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re are 156, 208 and 260 students in groups A, B and C respectively. Buses are to befor field trip. Find the minimum number of buses to be hired if the same numbertudents should be accommodated in each bus.d

Answer»

156 and 208156 = 2×2×3×13208 = 2×2×2×2×13 H.C.F. of 156 and 208 = 2×2×13 = 52 H.C.F. of 52 and 260 52 = 2×2×13 260 = 2×2×5×13H.C.F. = 2×2×13 = 52 Max. no of students per bus = 52Total no of students = 156+208+260 = 624 students.No. of buses = 624/52 = 12 buses.Like my answer if you find it useful



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