x -β) =0⇒ x² - (α+β)x +αβ =0now puttingα = 6β ,⇒x² - (6β +β)x + 6β×β =0⇒x² - 7βx +6β² =0now comparing with kx² -14x +8 =07β =14/k⇒β =2/k ⇒β² = 4/k²_______(1)and 6β² =8/k⇒β² =4/3k_______(2)equating (1) and (2), we get,4/k² = 4/3k⇒k =3

45.

Find the value of k for which one root of the quadratic equation kx^2- 14x + 8 -0 is six times the other.

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46.

3D(x +4+2) = 1ay tyz 22322. xy +42 + Zn = -1 and 22-|he value of ty5+23Factorise : 2+2x?_2-2 by using factortheonem (No long division).

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47.

EXERCISE29.11. If x = 3z + 4 ; y = x-4 and z = 1.5, find the value of 2x + 3y-22.(1) 33.5(2) 27.5(3) 6.5(4) 7.5

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thankyou very much

48.

distance of Q from the centre is 25 cm. WHat is it TadiuPind the area of sector, whose radius is 7cm with an angle 72wha ithe

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Area of sector = θ/360° × πr²

Area of sector = 72/360° × 22/7 × 7²

Area of sector = 8/40 × 22 × 7

Area of sector = 154/5 = 30.8 cm²

49.

288MathsThe area of a triangle, whose base and the corresponding altitude are 15cm and 7cm, is equal to the areaota right angle is 10.5cm. Find the other side of this triangle7.

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50.

(A) 7cm(C) 21 cms(B) 14cm

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