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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
TV T TN S TN R S T S рди |
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Answer» thanks |
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| 2. |
duinnx-čş |
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| 3. |
Example 12. 10 students of a class participated in a onumber of boys is 4 more than the number of girls, find the number of boyomptetion. If the |
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Answer» Let the number of girls be X. Then the number of boys is X+4. Then, X+X+4 = 10=> 2x +4=10=> 2x = 6=> X =3. X +4 = 7. The number of boys is 7. Please hit the like button if this helped you out. |
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| 4. |
Convert intoDu km 6hm |
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Answer» 4000cm is the right answer 4000 CM is the right answer 🤔🤔🤔 4000 cm is the answer of the following 4000cm is the correct answer |
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| 5. |
4. A welf is du |
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Answer» Diameter=4mRadius=d/2=4/2=2mDepth=10m Volume of earth taken out=πr²h=22/7×2×2×10=8800/7 m^3 Curved surface area=2πrh=2×22/7×2×10=8800/ 7m²=88000000/7 cm²Cost of plastering inner curved surface area:-For 1 cm²=Rs. 5For 88000000/7 cm²=62857142.8 rupees. |
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| 6. |
There are 156, 208 and 260 students in groups A, B and C respectively. Buses are to beired for field trip. Find the minimum number of buses to be hired if the same numberf students should be accommodated in each bus. |
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Answer» 156 and 208156 = 2×2×3×13208 = 2×2×2×2×13 H.C.F. of 156 and 208 = 2×2×13 = 52 H.C.F. of 52 and 260 52 = 2×2×13 260 = 2×2×5×13H.C.F. = 2×2×13 = 52 Max. no of students per bus = 52Total no of students = 156+208+260 = 624 students.No. of buses = 624/52 = 12 buses. |
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| 7. |
re are 156, 208 and 260 students in groups A, B and C respectively. Buses are to befor field trip. Find the minimum number of buses to be hired if the same numbertudents should be accommodated in each bus.d |
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Answer» 156 and 208156 = 2×2×3×13208 = 2×2×2×2×13 H.C.F. of 156 and 208 = 2×2×13 = 52 H.C.F. of 52 and 260 52 = 2×2×13 260 = 2×2×5×13H.C.F. = 2×2×13 = 52 Max. no of students per bus = 52Total no of students = 156+208+260 = 624 students.No. of buses = 624/52 = 12 buses.Like my answer if you find it useful |
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| 8. |
(i)s Find the value of the expression 2x +22-Tx+ 72 when3+5A |
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Answer» thanks for answer which is done by u because this is also my doubt What is your doubt and in which step? |
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| 9. |
2o-52x = 578 + 5 find x. |
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Answer» x=-1 is the right answer x= -1 is correct answer Because the base of both sides are same so 5x=7x+2, then x=-1 |
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| 10. |
3. निम्त समीकरण को हल IR4 \cos \theta-3 \sec \theta=\tan \theta |
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Answer» please give me full answer |
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| 11. |
4x^3-37x^2+52x-15by4x-5 |
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| 12. |
(iii)4x3 - 37x2 + 52x - 15 by 4x - 5 |
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Answer» x square - 8x + 3 this is a answer of this question ty |
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| 13. |
दि =yy— du |
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Answer» thanks |
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| 14. |
A cat is located at point (-6,-4) in xy plane. A bottle of milk is kept at (5,11) .The cat wishes to consume. The milk traveling through shortest possible distance. Find the equation of part which need to take its milk ( answer with steps) |
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(b) a-b+C,when a=15, b = 10, and c-5 |
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| 16. |
dutn |
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Answer» y=sin^2(cos^-1x)so dy/dx=2sin(cos^-1x)cos(cos^-1x)(-1)/root(1-x^2)=2sin(cos^-1x)x(-1)/root(1-x^2) do not understand |
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| 17. |
73)40°(3) AABC, is an isosceles triangle. ZA 40°. Find ZACD |
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| 18. |
If there are 'x' rows of chairs and each row contains x2 chairs. Determine the totalnumber of chairs. |
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Answer» the total number of chair= x*(x)^2=. (x)^3 |
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| 19. |
10x=40, find X? |
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Answer» 4 is the right answer 4 is the right answer 4 is the right answer 4 is the right answer 4 is the correct answer of the given question 4 is the right answer 4 is the right answer 4 is the right answer 4 is the right answer 4 is the right answer 4 is the right answer 4 is the right answer If,10x=40Then,x=4. 4 is the right answer 4 is the right answer |
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| 20. |
A school hall is 50m×24m×16m.How many student can it accomodate if each student need 4 metre cubic air |
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| 21. |
Find the average of(a) 32,41,47, 48, 40, 40 |
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Answer» 32+41+47+48+40+40______________________ 6 =248_______ 6 =41.33333... |
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| 22. |
\left( 4 a ^ { 2 } - 4 a b - 15 b ^ { 2 } \right) \div ( 2 a - 5 b ) |
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| 23. |
If x+\frac{1}{x}=6 \text { then } x^{4}+\frac{1}{x^{4}}(A) 1148(C)1154(B) 1150(D) 1156 |
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Answer» Solution :- It is given that , x + 1/x = 6 ---( 1 ) Do the square of equation ( 1 ), ( x + 1/x )² = 6² x² + 1/x² + 2 = 36 x² + 1/x² = 36 - 2 x² + 1/x² = 34 --( 2 ) Again do the square of equation ( 2 ), ( x² + 1/x² )² = 34² x⁴ + 1/x⁴ + 2 = 1156 x⁴ + 1/x⁴ = 1156 - 2 = 1154option (c) is correct. |
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| 24. |
㍠cat |
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Answer» thanks |
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| 25. |
Q. 2 Find out 8% of 25Kg. |
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Answer» right answer is 2kgplease like my answer 2kg is your answer... We have, 8% of 25 kg = 8/100 x 25 = 2 kgRead more on Sarthaks.com - https://www.sarthaks.com/794893/find-out-8-of-25-kg is your correct answer We have, 8% of 25 kg = 8/100 x 25 = 2 kg is your correct answer 2kg is the correct answer........ |
