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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1651. |
Find the equation of a line parallel to x-axis at a distance of 3 units above x axis |
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Answer» { y-3=0 } Y=3 |
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| 1652. |
3.1 exercise solution |
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| 1653. |
Range for sin |
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Answer» Range for sin is 0 , 30degree to 1 ,90 degree 0 to1 Trignometry |
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| 1654. |
What is the value of 1*2*3*5**8*8*9*6*5*4*46÷4*6*4*4*0*8*4*2*1????? |
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Answer» Its very simple 95,385,600÷0 =not defined 0 answer 0 Infinity Not defined 0 |
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| 1655. |
find the value of cos( 480) & sin(-1125) |
| Answer» cos(480) can also be written as cos(2π+2π/3) , now we know that, value of cos(2π) is 0, so now we get cos(2π/3) that is , cos(π/2 + π/6) , that is cos(90+30), which is -sin(30) and its value is -1/2.And it should be -sin(1125).It can also be written as -sin(6π + π/4), and value of 6π is 0. So we get -sin(π/4) and it is -sin(45) and its value is -1/√2 | |
| 1656. |
Ex 3.3 |
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| 1657. |
Sum of n AMs between a and b is |
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| 1658. |
If the coefficient |
| Answer» Multiple of x or any variable | |
| 1659. |
Find the H. C. F of 4!,5!and6! |
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Answer» 4! 4! 6! = 6 x 5 x 4 x 3 x 2 x 15! = 5 x 4 x 3 x 2 x 14! = 4 x 3 x 2 x 1Therefore HCF is 4 x 3 x 2 x 1 = 244! Hcf of 4! ,5!,6!= 24 means 4! 4! i.e 24 |
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| 1660. |
Find the coordinates of vertices of triangle whose midpoints are (2,1) (-5,7)& (-5,-5). |
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Answer» Hoew Vertices are : A(2,-11) ;B(2,13) ;C(-12,1) |
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| 1661. |
Find the square root of 3-4i |
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| 1662. |
Find dervative by first principle tan x |
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| 1663. |
find the value of x and y by all the three methods 3x +y/8 =l.59 and 3y - x/7 + 9 1/8 = -13.2 |
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| 1664. |
20÷3 |
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Answer» 6*2/3 6.666666 |
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| 1665. |
Cos x². Find D.C. by first principle |
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Answer» -2Sinx^2 Dyueue |
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| 1666. |
X lim to 0 sin√x-sin√a /x-a |
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| 1667. |
Find domain |
| Answer» \tThe set of all possible values which qualify as inputs to a function is known as the domain of the function or It can also be defined as the entire set of values possible for independent variables.\tDomain can be found if – the denominator of the fraction is not equal to zero and the digit under the square root bracket is positive. (In case of a function with fraction values).\t\tFor e.g. the domain of the function\xa0F\xa0is set\xa0A\xa0i.e. {India, Pakistan, Australia, Sri Lanka}.To find the domain we need to look at the values of the independent variables which are allowed to use as explained above i.e no zero at the bottom of fraction and no negative sign in square bracket. | |
| 1668. |
Express -4 in degree |
| Answer» -229°5\'27" | |
| 1669. |
Chapter 9 miscllanous excercise |
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| 1670. |
5 - 2 root 5 minus root 4 + cos theta upon 3 sin square theta |
| Answer» 45 | |
| 1671. |
Geometrical figures |
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| 1672. |
(5+7x)power 6 |
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| 1673. |
Using section formula, show that the points A(2,-3,4),B(-1,2,1) andC(0,1÷3,2)are collinear |
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| 1674. |
What is the marks weightage of class 11 maths |
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| 1675. |
5^^2 |
| Answer» 5^^2=125 (5 raised to the power 2) | |
| 1676. |
Lim/x=0 x+3 |
