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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1751. |
Plz help me how to get good Mark from mathematics |
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Answer» Study Believe on yourself and focus on knowledge Lots of practice only. Passing marks : 27 in cbse .... |
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| 1752. |
Write the value of 2n-1C5 + 2n-1C6 + 2n-1C7 |
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| 1753. |
How many 4 digit numbers are there with no digit repeated? |
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Answer» 4536 4536 correct answer 4536 correct 9×9×8×7=4536 9×9×8×7=4536If u are taking. 0,1,2,3,4,5,6,7,8,9 24 |
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| 1754. |
Sum of 5+55+555...to n terms |
| Answer» Is this a real question or u made it ??? | |
| 1755. |
Any one have half yearly blue print of Maths .... |
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Answer» Maths ka blue print mere friend ko chahiye tha ... No, I have chosen Hindi Aadika u have taken both maths and hindi? Jaldii help karo U r a kvaian so it might help I got papers |
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| 1756. |
Find the 4th term in the expansion of (x-2y)power 12 |
| Answer» 4th term we should find it by using general formula Tr+1 = ^nCr X^n-r Y^rr=3 , n=12 ,X=x y=2y. Substute it in the formula . | |
| 1757. |
Given f : R → R as f(x) = 3x + 4. If ordered pairs (a, 8) and (2, b) belong to ‘ f ’. Find a and b. |
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| 1758. |
1/8! + 1/7! = x/8! Find x. |
| Answer» X=9 | |
| 1759. |
Sina + sin(a + 2π/3) sin(a + 4π/3) =0 |
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| 1760. |
Cos(180/2-x |
| Answer» Sinx | |
| 1761. |
. find the sum of the first n terms of the series 3 + 7 + 13 + 21 + 31 + ...... |
| Answer» Given: Sn = 3 + 7 + 13 + 21 + 31 + ...... + an-1 + an……….(i)Also Sn = 3 + 7 + 13 + 21 + 31 + ...... + an-2\xa0+ an-1\xa0+ an ……….(ii)Subtracting eq. (i) from eq. (ii), 0 = 3 + ( 4 + 6 + 8 + 10 + ....... up to (n - 1) terms) - an\xa0{tex}\\Rightarrow a _ { n } = 3 + \\frac { n - 1 } { 2 } [ 2 \\times 4 + ( n - 2 ) \\times 2 ]{/tex}{tex}\\Rightarrow a _ { n } = 3 + \\frac { n - 1 } { 2 } [ 8 + 2 n - 4 ]{/tex}{tex}\\Rightarrow{/tex}\xa0an = 3 + (n - 1) (n + 2){tex}\\Rightarrow{/tex}\xa0an = 3 + n2 + n - 2{tex}\\Rightarrow{/tex}\xa0an = n2 + n + 1{tex}\\therefore{/tex}\xa0{tex}{S_n} = \\sum\\limits_{k = 1}^n {{a_{_k}}} = \\sum\\limits_{k = 1}^n {({k^{^2}}} + k + 1){/tex}= (12 + 1 + 1) + (22 + 2 + 1) + (32 + 3 + 1) + ...... +(n2 + n + 1)\xa0= (12 + 22 + 32 + ....... + n2) + (1 + 2 + 3 + ...... + n) + n\xa0{tex}= \\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } + \\frac { n ( n + 1 ) } { 2 } + n{/tex}{tex}= n \\left[ \\frac { 2 n ^ { 2 } + 3 n + 1 + 3 n + 3 + 6 } { 6 } \\right]{/tex}{tex}= n \\left[ \\frac { 2 n ^ { 2 } + 6 n + 10 } { 6 } \\right]{/tex}{tex}= \\frac { n } { 3 } \\left( n ^ { 2 } + 3 n + 5 \\right){/tex} | |
| 1762. |
If f(x)=x^2+2x+7 |
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Answer» Domain = R Range = R . |
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| 1763. |
Differentiate (x-1/x)^2 |
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| 1764. |
What is the result of{ 0 power 0 i.e. (0°) }???? |
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Answer» Answer is not defined But sometimes we take it 1 as you see in your calculator (phone) Answer is infinitive/ infinity/Not define Answer is not 1 All you are wrong 1 1 1 1 |
