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In given figure, <1= <2 and∆ NSQ = ∆ MTR,then prove that ∆ PTS ~ ∆ PRQ. |
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Answer» In the triangles PTS and PQR, let us assume that Q = angle 3 and R = angle 4.So, angle 1 = angle 3 (corresponding angles)and angle 2 = angle 4 (corresponding angles)Angle P is common angle.By AAA similarity triangle PTS is similar to PQR.Hence proved. |
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