Fill in the blanks(1) logs(AHSEC

1.	Fill in the blanks(1) logs(AHSEC
Answer» Logarithmbase25 of 1/5is−1/2 Rewrite as anequation. log25(1/5)=x Rewritelog25(1/5) = x in exponential form using the definition of a logarithm. Ifx andbare positive real numbers andb does not equal1, thenlogb(x)=yisequivalenttob^y=x 25^x=1/5 (5^2)^x=5^−1 5^2x=5^−1 Since thebasesare the same, then twoexpressionsare only equal if theexponentsare also equal. 2x=−1 x=−1/2

Answer»

Logarithmbase25 of 1/5is−1/2

Rewrite as anequation.

log25(1/5)=x

Rewritelog25(1/5) = x in exponential form using the definition of a logarithm. Ifx andbare positive real numbers andb does not equal1, thenlogb(x)=yisequivalenttob^y=x

25^x=1/5

(5^2)^x=5^−1

5^2x=5^−1

Since thebasesare the same, then twoexpressionsare only equal if theexponentsare also equal.

2x=−1

x=−1/2

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Fill in the blanks(1) logs(AHSEC

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