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| 1765. |
Shapes |
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| 1766. |
(1+x)^101(1+x^3)^100 find cofficent of x^50 |
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| 1767. |
Under root tan x + under root cot x integration |
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| 1768. |
What is HP give explain with examples please |
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| 1769. |
Find domain and range of the given function : 16-x |
| Answer» Domain = R Range = R | |
| 1770. |
np5=42 np3 find value of n |
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| 1771. |
Find the value of tan 13pie/12 |
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| 1772. |
Solve the equation -x^2+x-2=0 |
| Answer» Ans .-1±√7/-2 | |
| 1773. |
Bnm |
| Answer» Kinetic energy | |
| 1774. |
find the modulas and conjugate of complex no. 4+3i |
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Answer» Modulous = √16 +9=√25=5 And conjugate is __ ______Z. = 4 + 3i = 4 - 3i But answeof modulas given in book is √7 _MODULUS_ Let z = 4 + 3i ( where a=4 , b=3) => |z| = |4+3i| => |z| = root (4^2 + 3^2) = root( 25) = 5Modulus = 5 ansConjugate = 4 - 3i ans Modulas = 5, conjugate =4+3i Mod 5Con 4-3i Conjugate- 4-3iModulas- √7 |
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| 1775. |
n(A)=1,n(P(P(P(A))))= |
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Answer» Sorry ans is 16 8 ( (1),(phi),phi ) 2^4=16 |
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| 1776. |
Variance of first n natural Numbers |
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| 1777. |
Find per annum conpound anually when principle is 18000 and rate is 10% and year is 2 and have year |
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| 1778. |
5 properties of AP |
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Answer» Total 8 properties r their if want i will send u 2) If constant is subtracted from each term of AP ; the resulting sequence is also an AP 1) If constant is added to each term of AP; the resulting sequence is also an AP |
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| 1779. |
Solution set of |x-1| |
| Answer» -1is true | |
| 1780. |
Is important question are created in exam |
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Answer» Surely yes Obviously |
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| 1781. |
Sin4x / sin2x limit x- 0 |
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Answer» 2 2 cos2x |
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| 1782. |
A commitee of |
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| 1783. |
y= xcosx/sinx+cosx |
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| 1784. |
Cos510°cos330° + sin 390° cos120°= -1 |
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| 1785. |
Sinx=15° value |
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| 1786. |
Bhang bhosada kaab bana |
| Answer» This is inappropriate ? | |
| 1787. |
If X^2 -3x - 4 |
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Answer» Thanks to all for help?? -infinity to -1 -1 to 4 (-infinity to -1) |
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| 1788. |
Find the value of x if (x2 |
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| 1789. |
(2_x)^5(3 2) |
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| 1790. |
what is the value of iota **iota means iota ki power iota ? |
