This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 26551. |
In commercial TV transmission in India, picture and speech signals are modulated respectively(Picture)(Speech)(a)VSBVSB(b)VSBSSB(c)VSBFM(d)FMVSB |
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Answer»
Note that VSB modulation is the clever compromise between SSB and DSB. Since TV bandwidth is large so VSB is used for picture transmission. Also, FM is the best option for speech because of better noise immunity |
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| 26552. |
A 4 GHz carrier is DSB-SC modulated by a low-pass message signal with maximum frequency of 2 MHz. The resultant signal is to be ideally sampled. The minimum frequency of the sampling impulse train should be (a) 4 MHz (b) 8 MHz (c) 8 GHz (d) 8.004 GHz |
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Answer» (b) 8 MHz Given fc = 4GHz and fm = 2 MHz Such a signal is amplitude modulated (DSB-SC) i.e. two side bands = fc +fm and fc – fm = 4002 and 3998 ; BW = 4 MHz so, min. sampling frequency should be (Nyquist Rate) = 2 *4 MHz = 8MHz |
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| 26553. |
In FM signal with a modulation index mf is passed through a frequency tripler. The wave in the output of the tripler will have a modulation index of A. mf B. 3mf C. mf/3 D. mf/9 |
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Answer» B. 3mf Frequency multiplier increase the deviation, β = Δf/fm If multiplied by three,3 β = 3Δf/fm |
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| 26554. |
A DSB-SC signal is generated using the carrier cos(2πfc t + \(\theta\)) and modulating signal x(t). The envelop of the DSB-SC signal is (a) x(t) (b) |(t)| (c) Only positive portion of x(t) (d) (t) cos \(\theta\) |
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Answer» (b) |(t)| Given Carrier c(t) = cos(2πfc t + θ) Modulating signal m(t) = x(t) DSB SC modulated signal is given by m(t).s(t) = cos(2πfc t + θ)x(t) = x(t) { cos2πfc t cos θ - sin2πfc t sin θ} = x(t) cos2πfc t cosθ – x(t) sin2πfc t sin θ = x(t) |
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| 26555. |
The base-emitter voltage of an ideal transistor is a. 0 b. 0.3 V c. 0.7 V d. 1 V |
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Answer» The correct answer is: (a) 0 |
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| 26556. |
VSB modulation is preferred in TV becauseA. it reduces the bandwidth requirement to half B. it avoids phase distortion at low frequencies C. it results in better reception D. None of the above |
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Answer» D. None of the above VSB (vestigial side band) transmission transmits one side band fully and the other side band partially thus, reducing the bandwidth requirement. |
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| 26557. |
If you recalculate the collector-emitter voltage with the second approximation, the answer will usually be a. Smaller than the ideal value b.. The same as the ideal value c. Larger than the ideal value d. Inaccurate |
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Answer» (c) Larger than the ideal value |
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| 26558. |
The base-emitter voltage of the second approximation is a. 0 b. 0.3 V c. 0.7 V d. 1 V |
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Answer» The correct answer is: (c) 0.7 V |
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| 26559. |
If the collector resistance increases in a VDB circuit, the collector voltage willa. Decrease b. Stay the same c. Increase d. Double |
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Answer» (a) Decrease |
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| 26560. |
The Q point of a VDB circuit is a. Hypersensitive to changes in current gain b. Somewhat sensitive to changes in current gain c. Almost totally insensitive to changes in current gain d. Greatly affected by temperature changes |
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Answer» (c) Almost totally insensitive to changes in current gain |
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| 26561. |
The first step in analyzing emitter-based circuits is to find the a. Base current b. Emitter voltage c. Emitter current d. Collector current |
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Answer» (b) Emitter voltage |
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| 26562. |
The base voltage of two-supply emitter bias (TSEB) is a. 0.7 V b. Very large c. Near 0 V d. 1.3 V |
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Answer» (c) Near 0 V |
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| 26563. |
A circuit with a fixed emitter current is called a. Base bias b. Emitter bias c. Transistor bias d. Two-supply bias |
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Answer» (b) Emitter bias |
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| 26564. |
The bulk resistance of a 1N4001 is a. 0 b. 0.23 ohm c. 10 ohm d. 1 kohm |
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Answer» The correct answer is: (b). 0.23 ohm |
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| 26565. |
How much forward diode voltage is there with the ideal-diode approximation? a. 0 b. 0.7 V c. More than 0.7 V d. 1 V |
