There are 156, 208 and 260 students in groups A, B and C respectively. Buses are to beired for field trip. Find the minimum number of buses to be hired if the same numberf students should be accommodated in each bus.

There are 156, 208 and 260 students in groups A, B and C respectively.

1.	There are 156, 208 and 260 students in groups A, B and C respectively. Buses are to beired for field trip. Find the minimum number of buses to be hired if the same numberf students should be accommodated in each bus.
Answer» 156 and 208156 = 2×2×3×13208 = 2×2×2×2×13 H.C.F. of 156 and 208 = 2×2×13 = 52 H.C.F. of 52 and 260 52 = 2×2×13 260 = 2×2×5×13H.C.F. = 2×2×13 = 52 Max. no of students per bus = 52Total no of students = 156+208+260 = 624 students.No. of buses = 624/52 = 12 buses.