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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
14. In a circle of radius 21 cm, an arc subtends an angle of 60° at theFind the length of the arc.tho ratio 2:3. What ic s |
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| 2. |
L.C.M.éĄ(i) 26(iii) 338(ii) 521l(iv) 13. |
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| 3. |
Asha and Usha d3,20,000. Find their respective shares.However, Asha had a change of mind and decided to divide the profits equallybenefited from this decision and by what amount?ecided to divide their annual profit in the ratio 3:5. If the anual Profi. Who w |
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Answer» Let share of Asha be 3a and Usha 5aThen 3a + 5a = 3200008a = 320000a = 40000 Share of Asha = 3x40000 = 120000Share of Usha = 5x40000 = 200000 If share is divided equally then Asha will be benefitted by Rs 40000 |
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| 4. |
\left. \begin array l l \text (1) 26 & \text (2) 13 \\ \text (3) 4 & \text (4) 52 \end array \right. |
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Answer» Divisor of 52 are 1, 2, 4, 13,26, 52. Greatest divisor = 52 Smallest divisor = 1 So, 1 × 52 = 52 (4) option is correct |
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| 5. |
In given figure, <1= <2 and∆ NSQ = ∆ MTR,then prove that ∆ PTS ~ ∆ PRQ. |
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Answer» In the triangles PTS and PQR, let us assume that Q = angle 3 and R = angle 4.So, angle 1 = angle 3 (corresponding angles)and angle 2 = angle 4 (corresponding angles)Angle P is common angle.By AAA similarity triangle PTS is similar to PQR.Hence proved. |
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| 6. |
In triangle PQR, PQ-10 cm, QRangle of the triangle.12 cm, PR8 cm. Find out the greatest and the smallest angle of the triangle. |
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Answer» Largest side of triangle pqr is qr=12cm,smallest side is pr = 8 cm qr is greater than pq greater than pr Angle p is greatest angle and angle r is the smallest angle Reason angle opposite to greater side is greater |
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| 7. |
Composite Maththem1842. Find the unknown lentered angle.(iii)xCiv)705065653In each case find thew the following questions, the measures of two angles are given. In eache |
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Answer» 1)x=602)x=503)604)60 X=60x=506060 like me 1)x=602)x=503)x=604)x=60 is the right one |
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| 8. |
2. Find the value of k, for which one root of the quadratic equation kx-14x+8-0is 2. |
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| 9. |
| Find the value of k, for which one root of the quadratic equation kx,-14x+8 = 0 is 2. |
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Answer» If 2 is root of kx² - 14x + 8 = 0 So, k × 2² - 14 × 2 + 8 = 0 4k - 28 + 8 = 0 4k = 20 k = 5 |
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| 10. |
Fund the value of k. for which one root of the quadratic equation kx-14x-8-0 is 2 |
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Answer» If 2 is the root then after putting x= 2we may find the value of K4k-28-8=04k=36k=9 |
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| 11. |
7. A chord of length 40 cm is at a distance of 15 cm from the centre of a circle. Findthe radius of the circlecD aro two arallel chords of lengths 12 cm |
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| 12. |
construct a triangle ABC is which BC=4.5cm ,angle B=45° and AB-AC =2.5cm |
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Answer» angle A = 90 degree |
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| 13. |
So, total area (98+38.5) m2 136.5 m2The perimeter will be equal to the perimeter of the circle and twice the length of theectangle.Perimeter of the circle 2Ttr2x 22 x 3.5 = 22 m7Perimeter of the garden(22 + 14 +14) m- 50 mample 8. An ant is moving arohich foodund a few food pieces of different shapes scattered on the floor. Foiece would the ant have to take a longest roundb.1.5 cm2.8 cm2.8 cm2 cm2 cm |
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| 14. |
construct a triangle ABC in which BC=7cm angle B=75 and AB+AC =13 |
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| 15. |
13. Construct an isosceles right triangle PQR inwhich LR 90° and PR QR 3 cm. |
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Answer» QR is base of 3 cm, PQ is hypotenis, PR is 3 cm other angles are of 45 and 45 degree |
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| 16. |
. Ramesh wants to divide 14 presents between his sons Daksh and Daman in the raticobtained by them in their unit tests. If Daksh scored 20 marks and Daman scored 15many presents will each of them get?ofit in tho ratio 3 5 Ifthe annual |
