This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 25801. |
Organic chemistry |
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Answer» Organic chemistry is the study of the structure, properties, composition, reactions, and preparation of carbon-containing compounds, which include not only hydrocarbons but also compounds with any number of other elements, including hydrogen (most compounds contain at least one carbon–hydrogen bond), nitrogen, oxygen, halogens, phosphorus, silicon, and sulfur. This branch of chemistry was originally limited to compounds produced by living organisms but has been broadened to include human-made substances such as plastics. |
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| 25802. |
Which of the following forces is the most favourable for protein folding |
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Answer» Answer: Hydrophobic interactions Hydrophobic interactions aids in keeping protein stable and biologically active by allowing the protein to reduce its surface area. |
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| 25803. |
The hyperpolarization phase of the action potential is due to: |
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Answer» The prolonged opening of voltage-gated K+ channels |
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| 25804. |
Calcitonin is produced by |
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Answer» Calcitonin is a 32 amino acid hormone secreted by the C-cells of the thyroid gland. Calcitonin has been preserved during the transition from ocean-based life to land dwellers and is phylogenetically older than parathyroid hormone. C-cells of the thyroid gland. |
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| 25805. |
Consider an object travelling in a semicircular path from point O to point P in 5 second, as shown in the figure. The average speed is |
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Answer» 1) Average velocity = Total Displacement Total time Here, Total displacement is equal to "10cm" Because it is the shortest distance And , Total time is "5 sec" by putting this values in formula you will get 2cm/s 2) Average Speed = Total distance travelled Total time taken Total distance for a circle =2πr but here , distance will be 2πr/2
By putting this values in the formula you will get πr /5 = 2π |
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| 25806. |
A ground to ground projectile projected at t=0 is at point A at t=T/3 is at point B at t=5T/6 and reaches the ground at t=T. The difference in heights between point A and B is |
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Answer» Let heights difference between A and B = H Given :- t = T/3 t = 5T/6 As we know that, Time of Flight, T = 2u Sinθ/g u Sinθ = gT/2 ------(1) For A, h = usinθ t - 1/2 gt² h = usinθ × T/3 - gT²/18 h = gT²/6 - gT²/18 h = 2gT²/18 For B, h' = usinθ t - 1/gt² h' = gT/2 × 5T/6 - 1/2 g 25T²/36 h' = 5gT²/12 - 25gT²/72 h' = 5gT²/72 Again, H = h - h' = 2gT²/18 - 5gT²/72 H = (8gT² - 5gT²)/72 H = 3gT²/72 H = gT²/24 |
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| 25807. |
Select the correct statement about salmeterol:A. It is a long acting selective β2 agonist bronchodilatorB. It is a bronchodilator with anti-inflammatory propertyC. It is a β blocker that can be safely given to asthmaticsD. It is an antihistaminic with mast cell stabilizing property |
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Answer» A. It is a long acting selective β2 agonist bronchodilator. |
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| 25808. |
Agar is obtained from |
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Answer» Agar is contained in all algal species of the following orders: Gelidiales, Gracilariales, Ceramiales, and Rhodymeniales (Fredericq et al., 1996). However, the polysaccharide is traditionally obtained from red algae belonging to the genera Gracilaria, Ahnfeltia, Gelidium, and Pterocladiella. |
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| 25809. |
which is most basic among c6h5ch2nh2,c6h5nhc2,c6h5nh2 |