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Answer» The correct answer is: (a) 0 |
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| 26566. |
How much current is there through the second approximation of a silicon diode when it is reverse biased? a. 0 b. 1 mA c. 300 mA d. None of the above |
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Answer» The correct answer is: (a) 0 |
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| 26567. |
How much voltage is there across the second approximation of a silicon diode when it is forward biased? a. 0 b. 0.3 V c. 0.7 V d. 1 V |
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Answer» The correct answer is: (c) 0.7 V |
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| 26568. |
The reverse current consists of minority-carrier current and a. Avalanche current b. Forward current c. Surface-leakage current d. Zener current |
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Answer» (c) Surface-leakage current |
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| 26569. |
With a full-wave rectified voltage across the load resistor, load current flows for what part of a cycle? a. 0 degrees b. 90 degrees c. 180 degrees d. 360 degrees |
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Answer» (d) 360 degrees |
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| 26570. |
What is the peak load voltage out of a bridge rectifier for a secondary voltage of 15 V rms? (Use second approximation.) a. 9.2 V b. 15 V c. 19.8 V d. 24.3 V |
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Answer» The correct answer is: (c) 19.8 V |
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| 26571. |
If line frequency is 60 Hz, the output frequency of a half-wave rectifier is a. 30 Hz b. 60 Hz c. 120 Hz d. 240 Hz |
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Answer» The correct answer is: (b) 60 Hz |
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| 26572. |
The voltage across the zener resistance is usually a. Small b. Large c. Measured in volts d. Subtracted from the breakdown voltage |
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Answer» The correct answer is: (a) Small |
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| 26573. |
The collector current is 10 mA. If the current gain is 100, the base current is a. 1 microamp b. 10 microamp c. 100 microamp d. 1 mA |
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Answer» (c) 100 microamp |
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| 26574. |
The base current is 50 microamp. If the current gain is 125, the collector current is closest in value to a. 40 microamp b. 500 microamp c. 1 mA d. 6 mA |
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Answer» The correct answer is: (d) 6 mA |
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| 26575. |
Most small-signal E-MOSFETs are found in a. Heavy-current applications b. Discrete circuits c. Disk drives d. Integrated circuits |
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Answer» (d) Integrated circuits |
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| 26576. |
If line frequency is 60 Hz, the output frequency of a bridge rectifier is a. 30 Hz b. 60 Hz c. 120 Hz d. 240 Hz |
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Answer» The correct answer is: (c) 120 Hz |
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| 26577. |
With the same secondary voltage and filter, which produces the least load voltage? a. Half-wave rectifier b. Full-wave rectifier c. Bridge rectifier d. Impossible to say |
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Answer» (b) Full-wave rectifier |
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| 26578. |
Components are soldered together in a. Discrete circuits b. Integrated circuits c. SSI d. Monolithic ICs |
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Answer» (a) Discrete circuits |
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| 26579. |
The power dissipated by a transistor approximately equals the collector current times a. Base-emitter voltage b. Collector-emitter voltage c. Base supply voltage d. 0.7 V |
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Answer» (b) Collector-emitter voltage |
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| 26580. |
With the same secondary voltage and filter, which has the most ripple? a. Half-wave rectifier b. Full-wave rectifier c. Bridge rectifier d. Impossible to say |
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Answer» (a) Half-wave rectifier |
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| 26581. |
If the filtered load current is 10 mA, which of the following has a diode current of 10 mA? a. Half-wave rectifier b. Full-wave rectifier c. Bridge rectifier d. Impossible to say |
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Answer» (a) Half-wave rectifier |
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| 26582. |
In a loaded zener regulator, which is the largest current? a. Series current b. Zener current c. Load current d. None of these |
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Answer» (a) Series current |
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| 26583. |
The diodes in a bridge rectifier each have a maximum dc current rating of 2 A. This means the dc load current can have a maximum value of a. 1 A b. 2 A c. 4 A d. 8 A |
