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25801.

Organic chemistry

Answer»

Organic chemistry is the study of the structure, properties, composition, reactions, and preparation of carbon-containing compounds, which include not only hydrocarbons but also compounds with any number of other elements, including hydrogen (most compounds contain at least one carbon–hydrogen bond), nitrogen, oxygen, halogens, phosphorus, silicon, and sulfur. This branch of chemistry was originally limited to compounds produced by living organisms but has been broadened to include human-made substances such as plastics.

25802.

Which of the following forces is the most favourable for protein folding

Answer»

Answer: Hydrophobic interactions

Hydrophobic interactions aids in keeping protein stable and biologically active by allowing the protein to reduce its surface area.

25803.

The hyperpolarization phase of the action potential is due to:

Answer»

The prolonged opening of voltage-gated K+ channels  

25804.

Calcitonin is produced by

Answer»

Calcitonin is a 32 amino acid hormone secreted by the C-cells of the thyroid gland. 

Calcitonin has been preserved during the transition from ocean-based life to land dwellers and is phylogenetically older than parathyroid hormone.

C-cells of the thyroid gland.

25805.

Consider an object travelling in a semicircular path from point O to point P in 5 second, as shown in the figure. The average speed is

Answer»

1) Average velocity = Total Displacement

Total time

Here, Total displacement is equal to "10cm"

Because it is the shortest distance

And , Total time is "5 sec"

by putting this values in formula you will get

2cm/s

2) Average Speed = Total distance travelled

Total time taken

Total distance for a circle =2πr

but here , distance will be 2πr/2


And time will be 5 sec

By putting this values in the formula you will get

πr /5 = 2π

25806.

A ground to ground projectile projected at t=0 is at point A at t=T/3 is at point B at t=5T/6 and reaches the ground at t=T. The difference in heights between point A and B is

Answer»

Let heights difference between A and B = H

Given :-

t = T/3

t = 5T/6

As we know that, Time of Flight,

T = 2u Sinθ/g

u Sinθ = gT/2 ------(1)

For A,

h = usinθ t - 1/2 gt²

h = usinθ × T/3 - gT²/18

h = gT²/6 - gT²/18

h = 2gT²/18

For B,

h' = usinθ t - 1/gt²

h' = gT/2 × 5T/6 - 1/2 g 25T²/36

h' = 5gT²/12 - 25gT²/72

h' = 5gT²/72

Again,

H = h - h' = 2gT²/18 - 5gT²/72

H = (8gT² - 5gT²)/72

H = 3gT²/72

= gT²/24

25807.

Select the correct statement about salmeterol:A.    It is a long acting selective β2 agonist bronchodilatorB.    It is a bronchodilator with anti-inflammatory propertyC.    It is a β blocker that can be safely given to asthmaticsD.    It is an antihistaminic with mast cell stabilizing property

Answer»

A. It is a long acting selective β2 agonist bronchodilator.

25808.

Agar is obtained from

Answer»

Agar is contained in all algal species of the following orders: Gelidiales, Gracilariales, Ceramiales, and Rhodymeniales (Fredericq et al., 1996). However, the polysaccharide is traditionally obtained from red algae belonging to the genera Gracilaria, Ahnfeltia, Gelidium, and Pterocladiella.

25809.

which is most basic among c6h5ch2nh2,c6h5nhc2,c6h5nh2

Answer»

In C6H5CH2NH2, N is not directly attached to the benzene ring. Thus, its lone pair is not delocalized over the benzene ring. Therefore, the electrons on the N atom are more easily available for protonation in C6H5CH2NH2 than in C6H5NH2 i.e.C6H5CH2NH2 is more basic

25810.

What is the major role of ice cold calcium chloride in the preparation of competent cells?

Answer»

The process of calcium chloride heat-shock transformation encourages bacterial cells to uptake DNA from the surrounding environment.The ice-cold CaCl2 solution facilitates binding of DNA to the surface of the cell, which then enters the cell after a short period of heat- shock (3).

25811.

which enzyme is inducible by insulin?

Answer»

Insulin has several effects in liver which stimulate glycogen synthesis. First, it activates the enzyme hexokinase, which phosphorylates glucose, trapping it within the cell.

25812.

