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Find the value of k for which the equation kx²-5x +k=0has equal roots |
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Answer» 4√3 x² +5x -2√3 =0⇒4√3 x² +8x -3x -2√3=0⇒4x(√3 x+2) -√3(√3x +2) =0⇒(√3x +2)(4x -√3) =0⇒(√3x +2) =0 or (4x-√3) =0⇒x = -2/√3 or√3/4 tq |
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