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Find the valuc of k, for which one root of the quadratic equationkx^2-14x+8 = 0 is 2. |
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Answer» If 2 is root of of p(x) = kx² - 14x + 8 Then p(2) = k×2² - 14 × 2 + 8 = 0 4k - 28 + 8 = 0 4k = 20 k = 20/4 = 5 k = 5 |
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