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| 26. |
ABCD is a square of side 4 cm. If E is a point in the interior of the square such thatACED is equilateral, then area of AACE is |
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| 27. |
♡ (x+4) (2-5)=0, i5 25 unit 925 |
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Answer» By equating to 0 we can say x=4 and x=5 |
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| 28. |
Catdu |
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Answer» (a + b)2= a2+ b2+ 2ab |
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| 29. |
135and 925 |
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Answer» According to Euclid's division algorithm. a = bq+r Where a=dividend b=Divisor r=remainder Now a=bq+r225=135×1+90135=90×1+4590=45×2+0hence HCF of 135 and 225 by Euclid's division algorithm. is 45 |
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| 30. |
There are 1450 students of a school had to standin rows and columns. Where no. of rows andcolumn are same. How many student left out insuch arrangements. How many rows formed. |
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| 31. |
1225plants are to be in garden in such a way that each row contains as many plants as the number of rows find the no. of rows |
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Answer» No. Of plants = 1225 plants. No. Of rows = square root of 1225 Square root of 1225 = 35 Please see the attached picture.. Therefore, there are 35 rows. |
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| 32. |
1156 plants are to be planted in a garden in such a way that each row contains as many plant as the number of rows a find the of rows and number of plant in each row |
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Answer» gcud i0nezub9u9wv19wy1vU9Ev zeunniezkosszrxawh nesubjiexohwf sjxiyf 64 rows and each row have 64 plants there will be 64 rows and in each row there will be 64 plants in each rows 64 rows and each row have 64 plants is the |
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| 33. |
. 4225 trees an planted in a garden insuch a way that there are as many treesin each row as there are rows in agarden. Find the number of rows. |
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| 34. |
863 |
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| 35. |
5+6+8+6-3 |
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Answer» 5+6+8+6-3=(5+6+8+6)-3=25-3=22 |
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| 36. |
58ă36ăB4 |
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Answer» angle ABC = ACB = xIn triangle ABC2x + 58 = 180 2x = 180 - 58 = 122 x = 122/2 = 61 apply exterior angle theorem61 = y + 36y= 61 - 36 = 25 |
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| 37. |
ofthepassengers of a train were children,of the passengers wererest were women. If the number of women travelling in the trainnumber of passengers in the train.metanns80, find the t |
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Answer» Let total passengers in train = n Number of men passengers= 2n/5 Number of children passengers = n/8 Given,n - 2n/5 - n/8 = 380 Take LCM (40n - 16n - 5n) = 380*4019n = 380*40n = 20*40n = 800 Total number of passengers in train = 800 |
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| 38. |
State the three pairs of eaual pasts insABcand aceD |
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Answer» AD = DC [Given in the figure] AB= BC [Given in the figure] DB=DB [ Common ] |
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| 39. |
Hint: How many times does 67 go into 0? |
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| 40. |
r a parallelogram is 18 em and its height is i em, findl tof a parallelogram is 29.6 s om and itis boe is cm, fi |
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Answer» area of parallelogram=base× height=18×11=198 |
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| 41. |
9. Write three pairs if prime numbers such that the sum of each pair is also a prime |
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Answer» (2,3), (2,5), (2,11) write three pairs of coprime number |
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| 42. |
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row.18 in the row next to it and so on (see Fig. 5.5). In how many rows are the 200 logs placedand how many logs are in the top row?one000000000000nooooooooo0000000000000000 |
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| 43. |
115. 200 logs are stacked in such a way that there are 20 logs in the bottom row, 19 in the next row, 18 in thenext row, and so on. In how many rows 200 logs are placed and how many logs are there in the topind |
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Answer» 🙏 |
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| 44. |
1. If logs m+ logs-2, then is equal to1. If log m lo-, then m is equal to8 6 3 |
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| 45. |
(8) Evaluate : logs 10 logao 10 |
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Answer» please like my answer if you find it useful |
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| 46. |
\log \frac{11}{5}+\log \frac{14}{3}-\log \frac{22}{15}= ?® log2 ® log3 © logs ® log7 |
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Answer» thanks |
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| 47. |
Fill in the blanks(1) logs(AHSEC |
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Answer» Logarithmbase25 of 1/5is−1/2 Rewrite as anequation. log25(1/5)=x Rewritelog25(1/5) = x in exponential form using the definition of a logarithm. Ifx andbare positive real numbers andb does not equal1, thenlogb(x)=yisequivalenttob^y=x 25^x=1/5 (5^2)^x=5^−1 5^2x=5^−1 Since thebasesare the same, then twoexpressionsare only equal if theexponentsare also equal. 2x=−1 x=−1/2 |
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| 48. |
The value of logs 2log4 3logs 4.... (0g15 14log16 15 is |
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Answer» log₃2 can be written as log2/log3similarly others can also be written as log3/log4 , log4/log5 now on multiplication each numerator and denominator will cancel each other. (log2/log3)*(log3/log4)*(log4/log5).... after cancellation , the left terms will be log2/log16 = log₁₆2 = 1/4. answer |
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| 49. |
2 Find the value of log,5 3/3 -logs (0-04). |
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| 50. |
9.Value of θ is increased gradually from 6-0. At θ-tan-l | 2 | both the blocksjust start slipping. Than value of μ2 is: (g-10 m/s)μ=0.3 |
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