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Answer» In C6H5CH2NH2, N is not directly attached to the benzene ring. Thus, its lone pair is not delocalized over the benzene ring. Therefore, the electrons on the N atom are more easily available for protonation in C6H5CH2NH2 than in C6H5NH2 i.e.C6H5CH2NH2 is more basic |
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| 25810. |
What is the major role of ice cold calcium chloride in the preparation of competent cells? |
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Answer» The process of calcium chloride heat-shock transformation encourages bacterial cells to uptake DNA from the surrounding environment.The ice-cold CaCl2 solution facilitates binding of DNA to the surface of the cell, which then enters the cell after a short period of heat- shock (3). |
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| 25811. |
which enzyme is inducible by insulin? |
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Answer» Insulin has several effects in liver which stimulate glycogen synthesis. First, it activates the enzyme hexokinase, which phosphorylates glucose, trapping it within the cell. |
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| 25812. |
A M-cholinimimetic agent is: a) Carbachol b) Pilocarpine c) Acetylcholine d) Bethanechol |
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Answer» A M-cholinimimetic agent is Pilocarpine. |
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| 25813. |
Which of the following cholinomimetics is a plant derivative with lower potency than nicotine but with a similar spectrum of action? a) Lobeline b) Pilocarpine c) Carbochol d) Acetylcholine |
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Answer» Lobeline cholinomimetics is a plant derivative with lower potency than nicotine but with a similar spectrum of action. |
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| 25814. |
Characteristics of pilocarpine include all of the following EXCEPT: a) It is a tertiary amine alkaloid b) It causes miosis and a decrease in intraocular pressure c) Causes a decrease in secretory and motor activity of gut d) It is useful in the treatment of glaucoma |
| Answer» c) Causes a decrease in secretory and motor activity of gut | |
| 25815. |
The excessive stimulation of muscarinic receptors by pilocarpine and choline esters is blocked competitively by: a) Edrophonium b) Atropine c) Pralidoxime d) Echothiophate |
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Answer» b) Atropine |
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| 25816. |
Which of the following cholinesterase inhibitors is irreversible? a) Physostigmine b) Edrophonium c) Neostigmine d) Isoflurophate |
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Answer» d) Isoflurophate |
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| 25817. |
Indicate a cholinomimetic agent, which is related to direct-acting drugs: a) Edrophonium b) Physostigmine c) Carbachol d) Isoflurophate |
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Answer» c) Carbachol |
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| 25818. |
Indicate the location of M2 cholinoreceptor type: a) Heart b) Glands c) Smooth muscle d) Endothelium |
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Answer» Indicate the location of M2 cholinoreceptor type Heart. |
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| 25819. |
Сholinesterase inhibitors do not produce: a) Bradycardia, no change or modest fall in blood pressure b) Increased strength of muscle contraction, especially in muscles weakened by myasthenia gravis c) Miosis and reduction of intraocular pressure d) Dramatic hypertension and tachycardia |
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Answer» d) Dramatic hypertension and tachycardia |
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| 25820. |
Isofluorophate increases all of the following effects except: a) Lacrimation b) Bronchodilation c) Muscle twitching d) Salivation |
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Answer» b) Bronchodilation |
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| 25821. |
Which of the following cholinomimetics is a drug of choice for reversing the effects of nondepolarizing neuromuscular relaxants? a) Echothiophate b) Physostigmine c) Edrophonium d) Pilocarpine |