A M-cholinimimetic agent is: a) Carbachol b) Pilocarpine c) Acetylcholine d) Bethanechol 

Answer»

A M-cholinimimetic agent is Pilocarpine.

25813.

Which of the following cholinomimetics is a plant derivative with lower potency than nicotine but with a similar spectrum of action? a) Lobeline b) Pilocarpine c) Carbochol d) Acetylcholine

Answer»

Lobeline cholinomimetics is a plant derivative with lower potency than nicotine but with a similar spectrum of action.

25814.

Characteristics of pilocarpine include all of the following EXCEPT: a) It is a tertiary amine alkaloid b) It causes miosis and a decrease in intraocular pressure c) Causes a decrease in secretory and motor activity of gut d) It is useful in the treatment of glaucoma

Answer» c) Causes a decrease in secretory and motor activity of gut
25815.

The excessive stimulation of muscarinic receptors by pilocarpine and choline esters is blocked competitively by: a) Edrophonium b) Atropine c) Pralidoxime d) Echothiophate

Answer»

b)  Atropine

25816.

Which of the following cholinesterase inhibitors is irreversible? a) Physostigmine b) Edrophonium c) Neostigmine d) Isoflurophate 

Answer»

d) Isoflurophate 

25817.

Indicate a cholinomimetic agent, which is related to direct-acting drugs: a) Edrophonium b) Physostigmine c) Carbachol d) Isoflurophate

Answer»

c) Carbachol 

25818.

Indicate the location of M2 cholinoreceptor type: a) Heart b) Glands c) Smooth muscle d) Endothelium

Answer»

Indicate the location of M2 cholinoreceptor type Heart.

25819.

Сholinesterase inhibitors do not produce: a) Bradycardia, no change or modest fall in blood pressure b) Increased strength of muscle contraction, especially in muscles weakened by myasthenia gravis c) Miosis and reduction of intraocular pressure d) Dramatic hypertension and tachycardia

Answer»

d) Dramatic hypertension and tachycardia 

25820.

Isofluorophate increases all of the following effects except: a) Lacrimation b) Bronchodilation c) Muscle twitching d) Salivation

Answer»

b) Bronchodilation 

25821.

Which of the following cholinomimetics is a drug of choice for reversing the effects of nondepolarizing neuromuscular relaxants? a) Echothiophate b) Physostigmine c) Edrophonium d) Pilocarpine 

Answer»

c) Edrophonium 

25822.

Muscarinic receptors are located in:a) Autonomic ganglia b) Skeletal muscle neuromuscular junctions c) Autonomic effector cells d) Sensory carotid sinus baroreceptor zone  

Answer»

c) Autonomic effector cells

25823.

The symptoms of mushroom poisoning include all of the following EXCEPT: a) Salivation, lacrimation, nausea, vomiting b) Dryness of mouth, hyperpyrexia, hallucination c) Headache, abdominal colic d) Bradycardia, hypotension and shock

Answer»

b) Dryness of mouth, hyperpyrexia, hallucination

25824.

Which of the following cholinomimetics activates both muscarinic and nicotinic receptors? a) Lobeline b) Pilocarpine c) Nicotine d) Bethanechol 

Answer»

d) Bethanechol 

25825.

The value of m for which straight line `3x-2z+3=0=4x-3y+4z+1` is parallel to the plane `2x-y+mz-2=0` isA. `-2`B. `8`C. `-18`D. `11`

Answer» Correct Answer - A
Vertor `((3hati-2hatj+hatk)xx(4hati-3hatj+4hatk))` is perpendicular to
`2hati-hatj+mhatk` thus
`|{:(3,-2,1),(4,-3,4),(2,-1,m):}|=0` or `m=-2`
25826.