| Answer» Iota is indicated by ii=✓-1i²=-1In a complex number: Z=X+iy,x,y€R X is called the real part and y ia is the imaginary part. i is the solution of the equation | |
| 1791. |
Answer of half yearly paper |
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| 1792. |
Prove that cos10°+cos110°+cos130°=0 |
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Answer» Use the formulacosC+cosD:2cos(C+D/2)cos(C-D/2)Use this in the question:2cos(10+110/2)cos(10-110/2)+cos130=02cos60°cos(-50°)+cos130°=02×1/2.cos50+cos130=0cos50+cos130=02cos(50+130/2)cos(50-130/2)=02cos90.cos40=02×0.cos40=00=0H.P Thku cos 10 + cos 110 + cos 130 = (cos 10 + cos 110) + cos 130=\xa0{tex}2cos \\frac{(110+10)}{2}\\times cos\\frac{(110-10)}{2}{/tex}\xa0+ cos 130 {using cos C + cos D}= {tex}2cos \\frac {(C+D)}{2}{/tex}{tex}\\times{/tex}{tex}cos\\frac {(C-D)}{2}{/tex}={tex}2cos\\frac{120}{2}{/tex}{tex}\\times{/tex}{tex}cos\\frac {100}{2}{/tex}+ cos (180 - 50) (As 130 = 180 - 50)= 2 cos 60 {tex}\\times{/tex} cos 50 - cos 50 (Using cos (180 - A) = - cos A)= 2 {tex}\\times{/tex}{tex}\\frac{1}{2}{/tex}{tex}\\times{/tex} cos 50 - cos 50 ( As cos 60 = {tex}\\frac{1}{2}{/tex})= cos 50o - cos 50o = 0
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| 1793. |
Find square root of i |
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Answer» -1 -1 -1 R= { (x,y): x,y € W x square + y square = 25 |
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| 1794. |
Allied angle |
| Answer» Gfyb | |
| 1795. |
Prove that cos6x=32cos6 x-48cos4 +18cos2 x-1 |
| Answer» LHS =\xa0{tex}\\frac { 1 + \\sin \\theta - \\cos \\theta } { 1 + \\sin \\theta + \\cos \\theta }{/tex}=\xa0{tex}\\frac { ( 1 - \\cos \\theta ) + \\sin \\theta } { ( 1 + \\cos \\theta ) + \\sin \\theta }{/tex}\xa0=\xa0{tex}\\frac { 2 \\sin ^ { 2 } \\frac { \\theta } { 2 } + 2 \\sin \\frac { \\theta } { 2 } \\cdot \\cos \\frac { \\theta } { 2 } } { 2 \\cos ^ { 2 } \\frac { \\theta } { 2 } + 2 \\sin \\frac { \\theta } { 2 } \\cdot \\cos \\frac { \\theta } { 2 } }{/tex}[{tex}\\because{/tex}\xa0sin2x =\xa0{tex}\\frac { 1 - \\cos 2 x } { 2 } \\Rightarrow{/tex}\xa0{tex}2 sin^2x = 1 - cos 2x{/tex}\xa0and {tex}2sin^2\xa0\\frac{x}{2}\xa0= 1 - cosx{/tex}\xa0and {tex}2 cos^2{/tex}\xa0{tex}\\frac { x } { 2 }{/tex}\xa0{tex}= 1 + cosx{/tex} and {tex}sinx = 2sin{/tex}\xa0{tex}\\frac { x } { 2 }{/tex}\xa0{tex}\\times{/tex}\xa0{tex}cos{/tex}\xa0{tex}\\frac { x } { 2 }{/tex}]=\xa0{tex}\\frac { \\sin ^ { 2 } \\frac { \\theta } { 2 } + \\sin \\frac { \\theta } { 2 } \\cdot \\cos \\frac { \\theta } { 2 } } { \\cos ^ { 2 } \\frac { \\theta } { 2 } + \\sin \\frac { \\theta } { 2 } \\cdot \\cos \\frac { \\theta } { 2 } } = \\frac { \\sin \\frac { \\theta } { 2 } \\left[ \\sin \\frac { \\theta } { 2 } + \\cos \\frac { \\theta } { 2 } \\right] } { \\cos \\frac { \\theta } { 2 } \\left[ \\cos \\frac { \\theta } { 2 } + \\sin \\frac { \\theta } { 2 } \\right] }{/tex}=\xa0{tex}\\frac { \\sin \\frac { \\theta } { 2 } } { \\cos \\frac { \\theta } { 2 } }{/tex}\xa0= tan\xa0{tex}\\frac { \\theta } { 2 }{/tex}\xa0= RHS{tex}\\therefore{/tex}\xa0LHS = RHSHence proved. | |
| 1796. |
Latitude practical of mathematicsComplete portion |
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| 1797. |
Find n... |
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| 1798. |
What is mathematics? Whay do we study? Why cant we kill it???????? |
| Answer» Wait,,if you think then you realise that how it is important | |
| 1799. |
What is the rank of the word RAM? |
| Answer» 5th rank | |
| 1800. |
What is signum function |
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