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Statement 1: The range of `f(x)=sin^(2)x-sinx+1` is `[3/4,oo)`. Statemen 2: The range of `f(x)=x^(2)-x+1` is `[3/4,oo)AAxepsilonR`.A. Statement 1 is True, Statement 2 is True, Statement -2 is a correct explanation for Statement -1B. Statement -1 is True, Statement -2 is True, Statement -2 is NOT a correct explanation for Statemnt -1C. Statement -1 is True, Statement -2 is FalseD. Statement -1 is False, Statement -2 is True |
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Answer» Correct Answer - D Statement 1: `f(x)=sin^(2)x-sinx+1` `=(sinx-1/2)^(2)+3/4` `f(x)` is min at `sin x=1/2impliesf_(min)=3/4` `f(x)` is max when `sinx=-1impliesf_(max)=3` `:.` range is `[3/4,3]` hence Statement-1 is wrong. Statement -2 is correct. |
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