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Answer» c) Edrophonium |
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| 25822. |
Muscarinic receptors are located in:a) Autonomic ganglia b) Skeletal muscle neuromuscular junctions c) Autonomic effector cells d) Sensory carotid sinus baroreceptor zone |
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Answer» c) Autonomic effector cells |
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| 25823. |
The symptoms of mushroom poisoning include all of the following EXCEPT: a) Salivation, lacrimation, nausea, vomiting b) Dryness of mouth, hyperpyrexia, hallucination c) Headache, abdominal colic d) Bradycardia, hypotension and shock |
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Answer» b) Dryness of mouth, hyperpyrexia, hallucination |
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| 25824. |
Which of the following cholinomimetics activates both muscarinic and nicotinic receptors? a) Lobeline b) Pilocarpine c) Nicotine d) Bethanechol |
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Answer» d) Bethanechol |
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| 25825. |
The value of m for which straight line `3x-2z+3=0=4x-3y+4z+1` is parallel to the plane `2x-y+mz-2=0` isA. `-2`B. `8`C. `-18`D. `11` |
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Answer» Correct Answer - A Vertor `((3hati-2hatj+hatk)xx(4hati-3hatj+4hatk))` is perpendicular to `2hati-hatj+mhatk` thus `|{:(3,-2,1),(4,-3,4),(2,-1,m):}|=0` or `m=-2` |
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| 25826. |
If `axx(bxxc)` is perpendicular to `(axxb)xxc`, we may haveA. `(veca.vecc)|vecb|^(2)=(veca.vecb)(vecb.vecc)`B. `veca.vecb=0`C. `veca.vecc=0`D. `vecb.vecc=0` |
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Answer» Correct Answer - A::C `vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc` and `(vecaxxvecb)xxvecc=-(vecc.vecb)veca+(veca.vecc)vecb` We have been given `(vecaxx(vecbxxvecc)).((vecaxxvecb)xxvecc)=0` `because((veca.vecc)vecb-(veca.vecb)(vecc).((veca.vecc).(veca.vecc)vecb-(vecc.vecb)veca)=0` or `(veca.vecc)^(2)}vecb}^(2)-(veca.vecc)(vecb-vecc)(veca.vecb)` `-(veca.vecb(veca.vecc)(vecb.vecc)+(veca.vecb)(vecb.vecc)(vecc.veca)=0` or `(veca.vecc)^(2)|vecb}^(2)=(veca.vecc)(veca.vecb)(vecb.vecc)` or `(veca.vecc)[(veca.vecc)(vecb.vecb)-(veca.vecb)(vecb.vecc)` `veca.vecc=0` or `(veca.vec)|vecb|^(2)=(veca.vecb)(vecb.vecc)` |
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| 25827. |
`int_(-1)^(1) (e^(|x|))/(1+a^(x))dx`A. `e`B. `2-e`C. `e-3`D. `e-1` |
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Answer» Correct Answer - D `I=int_(-1)^(1)(e^(|x|))/(1+a^(x))dx`……….. `I=int_(-1)^(1)(e^(|0-x|)/(1+a^(-x))dx` (by `int_(a)^(b)f(a+b-x)dx)` `I=int_(-1)^(1)(a^(x).e^(|x|))/(1+a^(x))dx`………(2) (1) `+` (2) `2I=int_(-1)^(1)e^(|x|)dx` `2I=2int_(0)^(1)e^(|x|)dx` `I=int_(0)^(1)dx=e-1` |
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| 25828. |
The function `f(x)={ 1-2x+3x^2-4x^3; x!=-1, 1; x=-1}`discuss the continuity and differentiablilty at `x=-1`.A. continuous and derivable at `x=-1`B. Neither continuous nor derivable at `x=-1`C. Continuous but not derivasble at `x=-1`D. continuous but not derivable at `x=0` |
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Answer» Correct Answer - B For `x!=-1` `f(x)=1-2x+3x^(2)-4x^(3)+……….prop` `f(x)k=(1+x)^(-2)=1/((1+x)^(2))` LHL`=lim_(hrarr0)f(-1-h)=lim_(hrarr0)1/((1-1-h)^(2))rarroo` `impliesf(x)` is not continuous at `x=-1` so,`f(x)` is not derivative at `x=-1` hecne `f(x)` is neither continuous nor derivable at `x=-1` |
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| 25829. |
Statement 1: The range of `f(x)=sin^(2)x-sinx+1` is `[3/4,oo)`. Statemen 2: The range of `f(x)=x^(2)-x+1` is `[3/4,oo)AAxepsilonR`.A. Statement 1 is True, Statement 2 is True, Statement -2 is a correct explanation for Statement -1B. Statement -1 is True, Statement -2 is True, Statement -2 is NOT a correct explanation for Statemnt -1C. Statement -1 is True, Statement -2 is FalseD. Statement -1 is False, Statement -2 is True |
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Answer» Correct Answer - D Statement 1: `f(x)=sin^(2)x-sinx+1` `=(sinx-1/2)^(2)+3/4` `f(x)` is min at `sin x=1/2impliesf_(min)=3/4` `f(x)` is max when `sinx=-1impliesf_(max)=3` `:.` range is `[3/4,3]` hence Statement-1 is wrong. Statement -2 is correct. |
