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| 1. |
find the value of cos( 480) & sin(-1125) |
| Answer» cos(480) can also be written as cos(2π+2π/3) , now we know that, value of cos(2π) is 0, so now we get cos(2π/3) that is , cos(π/2 + π/6) , that is cos(90+30), which is -sin(30) and its value is -1/2.And it should be -sin(1125).It can also be written as -sin(6π + π/4), and value of 6π is 0. So we get -sin(π/4) and it is -sin(45) and its value is -1/√2 | |