If `axx(bxxc)` is perpendicular to `(axxb)xxc`, we may haveA. `(veca.vecc)|vecb|^(2)=(veca.vecb)(vecb.vecc)`B. `veca.vecb=0`C. `veca.vecc=0`D. `vecb.vecc=0`

Answer» Correct Answer - A::C
`vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc` and
`(vecaxxvecb)xxvecc=-(vecc.vecb)veca+(veca.vecc)vecb`
We have been given
`(vecaxx(vecbxxvecc)).((vecaxxvecb)xxvecc)=0`
`because((veca.vecc)vecb-(veca.vecb)(vecc).((veca.vecc).(veca.vecc)vecb-(vecc.vecb)veca)=0`
or `(veca.vecc)^(2)}vecb}^(2)-(veca.vecc)(vecb-vecc)(veca.vecb)`
`-(veca.vecb(veca.vecc)(vecb.vecc)+(veca.vecb)(vecb.vecc)(vecc.veca)=0`
or `(veca.vecc)^(2)|vecb}^(2)=(veca.vecc)(veca.vecb)(vecb.vecc)` or `(veca.vecc)[(veca.vecc)(vecb.vecb)-(veca.vecb)(vecb.vecc)`
`veca.vecc=0` or `(veca.vec)|vecb|^(2)=(veca.vecb)(vecb.vecc)`
25827.

`int_(-1)^(1) (e^(|x|))/(1+a^(x))dx`A. `e`B. `2-e`C. `e-3`D. `e-1`

Answer» Correct Answer - D
`I=int_(-1)^(1)(e^(|x|))/(1+a^(x))dx`………..
`I=int_(-1)^(1)(e^(|0-x|)/(1+a^(-x))dx` (by `int_(a)^(b)f(a+b-x)dx)`
`I=int_(-1)^(1)(a^(x).e^(|x|))/(1+a^(x))dx`………(2)
(1) `+` (2)
`2I=int_(-1)^(1)e^(|x|)dx`
`2I=2int_(0)^(1)e^(|x|)dx`
`I=int_(0)^(1)dx=e-1`
25828.

The function `f(x)={ 1-2x+3x^2-4x^3; x!=-1, 1; x=-1}`discuss the continuity and differentiablilty at `x=-1`.A. continuous and derivable at `x=-1`B. Neither continuous nor derivable at `x=-1`C. Continuous but not derivasble at `x=-1`D. continuous but not derivable at `x=0`

Answer» Correct Answer - B
For `x!=-1`
`f(x)=1-2x+3x^(2)-4x^(3)+……….prop`
`f(x)k=(1+x)^(-2)=1/((1+x)^(2))`
LHL`=lim_(hrarr0)f(-1-h)=lim_(hrarr0)1/((1-1-h)^(2))rarroo`
`impliesf(x)` is not continuous at `x=-1`
so,`f(x)` is not derivative at `x=-1`
hecne `f(x)` is neither continuous nor derivable at `x=-1`
25829.

Statement 1: The range of `f(x)=sin^(2)x-sinx+1` is `[3/4,oo)`. Statemen 2: The range of `f(x)=x^(2)-x+1` is `[3/4,oo)AAxepsilonR`.A. Statement 1 is True, Statement 2 is True, Statement -2 is a correct explanation for Statement -1B. Statement -1 is True, Statement -2 is True, Statement -2 is NOT a correct explanation for Statemnt -1C. Statement -1 is True, Statement -2 is FalseD. Statement -1 is False, Statement -2 is True

Answer» Correct Answer - D
Statement 1: `f(x)=sin^(2)x-sinx+1`
`=(sinx-1/2)^(2)+3/4`
`f(x)` is min at `sin x=1/2impliesf_(min)=3/4`
`f(x)` is max when `sinx=-1impliesf_(max)=3`
`:.` range is `[3/4,3]`
hence Statement-1 is wrong. Statement -2 is correct.
25830.

For reaction `AtoB`, the rate constant `k_(1)=A_(1)e^(-Ea)//RT` and for the reaction `PtoQ`, the rate constant `k_(2)=A_(2)e^(-Ea_(2))//RT`. If `A_(1)=10^(8),andEa_(1)=600"cal/mol",Ea_(2)=1200"cal/mol"`, then the temperature at which `k_(1)=k_(2)` is (R=2cal/K-mol)A. 600 KB. `300xx4.606` KC. `(300)/(4.606)K`D. `(4.606)/(600)K`

Answer» Correct Answer - C
`A_(1)e-Ea_(1)//RT=A_(2)e-Ea_(2)//RT`
`(A_(2))/(A_(1))=e(Ea_(2)-Ea_(1))//RT`
`10^(2)="Exp"{(600)/(RT)}" R=2cal/K-mol"`
`2" ln "10=(600)/(2T)`
`T={(300)/(2xx2.303)}K" "]`
25831.