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| 25830. |
For reaction `AtoB`, the rate constant `k_(1)=A_(1)e^(-Ea)//RT` and for the reaction `PtoQ`, the rate constant `k_(2)=A_(2)e^(-Ea_(2))//RT`. If `A_(1)=10^(8),andEa_(1)=600"cal/mol",Ea_(2)=1200"cal/mol"`, then the temperature at which `k_(1)=k_(2)` is (R=2cal/K-mol)A. 600 KB. `300xx4.606` KC. `(300)/(4.606)K`D. `(4.606)/(600)K` |
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Answer» Correct Answer - C `A_(1)e-Ea_(1)//RT=A_(2)e-Ea_(2)//RT` `(A_(2))/(A_(1))=e(Ea_(2)-Ea_(1))//RT` `10^(2)="Exp"{(600)/(RT)}" R=2cal/K-mol"` `2" ln "10=(600)/(2T)` `T={(300)/(2xx2.303)}K" "]` |
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| 25831. |
Figure shows `K_(alpha)`& `K_(beta)` X-rays along with continuous X-ray. Find the energy of `L_(alpha)` X-ray. (Use hc = 12420 evÅ) |
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Answer» Correct Answer - `6.21 KeV` `=E _(K beta) -E_(K alpha)=12420 ((1)/(1)-(1)/(2))` `=(12420)/(2)=6110 Ev=6.21 KeV`. |
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| 25832. |
Two point charge +q and -q are fixed on diameterically opposite point on the unirom ring, such that -q is at bottom and is contact will a perfect insulator incline plane. Total mass is equal to m remains in equilibrium on the rough inclined plane in the presence of uniform vertical electric field. Then A. the value of friction force is `mg sin theta`B. the value of friction force is less than `mg sin theta`C. the value of electric field is `(mg)/(2q)`D. the value of electric field is `(mg tan theta)/(2q)` |
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Answer» Correct Answer - A::C `f = mg sin theta` and `PE sin theta = mg sin theta R` `q 2R E sin theta = mg sin theta R` `E = (mg)/(2q)`. |
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| 25833. |
There are two vessels. Each of them contains one moles of a monoatomic ideal gas. Initial volume of the gas in each vessel is `8.3 xx 10^(-3) m^(3) at 27^(@)C`. Equal amount of heat is supplied to each vessel. In one of the vessels, the volume of the gas is doubled without change in its internal energy, whereas the volume of the gas is held constant in the second vessel. The vessels are now connected to allow free mixing of the gas. Find the final temperature and pressure of the combined gas system. |
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Answer» Correct Answer - `00369.31` For first vessel `DeltaU=0` `DeltaQ_(1)=DeltaW=nRTln((V_(f))/(V_(i)))=1.R.300.ln2` `=(0.6931)xx300xxR=207.93R` For second vessel `DeltaV=0` `DeltaQ_(2)=DeltaU=nC_(v)Deltat=1 . 3/2 RDeltaT` `DeltaQ_(1)=DeltaQ_(2)` `207.93R= 3/2 RDeltaT` `impliesDeltaT=138.62` `T_(f)=300+138.62=438.62` `U_("mix")=U_(1)+U_(2)` `(n_(1)+n_(2))C_(V_("mix"))T_("mix")=_(1)C_(V_(1))T_(1)+n_(2)CV_(2)T_(2)` `=T_("mix")=(T_(1)+T_(2))/(n_(1)+n_(2))=369.31K` |
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| 25834. |
A particle of mass `m = 1 kg` excutes `SHM` about mean position `O` with angular frequency `omega = 1.0 rad//s` and total energy `2J`. `x` is positive if measured towards right from `O`. At `t = 0`, particle is at `O` and movel towards right. A. speed of particle is `sqrt(2)m//s` at `x = +- sqrt(2)m`B. Kinetic energy of the particle is `1J` at `x = +- sqrt(2)m`C. At `t = pi//6` sec. particle is at `x = -1 m`D. Kinetic energy is `1.5 J` at `x = +- 1m` |
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Answer» Correct Answer - A::B::D `KE_(max)=(1)/(2)mv_(max)^(2)=TE` `rArr v_(max)=sqrt((2xx2)/(1))=2 m//s` amplitude `A = (v_(max))/(omega) = 2 m` `x = A sin omega t = 2 sin t` `v =2 cos t = sqrt(4 - x^(2))` (A) `v = sqrt(2) m//s rArr x = pm sqrt(2) m` (B) `KE = (1)/(2) mv_(2) rArr 1 = (1)/(2) xx 1 xx v_(2)` `rArr v = sqrt(2) m//s` `:. x = pm sqrt(2) m` (C) at `t = pi//6 s, x =2 sin pi//6 = 1m` (D) `KE = (3)/(2) rArr 1.5 =(1)/(2) xx mv_(2)` `rArr v = sqrt(3) rArr x = pm 1 m`. |
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| 25835. |
Action and reaction ……(a) Acts on same object (b) Acts on two different objects (c) Have resultant not zero (d) Acts on the same direction |