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Answer» The correct answer is: (c) 4 A |
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| 26584. |
If the line voltage is 115 V rms, a turns ratio of 5: 1 means the rms secondary voltage is closest to a. 15 V b. 23 V c. 30 V d. 35 V |
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Answer» The correct answer is: (b) 23 V |
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| 26585. |
What is peak lead voltage in full wave rectifier if secondary voltage is 20 vrms |
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Answer» Vrms = 20 Vp = ? Vplak = Vrms√2 Vplak = 20 x √2 volt |
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| 26586. |
What is the peak load voltage in a full-wave rectifier if the secondary voltage is 20 V rms? a. 0 V b. 0.7 V c. 14.1 V d. 28.3 V |
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Answer» The correct answer is: (d) 28.3 V |
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| 26587. |
The tail current of a diff amp is a. Half of either collector current b. Equal to either collector current c. Two times either collector current d. Equal to the difference in base currents |
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Answer» (c) Two times either collector current |
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| 26588. |
The input offset current equals the a. Difference between two base currents b. Average of two base currents c. Collector current divided by current gain d. Difference between two base-emitter voltages |
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Answer» (a) Difference between two base currents |
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| 26589. |
The collector-emitter voltage is usually a. Less than the collector supply voltage b. Equal to the collector supply voltage c. More than the collector supply voltage d. Cannot answer |
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Answer» (a) Less than the collector supply voltage |
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| 26590. |
When the reverse voltage increases, the capacitance a. Decreases b. Stays the same c. Increases d. Has more bandwidth |
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Answer» (a) Decreases |
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| 26591. |
The barrier potential across each silicon depletion layer is a. 0 b. 0.3 V c. 0.7 V d. 1 V |
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Answer» The correct answer is: (c) 0.7 V |
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| 26592. |
The emitter diode is usually a. Forward-biased b. Reverse-biased c. Nonconducting d. Operating in the breakdown region |
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Answer» (a) Forward-biased |
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| 26593. |
How is a nonconducting diode biased? a. Forward b. Inverse c. Poorly d. Reverse |
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Answer» The correct answer is: (d) Reverse |
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| 26594. |
A series regulator is an example of a a. Linear regulator b. Switching regulator c. Shunt regulator . Dc-to-dc converter |
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Answer» (a) Linear regulator |
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| 26595. |
An increase of line voltage into a power supply usually produces a. A decrease in load resistance b. An increase in load voltage c. A decrease in efficiency d. Less power dissipation in the rectifier diodes |
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Answer» (b) An increase in load voltage |
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| 26596. |
Why do we prefer a convex mirror as a rear-view mirror in vehicles? |
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Answer» Image formed by a concex mirror is always virtual, erect and smaller than the object. They are more helpful than the plane mirror because they can capture a wider range. |
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| 26597. |
A series regulator is more efficient than a shunt regulator because a. It has a series resistor b. It can boost the voltage c. The pass transistor replaces the series resistor d. It switches the pass transistor on and off |
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Answer» (c) The pass transistor replaces the series resistor |
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| 26598. |
A switching regulator is considered a. Quiet b. Noisy c. Inefficient d. Linear |
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Answer» The answer is: (b) Noisy |
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| 26599. |
In a boost regulator, the output voltage is filtered with a a. Choke-input filter b. Capacitor-input filter c. Diode d. Voltage divider |
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Answer» (b) Capacitor-input filter |
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| 26600. |
A current-sensing resistor is usually a. Zero b. Small c. Large d. Open |
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Answer» The answer is: (b) Small |
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