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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1851. |
1×2×3+2×3×4+3×4×5+4×5×6..........up to infinity =???? |
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Answer» n(n+1)/4.n^2+3n+5 Infinity Zero Excellent answer The answer is also infinite |
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| 1852. |
What is straight line |
| Answer» | |
| 1853. |
How many calenders are required to serve all possible leap years?(permutation and combination) |
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Answer» Plz answee Wow |
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| 1854. |
What is permutations and combination |
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| 1855. |
What is i?? |
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Answer» I means iota i means iota which is used to represent square root of -1 i is the symbolic form of √-1 The letter i is used to signify that a number is an imaginary number. It stand for the square root of negative one.\xa0 |
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| 1856. |
Cos2theta.cos 2phi plus sin^2( theta minus phi) - sin^2( theta plus phi) |
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| 1857. |
1/x3+1 |
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| 1858. |
Find its doman and rangeF(x)=/2x-3/=-3 |
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| 1859. |
x2+x+1root2=0 |
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| 1860. |
F(x)=/2x-3/=-3 |
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| 1861. |
Find the value of Sin(500π) |
| Answer» 0 | |
| 1862. |
Wt is the value of 13pi divided by 6 in trignometry |
| Answer» 390 | |
| 1863. |
Show that (1+i)^2=-2i |
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Answer» The correct question would be (1+i)^2 =2i From my opinion the question is wrong |
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| 1864. |
If A.M and G.M of Two positive number a and b are 10 and 8, respectively, find the numbers |
| Answer» (A+B)/2=10Root (AB)=65A×B=64_______(1)A+B=20A=20-BPUTTING IN EQ 120-B)×B=6420B-B*2=64B*2-20B+64=0B*2-4B-16B+64=0FROM HERE B= 4 OR 16 IF B=4 ,A=16IF B=16,A=4??? | |
| 1865. |
The angle between the minute and hour hands of a clock at 8:30 |
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Answer» 60 75 degree 75 degree 54° |
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| 1866. |
Cos2Acos3A—cos2Acos7A+cosAcos10A =cot6Acot5ASin4ASin3A—sin2Asin5A+sin4A+sin7A |
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| 1867. |
CoaA,CosB,CosC |
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Answer» Please once check your question again Question is not complete |
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| 1868. |
Prove that sin3x.sin^3x+cos3x.cos^3=cos^2x |
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| 1869. |
(√3+√2)^6-(√3-√2)^6 |
| Answer» F i r s t l y, t h e e x p r e s s i o n (a + b)6 – (a – b)6 i s s i m p l i f i e d by using Binomial Theorem.\xa0 | |
| 1870. |
Define modulus function? |
| Answer» Eis | |
| 1871. |
If tanx= b/a, prove that acos 2x +b sin 2x = a |
| Answer» This is simple write sinx and cosx in terms of tan x then put in the equation | |
| 1872. |
Find the argument of 1-i/1+i |
| Answer» -i | |
| 1873. |
Formula of a(square)-b(square) |
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Answer» But why a^2 - b^2 = ( a + b) ( a - b) |
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| 1874. |
Sin8π÷3*cos23π÷6+cos13π÷3*sin35π÷6 |
| Answer» 1 | |
| 1875. |
Best mathbook for 11 and 12 |
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Answer» R.b sharma and ncert is best R.D sharma is best R.D Sharma and the NCERT Book R.D.Sharma or R.S.Agrawal both R.D Sharma is the best |
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| 1876. |
A€¥¥ |
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| 1877. |
Find the value of 13π/13 |
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Answer» Pie Pie Pie 1 |
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| 1878. |
How many term in G P 3, 3/2 ,3/4 are needed to given 3069/512 |
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| 1879. |
456 20## |
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| 1880. |
Secx - tanx =3 |
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| 1881. |
Find the equation of the line which makes intercepts -3 and 2 on the X and y axes respectively |
| Answer» (Y/2)+(X/-3) = 1 | |
| 1882. |
Find tha domain of tha function f(x) =xsquare +3x+6\\xsquare-5x+4 |
| Answer» This question is same as example 21 of ncert | |
| 1883. |
1+7i/(2-i)^2 |
| Answer» 1+7i/(4-1-4i)=) 1+7i/3-4iRationalizing =) (1+7i)*(3+4i)/9+16=) 3-28+25i/25=) 25i-25/25=) i-1 Answer | |
| 1884. |
Prove thatsin10.sin30.sin50.sin70=1/16 |
| Answer» Sin10.sin30.sin50.sin.70=1/16(Taking the value of sin30°= 1/2) also sin50°= sin60-10& sin70°= sin60+10(it can be written as this)1/2 [ sin(60-10)sin(60+10)sin10°1/2 [sin²60- Sin²10]sin10°1/2[3/4 - sin²10]sin10°..( sin60=√3/2)&(√3/2)²= 3/4)Now 1/8[ 3sin10°- 4sin³] by using value of sin 3X1/8 [sin3X] x= 101/8[sin3× 10]1/8[ sin30°]ie. 1/8×1/2= 1/16 Hence proved... #PanDat_Golu❤ | |
| 1885. |
2c8 |
| Answer» Not possible as a equation of power 2 cannot have value of r as 8 | |
| 1886. |
Crossfire 19 into cos 2519 into cos 53 into cos 45 19 |
| Answer» | |
| 1887. |
Sinb-c/2=b-c/a.cosA/2 |
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Answer» prove ya solve Bhai carna kya hai |
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| 1888. |
Cosxcosx by 2 -cos3xcos9x by 2= sin4xsin7x by 2 |
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| 1889. |
Binomial theorem Expersing binomial theorem, evaluate each of the following (96) power 3 |
| Answer» It can be written in the form (100-4)whole cube and then it can be solved using binomial theorem | |
| 1890. |
If sum of p term is q and sum of q term is p then show that sum of p+q term is –(p+q) |
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| 1891. |
Solve for ×_X+8/X+2>2 |
| Answer» Its really simple. Let x+2 to rhs and then solve it | |
| 1892. |
Find 9th term of the following series 5,10,20,40 |
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| 1893. |
If tanx + tan(x+60) + tan(x+120) = 3Then prove that3tanx - tan³x = 1 - 3tan²x |
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| 1894. |
A={1,2,3}B={6,8,9}So find AUB |
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Answer» A union B={1,2,3,6,8,9} A union B = {1,2,3,6,8,9} |
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| 1895. |
Write the set of all vowels in english alphabet which precede s. |
| Answer» A= {a,e,i,o} | |
| 1896. |
तीन अंकों की सबसे छोटी संख्या बताओ जो 6,8,12से विभाजित हो जाए |
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Answer» 144 120 222 120 |
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| 1897. |
The number of subsets of a set containing n elements is |
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Answer» 2 to power n 2to the power n 2 to the power n |
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| 1898. |
Pattern kya hai cbse mid term ka ?marks distribution of syllabus mid term? |
| Answer» You can check syllabus in mycbseguide app of each subject in syllabus last page contains exam design which will help you. | |
| 1899. |
How many diagonals are there in a polygon with n sides ? |
| Answer» Solution= A polygon of n side has n vertices. By joining any two vertices of a polygon, we obtain either a side or a diagonal of the polygon. Number of line segment obtained by joining the vertices of an n sided polygon taken two at a time= Number of ways of selecting 2out of n =nC2=n(n-1)/2Out of these lines n lines are the sides of the polygon. Number of diagonals of the polygon =n(n-1)/2-n= n(n-3)/2 | |
| 1900. |
Important question chapter 5 |
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