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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1951. |
Do definitions of terms come in cbse exam |
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| 1952. |
Gen solof sinx |
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| 1953. |
H/7=tan(15degree) solve |
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| 1954. |
Find the general solution of the equation : Sinx+Sin3x+Sin5x=0 |
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Answer» ???????? (Sin5x+sinx)+sin3x=Sin3xcos2x+sin3x=Sin3x(cos2x+1)3x=nπX=nπ/3 |
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| 1955. |
What is dy/dx of log of 2^x to the base e |
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| 1956. |
Draw a quadrilateral in the Cartesian plane vortices are |
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| 1957. |
Express 1+cosx+isinx in polar form |
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| 1958. |
Exercise 7.4 ka 2 question |
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| 1959. |
49t²-300t+860 |
| Answer» Use shri dhara charya formula X=-b± under. root b²-4ac/2a | |
| 1960. |
Exercise 6.3 all questions |
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Answer» Visit ncert solutions from this app Yes |
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| 1961. |
How many 4-digit numbers are there with no digit repeated?☺️☺️☺️☺️☺️☺️ |
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Answer» 9*8*7*6=? Total no of digits =44 vaccent places can be filled with10P 4 WAYS but this no include those no whi start with zero If we find zero at thousands place then the remaining 3 places can be filled with remaining 9 digits in 9p 3 ways so Total no of 4 digit no = 10p 4-9p 410!/(10-4)! -9!/(9-3)!10*9*8*7*6! - 9*8*7*6!--------------------- --------------6! 6!=90*56-72*7=5040-504=4536 ans Hope it will help you? |
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| 1962. |
What is the value of Tan π/8 |
| Answer» I know this question but i dont know how i give u answer | |
| 1963. |
x=4,y=3 5x+3y= 9cC=? |
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Answer» 5x+3y=9c5×4+3×3=9c. [x=4,y=3 given]20+9=9c29=9cC=29/9C=3.22 29/9 29/3=9.66 29/9 C = 9/29 or 3.2 yaar C=29/9 |
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| 1964. |
Why sinx/x =1 in trigonometric limits? |
| Answer» Hi...but also their derivation is possible...but i can\'t understand by only reading it... | |
| 1965. |
_9+9i/1_2i find moduls |
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Answer» Sorry (1-2i )(1+2i) (-9+9i)(1+2i)/(1-i )(1+i) Modulas is root 5 |
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| 1966. |
3+9i-6+7i |
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Answer» -3+16i -3+16i |
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| 1967. |
Ex 3.4 ouestion no. 4 |
| Answer» It is available in this app under ncert solution option i hope u will be able to understand from that.? | |
| 1968. |
Math practical bool |
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| 1969. |
Find thevalue of x (x |
| Answer» What?????????????????? | |
| 1970. |
Find the equation |
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| 1971. |
The minute hand of a watch is 1.4cm long.how far does its tip move in 45minutes |
| Answer» This question is included in ncert ch 3 as example | |
| 1972. |
If Sn Denote sum of first n terms of an AP. and S2n = 3Sn. Then ratio of S3n/Sn equals to ? |
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| 1973. |
From where i can get the solution of activity work ? |
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| 1974. |
Sin3A+sin2A-sinA=4sinAcosA/2cos3A/2 |
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| 1975. |
Construct five different examples of sets. Describe each with the help of a proposition |
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| 1976. |
If two zeroes of the polynomial x⁴-6x³-26x²+138x-35 are 2+-√3. find other zeroes. |
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Answer» Two zeros are {tex}2\\pm\\sqrt3{/tex}Sum of Zeroes\xa0{tex}2 + \\sqrt { 3 } + 2 - \\sqrt { 3 } = 4{/tex}and product of zeroes =\xa0{tex}( 2 + \\sqrt { 3 } ) ( 2 - \\sqrt { 3 } ) = 4 - 3 = 1{/tex}Hence quadratic polynomial formed out of this will be a factor of given polynomial,So, x2 - (sum of zeroes)x + product of zeroes= x2 - 4x + 1 will be a factor of given polynomial,Divide given polynomial with x2 - 4x + 1 to get other zeroes.Now,x2 -2x - 35= x2 - 7x + 5x - 35= x(x - 7) + 5(x - 7)= (x - 5) (x - 7){tex}\\therefore {/tex}\xa0Zeros arex = 7 and x = -5{tex}\\therefore {/tex} Other two zeros are 7 and -5\xa0 Let the remaining two zeros be X and Y,As,Sum of roots =6 , product of roots = -35We get 2 equations,2+√3 + 2-√3 + x +y = 6x+y= 2-----(1)(2+√3)(2-√3)(xy) = -35xy=-35x=-35/y -----(2)Subs (2) in (1)y-35/y =2y²-2y-35=0y=[2±√(144)]/2y=7 y=-5x=-5 x=7Hence the roots are (2±√3),(-5),(7) . |