Figure shows `K_(alpha)`& `K_(beta)` X-rays along with continuous X-ray. Find the energy of `L_(alpha)` X-ray. (Use hc = 12420 evÅ)

Answer» Correct Answer - `6.21 KeV`
`=E _(K beta) -E_(K alpha)=12420 ((1)/(1)-(1)/(2))`
`=(12420)/(2)=6110 Ev=6.21 KeV`.
25832.

Two point charge +q and -q are fixed on diameterically opposite point on the unirom ring, such that -q is at bottom and is contact will a perfect insulator incline plane. Total mass is equal to m remains in equilibrium on the rough inclined plane in the presence of uniform vertical electric field. Then A. the value of friction force is `mg sin theta`B. the value of friction force is less than `mg sin theta`C. the value of electric field is `(mg)/(2q)`D. the value of electric field is `(mg tan theta)/(2q)`

Answer» Correct Answer - A::C
`f = mg sin theta`
and
`PE sin theta = mg sin theta R`
`q 2R E sin theta = mg sin theta R`
`E = (mg)/(2q)`.
25833.

There are two vessels. Each of them contains one moles of a monoatomic ideal gas. Initial volume of the gas in each vessel is `8.3 xx 10^(-3) m^(3) at 27^(@)C`. Equal amount of heat is supplied to each vessel. In one of the vessels, the volume of the gas is doubled without change in its internal energy, whereas the volume of the gas is held constant in the second vessel. The vessels are now connected to allow free mixing of the gas. Find the final temperature and pressure of the combined gas system.

Answer» Correct Answer - `00369.31`
For first vessel
`DeltaU=0`
`DeltaQ_(1)=DeltaW=nRTln((V_(f))/(V_(i)))=1.R.300.ln2`
`=(0.6931)xx300xxR=207.93R`
For second vessel `DeltaV=0`
`DeltaQ_(2)=DeltaU=nC_(v)Deltat=1 . 3/2 RDeltaT`
`DeltaQ_(1)=DeltaQ_(2)`
`207.93R= 3/2 RDeltaT`
`impliesDeltaT=138.62`
`T_(f)=300+138.62=438.62`
`U_("mix")=U_(1)+U_(2)`
`(n_(1)+n_(2))C_(V_("mix"))T_("mix")=_(1)C_(V_(1))T_(1)+n_(2)CV_(2)T_(2)`
`=T_("mix")=(T_(1)+T_(2))/(n_(1)+n_(2))=369.31K`
25834.

A particle of mass `m = 1 kg` excutes `SHM` about mean position `O` with angular frequency `omega = 1.0 rad//s` and total energy `2J`. `x` is positive if measured towards right from `O`. At `t = 0`, particle is at `O` and movel towards right. A. speed of particle is `sqrt(2)m//s` at `x = +- sqrt(2)m`B. Kinetic energy of the particle is `1J` at `x = +- sqrt(2)m`C. At `t = pi//6` sec. particle is at `x = -1 m`D. Kinetic energy is `1.5 J` at `x = +- 1m`

Answer» Correct Answer - A::B::D
`KE_(max)=(1)/(2)mv_(max)^(2)=TE`
`rArr v_(max)=sqrt((2xx2)/(1))=2 m//s`
amplitude `A = (v_(max))/(omega) = 2 m`
`x = A sin omega t = 2 sin t`
`v =2 cos t = sqrt(4 - x^(2))`
(A) `v = sqrt(2) m//s rArr x = pm sqrt(2) m`
(B) `KE = (1)/(2) mv_(2) rArr 1 = (1)/(2) xx 1 xx v_(2)`
`rArr v = sqrt(2) m//s`
`:. x = pm sqrt(2) m`
(C) at `t = pi//6 s, x =2 sin pi//6 = 1m`
(D) `KE = (3)/(2) rArr 1.5 =(1)/(2) xx mv_(2)`
`rArr v = sqrt(3) rArr x = pm 1 m`.
25835.

Action and reaction ……(a) Acts on same object (b) Acts on two different objects (c) Have resultant not zero (d) Acts on the same direction

Answer»

(b) Acts on two different objects

25836.