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| 17. |
(IV) D(-2,-))2.12 Draw the graph of theraw the graph of the following equations(ii) y = x(0) y = 3x + 2 |
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| 18. |
62. Acard is drawn at random from a wellshuffled pack of cards. The probability ofthat card being a king is...C.D. 1522613 |
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Answer» but the correct answer is 1/13 in digest how? ??? |
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| 19. |
Construct the right-angled trianglePQRwhere <Q =90", QR = 2 cm andPR = 2.5 cm |
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| 20. |
Math 50 pts 2 minutes agoA quadrilateral has distinct integer sidelength. If the second largest side haslength 10 then the maximum possiblelength of the largest side is |
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Answer» In the above image, y is the largest side. We try to find the maximum value of each a, b, & x first. a & b each should be less than 10( as 10 is the 2nd largest) So, let's take a & b = 9 ( maximum integral value) So, x < 18 => x = 17 ( maximum integral value) & y < 10 + x => y < 10 + 17 =>y = 26( the maximum integral value) |
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| 21. |
two numbers is-and HOE OE TWO nasU the sum of LanaLawto the sum ofis 900 more tupo1260 and their carof two nurpoodwetHe then find thetwo numbers |
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Answer» Let a is the LCM and b is the HCF of two numbers. Given, a + b = 1260 ..............1 and a = b + 900 ...............2 substituting (2) in (1) , we get b + 900 + b = 1260 2b + 900 = 1260 2b = 1260 - 900 2b = 360 b = 360/2 b = 180 From equation 1, we get a + 180 = 1260 a = 1260 - 180 a = 1080 So, LCM = a = 1080 and HCF = b = 180 Now, product of two numbers = LCM * HCF product of two numbers = 1080 * 180 product of two numbers = 194400 thanks bhai |
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| 22. |
dx2. , xloglal ? |
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| 23. |
.2:11 tile quat latic equation KX -2kX-.I =0 nas equal roots, then rind the value ol k.+is zero? |
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| 24. |
2 aa"-x" +--sin-1325. Prove thatdx 222 |
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| 25. |
2. If the edge of a cube is 1 cm, then which of thefollowingisitsvolume(i) 6 m(ii) 1 m3(i) 3 m3(iv) none of these |
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Answer» Edge of cube = 1 CMVolume of cube = (1)³=1 cm³ thanks |
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| 26. |
rs of 272727 aroPactor7B) 13C) 37D) 41 |
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| 27. |
angular field is six times its breadth. If the length of the ficldis 114 m, indthe breadth and perimeter of the field. |
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| 28. |
Perimeter of a square and a rectangle is sume: IF a side of he square is Sem and o irectangle is 18cm, find the area of the rectangle. |
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Answer» Perimeter of Square Ps = 4*sidePerimeter of Reactangle Pr= 2(l + b) Given,side length of square = 15 cmlength of reactangle = 18 cnPs = Pr Then, 4*15 = 2(18 + b) 30 = 18 + bb = 30 - 18b = 12 Area of Reactangle = length * breadth = 18 * 12= 216 cm^2 |
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| 29. |
3.Construct a triangle PQR in which QR = 6cm, <Q = 60° and PR-PQ = 2cm. |
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| 30. |
1Two stones are thrown up simultaneously from the edgeofadil 240 m high with initialspeedof 10 m/s and 40 m/s respectively. Whichof the following graph bestre presents the timevariation of relative position of the second stone withrespect to the first?Assumestones do not rebound after hitting the ground and neglectairresistance, take g =10 m(the figure are schematicand not drawn to scale) |
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| 31. |
In AABC, LA 90. If ACangle B.Sem, AB - 6em, find all the trigonometric ratios of |
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Answer» Solve this question what do you think i have done here ?? |
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| 32. |
fite argeoteevatron ofecoud from eport h meters above a iake has measureand the angie of depression orh tans-tane)tang-tamtselectron mte ase nas measure β.provet at the terrtofte cons |
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Answer» Like if you find it useful |
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| 33. |
in A triangle PQR right angle at Q PQ=3cm and PR =6cm. Determine QR |
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| 34. |
ही3 Prove that: (cosecA ——“ ins |
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| 35. |
Evaluate:dx2 |
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| 36. |
ERÄ°METER, AREA, and VOLUMEFind the perimeter and area of the rectangx +2x + 6 |
