Saved Bookmarks
| 1. |
A 4 GHz carrier is DSB-SC modulated by a low-pass message signal with maximum frequency of 2 MHz. The resultant signal is to be ideally sampled. The minimum frequency of the sampling impulse train should be (a) 4 MHz (b) 8 MHz (c) 8 GHz (d) 8.004 GHz |
|
Answer» (b) 8 MHz Given fc = 4GHz and fm = 2 MHz Such a signal is amplitude modulated (DSB-SC) i.e. two side bands = fc +fm and fc – fm = 4002 and 3998 ; BW = 4 MHz so, min. sampling frequency should be (Nyquist Rate) = 2 *4 MHz = 8MHz |
|