A wheel has angular acceleration of 3.0 rad/s2 and an initial angular speed of 2.00 rad/s. In a time of 2 seconds it has rotated through an angle of (in radian) ........(a) 10(b) 12(c) 4(d) 6

Answer»

Correct answer is (a) 10

25837.

If \( \hat{\imath}+\hat{\jmath}+\hat{k}, 2 \hat{\imath}+5 \hat{\jmath}, 3 \hat{\imath}+2 \hat{\jmath}-3 \hat{k} \) and \( \hat{\imath}-6 \hat{\jmath}-\hat{k} \) respectively are the position vectors of points \( A, B, C \) and \( D \), then find the angle between the straight lines \( A B \) and \( C D \). Find whether \( \overrightarrow{A B} \) and \( \overrightarrow{C D} \) are collinear or not.

Answer»

Position vectors of \(\vec A\,\&\,\vec B\) are \(\hat i+\hat j + \hat k\) and \(2\hat i+5\hat j\) respectively.

\(\therefore\) Direction vector of line AB is \(\vec a=(2\hat i+5\hat j)-(\hat i+\hat j+\hat k)\)

⇒ \(\vec a=\hat i+4\hat j-\hat k\)

Position vectors of \(\vec C\,\&\,\vec D\) are \(3\hat i+2\hat j - 3\hat k\) and \(\hat i-6\hat j - \hat k\) respectively.

\(\therefore\) Direction vector of line CD is

\(\vec b=(\hat i-6\hat j-\hat k)-(3\hat i+2\hat j-3\hat k)\) 

⇒ \(\vec b=-2\hat i-8\hat j+2\hat k\) 

Let angle between line AB and CD is θ.

\(\therefore\) cos θ = \(\frac{\vec a.\vec b}{|\vec a||\vec b|}\)

⇒ cos θ = \(\left|\frac{(\hat i+4\hat j-\hat k).(-2\hat i-8\hat j+2\hat k)}{\sqrt{1^2+4^2+(-1)^2}\sqrt{(-2)^2+(-8)^2+2^2}}\right|\)

\(=\left|\frac{-2-32-2}{\sqrt{18}\sqrt{72}}\right|\) 

\(=\left|\frac{-36}{\sqrt{18}\sqrt{18}.\sqrt4}\right|\)

\(=\frac{36}{18\times2}\) = 1 = cos 0°

\(\therefore\) θ = 0°

Hence, lines/vectors \(\vec {AB}\) and \(\vec {CD}\) are collinear.

25838.

Find the angle between the vectors \( \bar{p} \times \tilde{q} \) and \( \bar{q} \times \bar{p} \)

Answer»

∵ \(\overrightarrow{q}\times\overrightarrow{p}=-(\overrightarrow{p}\times\overrightarrow{q})\)

∴ Angle between \((\overrightarrow{p}\times\overrightarrow{q})\) & \((\overrightarrow{q}\times\overrightarrow{p})\) is 180°.

(Because both vectors have same magnitude but opposite directions)

25839.

Find the vector joining the points P(2, 3, 0) and Q(– 1, – 2, – 4) directed from P to Q.

Answer» Given P(2,3,0) and Q (-1,-2,-4)
P (2,3,0)
Q (-1,-2,-4)

PQ =(−1−2)i+(−2−3)j+(−4−0)k
=−3i−5j−4k

∴ Vector jonining P and Q given by
PQ  =−3i−5j−4k.
25840.

he is youngest boy in group.

Answer» He is the youngest in the group.

He word will be capital letter and after group word, use full stop.
25841.

Protoxylem is largely composed ofa) annular vesselsb) spiral vesselsc) parenchymad) all

Answer» Supplement

The xylem is the vascular tissue that is responsible for the conduction of water and nutrients from the roots up to the shoots and leaves. In contrast, the phloem is the other vascular tissue and is responsible for the translocation of metabolic products in various parts of the plant. The xylem may be categorized as primary xylem or secondary xylem. These two types of xylems are distinguished based on their origin. The primary xylem is produced from primary growth. The procambium gives rise to the primary xylem.