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Answer» (b) Acts on two different objects |
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| 25836. |
A wheel has angular acceleration of 3.0 rad/s2 and an initial angular speed of 2.00 rad/s. In a time of 2 seconds it has rotated through an angle of (in radian) ........(a) 10(b) 12(c) 4(d) 6 |
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Answer» Correct answer is (a) 10 |
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| 25837. |
If \( \hat{\imath}+\hat{\jmath}+\hat{k}, 2 \hat{\imath}+5 \hat{\jmath}, 3 \hat{\imath}+2 \hat{\jmath}-3 \hat{k} \) and \( \hat{\imath}-6 \hat{\jmath}-\hat{k} \) respectively are the position vectors of points \( A, B, C \) and \( D \), then find the angle between the straight lines \( A B \) and \( C D \). Find whether \( \overrightarrow{A B} \) and \( \overrightarrow{C D} \) are collinear or not. |
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Answer» Position vectors of \(\vec A\,\&\,\vec B\) are \(\hat i+\hat j + \hat k\) and \(2\hat i+5\hat j\) respectively. \(\therefore\) Direction vector of line AB is \(\vec a=(2\hat i+5\hat j)-(\hat i+\hat j+\hat k)\) ⇒ \(\vec a=\hat i+4\hat j-\hat k\) Position vectors of \(\vec C\,\&\,\vec D\) are \(3\hat i+2\hat j - 3\hat k\) and \(\hat i-6\hat j - \hat k\) respectively. \(\therefore\) Direction vector of line CD is \(\vec b=(\hat i-6\hat j-\hat k)-(3\hat i+2\hat j-3\hat k)\) ⇒ \(\vec b=-2\hat i-8\hat j+2\hat k\) Let angle between line AB and CD is θ. \(\therefore\) cos θ = \(\frac{\vec a.\vec b}{|\vec a||\vec b|}\) ⇒ cos θ = \(\left|\frac{(\hat i+4\hat j-\hat k).(-2\hat i-8\hat j+2\hat k)}{\sqrt{1^2+4^2+(-1)^2}\sqrt{(-2)^2+(-8)^2+2^2}}\right|\) \(=\left|\frac{-2-32-2}{\sqrt{18}\sqrt{72}}\right|\) \(=\left|\frac{-36}{\sqrt{18}\sqrt{18}.\sqrt4}\right|\) \(=\frac{36}{18\times2}\) = 1 = cos 0° \(\therefore\) θ = 0° Hence, lines/vectors \(\vec {AB}\) and \(\vec {CD}\) are collinear. |
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| 25838. |
Find the angle between the vectors \( \bar{p} \times \tilde{q} \) and \( \bar{q} \times \bar{p} \) |
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Answer» ∵ \(\overrightarrow{q}\times\overrightarrow{p}=-(\overrightarrow{p}\times\overrightarrow{q})\) ∴ Angle between \((\overrightarrow{p}\times\overrightarrow{q})\) & \((\overrightarrow{q}\times\overrightarrow{p})\) is 180°. (Because both vectors have same magnitude but opposite directions) |
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| 25839. |
Find the vector joining the points P(2, 3, 0) and Q(– 1, – 2, – 4) directed from P to Q. |
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Answer» Given P(2,3,0) and Q (-1,-2,-4) P (2,3,0) Q (-1,-2,-4) PQ =(−1−2)i+(−2−3)j+(−4−0)k =−3i−5j−4k ∴ Vector jonining P and Q given by PQ =−3i−5j−4k. |
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| 25840. |
he is youngest boy in group. |
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Answer» He is the youngest in the group. He word will be capital letter and after group word, use full stop. |
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| 25841. |
Protoxylem is largely composed ofa) annular vesselsb) spiral vesselsc) parenchymad) all |
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Answer» Supplement The xylem is the vascular tissue that is responsible for the conduction of water and nutrients from the roots up to the shoots and leaves. In contrast, the phloem is the other vascular tissue and is responsible for the translocation of metabolic products in various parts of the plant. The xylem may be categorized as primary xylem or secondary xylem. These two types of xylems are distinguished based on their origin. The primary xylem is produced from primary growth. The procambium gives rise to the primary xylem. The primary xylem may be differentiated into two main parts: protoxylem and metaxylem. Both protoxylem and metaxylem contain tracheids, vessels, and parenchyma. They are produced from the procambium. Nevertheless, the protoxylem is the first xylem that develops (thus, the name). It consists of narrow vessels. The vessels are formed of cells that are relatively smaller than those of metaxylem. Nevertheless, the protoxylem has more parenchyma cells than metaxylem. In young plants, the protoxylem in stems has very little secondary wall material. In the stem, it is arranged towards the center whereas in the root, it is towards the periphery. In a young stem, the protoxylem consists of tracheary element with annular or spiral thickenings, hence, capable of stretching or elongating (for stem growth). As the stem gets older, the stem stops elongating and the tracheary elements become more filled in. Word origin: Greek prôtos (“first”) + xylem, from Greek xúlon (“wood”) See also: |