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Answer» GivenLength of Reactangle = (x + 6)Breadth of Reactangle = (x + 2) Perimeter of Reactangle= 2(Length + Breadth)= 2(x + 6 + x + 2)= 2(2x + 8)= 4x + 16 Area of Reactangle= Length * Breadth= (x + 6)*(x + 2)= x^2 + 8x + 12 |
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| 37. |
(2) Multiply the given polynomials:2x, x2-2x-1. |
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Answer» 2x × ( x² - 2x - 1) 2x³ - 4x² - 2x four ex squre is there answer |
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| 38. |
very angular field aro 131find the5 m respectivelyding its four sus de thePerimeterAnswersParimeter is, bemLength his "a6m;find the breadth in2 Ce+b)=2226tb)=766 m.breadth = am |
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Answer» the answer is 2(l×b)= 2 (26 + b) =76cm.the breadth is 24. |
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| 39. |
) If m2 ends in 9, then m3 ends in 7 (T/F). |
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Answer» assuming m3 as m³False, because m³ ends with 9 |
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| 40. |
IndABC,LA(0 sin C90°. If AB(ii) tan B7am and BC-AC#1cm, find |
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| 41. |
Prove that the diagonals of the parallellogram bisect each other. [Hinton both axes as 1cm-a units]: Take scale |
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Answer» hit the like button if solution helped you. |
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| 42. |
Two cubes of side 4 cm are fixed together. Find the total surface area of the newsolid formed. |
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| 43. |
two cubes of side 4 cm are fixed together. Find the total surface area of the newsolid formed |
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Answer» When the two cubes are fixed together, the resulting solid is a cuboid. Length of the cuboid,= 2× edge of the cube = 2*4 = 8 cm Breadth of the cube = 1×edge of the cube = 4 cm Height of the cube = 1 × edge of the cube = 4 cm Total surface area of the cuboid = 2*(LB + BL + LH) ⇒ 2*(8*4 + 4*4 + 4*8) ⇒ 2*(32 + 16 + 32) ⇒ 2*80 ⇒ 160 sq cm So, the total surface area of the cuboid is 160 sq cm Thanks for the help |
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| 44. |
OMON and PQ6cm. Find RS.A is the centre of the circle and ABCD is a square. If BD-4cm thenfind the radius of the circle.7. |
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Answer» ABCD is a square.Diagonals of square are equal.BD=ACBD=4cmAC is the radius of circleSo, radius of the circle is 4cm |
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| 45. |
Find t! perimeter of a) the square with side length Semb) equilatcral triangle with side length 5cmc) the regular hexagon with side length 7emd) an isosceles triangle with equal sides 4cm each and third side 6cm |
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Answer» Perimeter (P)=sum of all sidesa) P= 4× 8 cm = 32 cmb) P= 3× 5 cm = 15cmc) P =6× 7 cm = 42cmd) P = 4 + 4 + 6 cm = 14 cm |
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| 46. |
IVIUS u nas Slues bum and 40m and one o gdiagonal is 80m long. Find the area of parallelogram.6. The sides of a quadrilateral ABCD are 6cm, 8cm, 12cm and. 14 cm respectivelyand the angle between the two sides is a right angle. Find its square.7 The perimeter of triangular field is 420 |
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Answer» i dont know but i ask my teacher only give chapter name or exercise |
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| 47. |
(2) Multiply the given polynomials:2x, x2-2x-1 |
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Answer» 2x × (x² - 2x -1)2x³ - 4x² - 2x |
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| 48. |
O A D TINM 5= oo 2w Né\ NG |की लो, BAMPMREES 9 >e Dfiy&a)\\; ही )S5i f |
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Answer» PLEASE LIKE IT, IF YOU FIND THIS SOLUTION HELPFUL. |
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| 49. |
nouluting Im costs Rs 20length, breadth and height of a room are 5 m,4 m and 3 m respectively.Iest of white washing the walls of the room and the ceiling at the |
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| 50. |
2. A path 1 m wide is built inside a square park of side 30 m along its sides. Find the areaof the path. Calculate the cost of constructing the path at the rate otro perale IF 25 cm of the table cover is |
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Answer» side of square park (A) = 30m width of path = 1m side of inner park (a) = 30-1-1 = 28m cost of construction = 70 per m^2 Area of path = Area of square park - area of park inside the path = A^2 - a^2 = 30^2 - 28^2 = 900 - 784 = 116m^2 Cost of construction of path = 70×116 =8120 |
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