The primary xylem may be differentiated into two main parts: protoxylem and metaxylem. Both protoxylem and metaxylem contain tracheids, vessels, and parenchyma. They are produced from the procambium. Nevertheless, the protoxylem is the first xylem that develops (thus, the name). It consists of narrow vessels. The vessels are formed of cells that are relatively smaller than those of metaxylem. Nevertheless, the protoxylem has more parenchyma cells than metaxylem. In young plants, the protoxylem in stems has very little secondary wall material. In the stem, it is arranged towards the center whereas in the root, it is towards the periphery.

In a young stem, the protoxylem consists of tracheary element with annular or spiral thickenings, hence, capable of stretching or elongating (for stem growth). As the stem gets older, the stem stops elongating and the tracheary elements become more filled in.

Word origin: Greek prôtos (“first”) + xylem, from Greek xúlon (“wood”)

See also:
25842.

What do you mean by global warming?

Answer»

As more and more infrared radiations are trapped, the atmosphere becomes hotter and the global temperature rises up. This is known as global warming. There has been a marked increase in the levels of CO2 in the atmosphere due to severe deforestation and burning of fossil fuels.

25843.

Give two examples in which green chemistry has been applied.

Answer»

(1) Oxidative cracking process in the formation of ethylene is a significant step. 

(2) Fuel cells for cellular phones have been developed. This cell last for the full life time of the phone.

25844.

Carbon monoxide gas is more dangerous than carbon dioxide gas. Why?

Answer»

CO combines with haemoglobin to forms a complex entity, carboxyhaemoglobin which is about 300 times more stable than oxyhaemoglobin. In blood, when the concentration of carboxyhaemoglobin reaches 3 -4%, the oxygen-carrying capacity of the blood is significantly reduced. In other words, the body becomes oxygen starved. This results into headache, nervousness, cardiovascular disorder, weak eyesight etc.

25845.

Lignin deposition is found in

Answer»

The correct option is Parenchyma and Sclerenchyma

  • Lignin was found to be predominant in the sclerenchyma ring of the cortex at all the studied growth stages and cultivars, but it was also found in the epidermis, parenchyma and vascular tissue

 

sclereids and fibres
25846.

You have been transferred to Jaipur from Mumbai. You want to sell your house in Mumbai along with furniture. Prepare an advertisement for it for a classified column in not more than 50 words. 

Answer»

                                       TO-LET

 Available two bedroom plus dining hall, fully furnished set located at 81/454 Galaxy Apartments, Mahalaxmi, Mumbai with clear titles for sell. Separate kitchen and bathroom. 24 Hrs, water supply and car parking facility. A well equipped project in the heart of the city. Price negotiable .Contact - 77XXXXXXXX Raj 12/24 SFS, Mansarovar Jaipur. 

25847.

1. Write three major consequences of air pollution. 2. Write any two suitable methods to control air pollution.

Answer»

1.Three major consequences of air pollution:

  • We cannot get pure oxygen for inspire. 
  • Air pollution causes global warming. 
  • It leads to acid rain. 
  • It leads to diseases.

2. Two suitable methods to control air pollution:

  • Plant trees. 
  • Reduce the use of motor vehicles. 
  • Do not burn plastics.
25848.

How many bricks, each measuring 50 cm x 25 cm x 12 cm, will be needed to build a wall measuring 16 mx 12 mx 45 cm ?(a) 4860 (c) 6320(b) 5760(d) 8120

Answer»

b) 5760 

no. of bricks 

= volume of wall/volume of bricks

n = 1600*1200*45/50*25*45 

[16m = 1600cm and 12m = 1200cm]

n = 5760

25849.

Give an example of a compound in which hydrogen exists in (a) `+1`, (b) `-1`, ( c) zero oxidation state.

Answer» a. `H_(2)O` b. `NaH` c. `H_(2)`
25850.

Maximum oxidation state is shown by which pair elements :(1)  Np, Pu(2)  Cf, Bk(3)  Np,Pr(4) Ac, Th

Answer»

Correct option  (1)  Np, Pu

Explanation:

Np & Pu :  +3, + 4, + 5, + 6, + 7

Cf & Bk :  +3 & + 3, + 4, respectively

Np & Pr : +3

Ac & Th : +3 & + 4 respectivey