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| 25842. |
What do you mean by global warming? |
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Answer» As more and more infrared radiations are trapped, the atmosphere becomes hotter and the global temperature rises up. This is known as global warming. There has been a marked increase in the levels of CO2 in the atmosphere due to severe deforestation and burning of fossil fuels. |
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| 25843. |
Give two examples in which green chemistry has been applied. |
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Answer» (1) Oxidative cracking process in the formation of ethylene is a significant step. (2) Fuel cells for cellular phones have been developed. This cell last for the full life time of the phone. |
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| 25844. |
Carbon monoxide gas is more dangerous than carbon dioxide gas. Why? |
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Answer» CO combines with haemoglobin to forms a complex entity, carboxyhaemoglobin which is about 300 times more stable than oxyhaemoglobin. In blood, when the concentration of carboxyhaemoglobin reaches 3 -4%, the oxygen-carrying capacity of the blood is significantly reduced. In other words, the body becomes oxygen starved. This results into headache, nervousness, cardiovascular disorder, weak eyesight etc. |
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| 25845. |
Lignin deposition is found in |
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Answer» The correct option is Parenchyma and Sclerenchyma
sclereids and fibres |
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| 25846. |
You have been transferred to Jaipur from Mumbai. You want to sell your house in Mumbai along with furniture. Prepare an advertisement for it for a classified column in not more than 50 words. |
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Answer» TO-LET Available two bedroom plus dining hall, fully furnished set located at 81/454 Galaxy Apartments, Mahalaxmi, Mumbai with clear titles for sell. Separate kitchen and bathroom. 24 Hrs, water supply and car parking facility. A well equipped project in the heart of the city. Price negotiable .Contact - 77XXXXXXXX Raj 12/24 SFS, Mansarovar Jaipur. |
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| 25847. |
1. Write three major consequences of air pollution. 2. Write any two suitable methods to control air pollution. |
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Answer» 1.Three major consequences of air pollution:
2. Two suitable methods to control air pollution:
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| 25848. |
How many bricks, each measuring 50 cm x 25 cm x 12 cm, will be needed to build a wall measuring 16 mx 12 mx 45 cm ?(a) 4860 (c) 6320(b) 5760(d) 8120 |
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Answer» b) 5760 no. of bricks = volume of wall/volume of bricks n = 1600*1200*45/50*25*45 [16m = 1600cm and 12m = 1200cm] n = 5760 |
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| 25849. |
Give an example of a compound in which hydrogen exists in (a) `+1`, (b) `-1`, ( c) zero oxidation state. |
| Answer» a. `H_(2)O` b. `NaH` c. `H_(2)` | |
| 25850. |
Maximum oxidation state is shown by which pair elements :(1) Np, Pu(2) Cf, Bk(3) Np,Pr(4) Ac, Th |
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Answer» Correct option (1) Np, Pu Explanation: Np & Pu : +3, + 4, + 5, + 6, + 7 Cf & Bk : +3 & + 3, + 4, respectively Np & Pr : +3 Ac & Th : +3 & + 4 respectivey |
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