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| 1977. |
Evaluate cos105degree+sin105degree |
| Answer» The value of cos 105o\xa0+ sin 105o\xa0is\xa0{tex}\\frac{1}{\\sqrt{2}}{/tex}Cos trigonometric values are positive in “first and fourth” quadrants in coordinate axes.Sin trigonometric values are positive in “first and second” quadrants in coordinate axes.cos 105o\xa0+ sin 105o\xa0= cos (90o\xa0+ 15o) + sin (90o\xa0+ 15o)= - sin (15o) + cos (15o) (ascos (90o\xa0+\xa0{tex}\\theta{/tex}) = - sin\xa0{tex}\\theta{/tex}\xa0and sin (90o +\xa0{tex}\\theta{/tex}) = cos\xa0{tex}\\theta{/tex})= cos 15o - sin 15o{tex}\\left.=\\sqrt{2}\\left[\\frac{1}{\\sqrt{2}} \\cos 15^{\\circ}-\\frac{1}{\\sqrt{2}} \\sin 15^{\\circ}\\right] \\quad \\text { (Multiply and divide by } \\sqrt{2}\\right){/tex}{tex}=\\sqrt{2}\\left[\\sin 45^{\\circ} \\cos 15^{\\circ}-\\cos 45^{\\circ} \\sin 15^{\\circ}\\right] \\quad\\left(A s \\sin 45^{\\circ}=\\cos 45^{\\circ}=\\frac{1}{\\sqrt{2}}\\right){/tex}{tex}=\\sqrt{2}\\left[\\sin \\left(45^{\\circ}-15^{\\circ}\\right)\\right] \\quad(A \\sin (A-B)=\\sin A \\cos B-\\cos A \\sin B){/tex}{tex}=\\sqrt{2}\\left[\\sin 30^{\\circ}\\right]{/tex}{tex}=\\sqrt{2} \\times \\frac{1}{2}=\\frac{1}{\\sqrt{2}}{/tex} | |
| 1978. |
(1.1)^10000 or 1000 |
| Answer» 1.1^10000 | |
| 1979. |
cos(-1714) find the value |
| Answer» cos 1714cos (90*20-86)-cos86 | |
| 1980. |
cos4x+cos3x+cos2x/sin4x+sin2x+sin5x=cot3x |
| Answer» There is a mistake in this question. Write question is cos4x+cos3x+cos2x/sin4x+sin2x+sin3x=cot3x | |
| 1981. |
Tan cube theta minus tan theta is equal to 0 |
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| 1982. |
1+cos square 2 theta is equal to cross ka Ghat 4 theta Plus sin 4 theta |
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| 1983. |
Prove that cos2x + cos2(x+120) + cos2( x-120) = 3/2 |
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| 1984. |
Exercise 12.2 questions number. 4 |
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| 1985. |
Solve 24x |
| Answer» X=(1,2,3,4) | |
| 1986. |
(_2_1/3i)³ |
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| 1987. |
Question 15 of chapter 13 (limits and derivatives)exercise 13.3 |
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| 1988. |
7.4ka question |
| Answer» You can check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 1989. |
describe the set of complex numbers z,such that|3z-1/z-2|=3 |
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| 1990. |
If in 2 circles, arcs of same length substend angles 60° and 75°. Find the ratio of their radii |
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Answer» 5 ratio 4 We are givenangle 1= 60° and 75°To find,ratio of their radii..S=so the answer will be,in ratio5:4 5:4 |
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| 1991. |
Set A={1,2,3,.......100,} find the number of subsets of A such that the product of all element in |
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Answer» 123............100 Finite |
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| 1992. |
EVALUATE1+i+i2+i3 |
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| 1993. |
Virat Kohli total centuries in cricket history |
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Answer» ????????☺☺☺???????????????? What ??????? |
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| 1994. |
What is the latest examination pattern for the academic year 2019-20 ? |
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| 1995. |
Limits and derevative |
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| 1996. |
Ch sets example 35 |
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| 1997. |
Trigonometric ratio of sin B |
| Answer» B/h | |
| 1998. |
sin (150+x)+ sin (150-x) |
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Answer» 2sin x cos x =cosx |
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| 1999. |
1(c).8ka 3ra ke question |
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| 2000. |
Anyone is there to solve my problem of chapter 2 miscellaneous question 10 |
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Answer» Please write naaa yaar Or on the app See in book Can you write the statement please. |
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