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Answer» As we know that the value of x is 0 and then putting the value of x in the equation x+3=0+3=3 Lim/x=0 x+3Putting the value of x=00+3=3 |
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| 1677. |
I have a doubt in mathematics of chapter9 in miscellaneous exercise of question13 |
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Answer» Sorry but where is anwser Please ask your doubt. |
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| 1678. |
Find the number of arrangement of the letter of the word INDEPENDENCE |
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Answer» 12!/4!3!2!1663200 There are 12 letters ,of which n appears 3 times, e appears 4 times and d appears 2 times and the rest are all different. Therefore the required number of arrangements =12!÷3! 4! 2! = 1663200 |
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| 1679. |
Answer for 12r2+25r+12= |
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Answer» 12r²+25r+12=012r²+9r+16r+12=03r(4r+3)+4(4r+3)=0(3r+4) (4r+3)3r=-4. 4r=-3r=-4/3. r=-3/4 R=-4/3 or r=-3/4 |
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| 1680. |
How to solve permutations formula in (k+1) |
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| 1681. |
x_y=33x+4y=12 |
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| 1682. |
Prove that Cos4x= 1- 8sin^2xcos^x |
| Answer» Taking LHS cos4x= cos2 (2x) = 1- 2sin^2x = 1- 2 ( 2sinxcosx)^2 = 1-2 (4sin^2xcos^2x) = 1-8sin&2xcos^2x | |
| 1683. |
The number 251 in decimal system is expressed in binary system by what |
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| 1684. |
Expansion of (x+a) whole square is 51..? |
| Answer» It cannot be expanded .only we can find some terms such as first term ,last termmiddle ,general terms | |
| 1685. |
In an A. P 8,11,14,... Find Sn-Sn-1 |
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Answer» In this AP a=8and d=11-8=3Sn=n/2[2a+(n-1)d] =n/2[2x8+(n-1)3] =n/2 [16+(n-1)3]Replace n by n-1Sn-1=n-1/2[2x8+(n-1-1)3] =n-1/2[16+(n-2)3]Now Sn-Sn-1=n/2[16+(n-1)3]-n-1/2[+(n-2)3] Now on solving you will get the answer hope it will help you thanks Vnnk |
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| 1686. |
Limited divided by X equal to sin x sin 2x + sin 60 / sin 5x - sin 3x |
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| 1687. |
Sin (x+y)Hence prove sin (x-y) |
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| 1688. |
Find value of sin 18° |
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| 1689. |
Cos 20°+cos 100°+cos 140° find value |
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| 1690. |
5 cos square theta plus 7 sin square theta minus 6 |
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| 1691. |
Express 4 cosA . cosB . cosC as the sum of four cosines....? Plzzz help??? |
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| 1692. |
Explain cauchy swartzy inequality |
| Answer» Cauchy-Schwarz inequalitythe theorem that the square of the integral of the product of two functions is less than or equal to the product of the integrals of the square of each function | |
| 1693. |
Cauchy swartzy inequality |
| Answer» Cauchy-Schwarz inequalitythe theorem that the square of the integral of the product of two functions is less than or equal to the product of the integrals of the square of each function | |
| 1694. |
If n A. p and first term is a and D-=1,2,3,....n so prove n terms addition is 1/2n(n squair+1 |
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| 1695. |
3 powee x-5 = 1/9 power x.. Soove for x. |
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| 1696. |
The largest possible right circular cone is cut of a cube of edge rcm .what is the volume of cone |
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Answer» 2/3*pi*(r/2)²*r It\'s simple, r^3cm^3 |
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| 1697. |
If alpha and beta are the roots of equation 6cos(theta)+8sin(theta)=9Find. sin(alpha+beta) |
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| 1698. |
Find the 20th term and the sum of 20terms of the series: 2×4+4×6+6×8+... |
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| 1699. |
Find enquation of parabola whose focus is (1,3) and directix 3x+4y =2 |
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| 1700. |
How many terms of GP ,3,3/2,3/4,........are needed to give the sum 3069/512? |
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