Explore topic-wise InterviewSolutions in .

Correct option is 

1. (i)-(D), (ii) -(C), (iii)-(B), (iv)-(A)

Correct option is 

(d) A-iv,B-i,C-ii D-iii

Minimum amount that can be transferred through RTGS is Rs 200,000.

Correct option: (c) actual

Correct answer is c. National Electronic Fund Transfer

Correct option: c) National Electronic Fund Transfer

A Secretary has to be responsible person to whom an executive can delegate his/her routine duties, entrust confidential matters with full confidence to act on his/her behalf whenever necessary .

Let A(2, 4, 5), B(3, 5, –4). xy-plane divides bar AB in the ratio = 5 : –(–4) = 5 : 4.

Given - 

LCM = 1800

ratio between the number = 3 : 4 : 5

Solution - 

Let the numbers be 3x, 4x, and 5x respectively.

⇒ LCM (3x, 4x, 5x) = 1800

⇒ 60x = 1800

⇒ x = 30

⇒ second number = 4x = 120

∴ second number = 120.

Given: 

Three numbers are 108, x, and 144, 

HCF of these numbers is 12.

Concept:

H.C.F. of two or more factors is the greatest factor that divides each of them exactly.

Calculation: 

Factor of 108 = 2 × 2 × 3 × 3 × 3

Factor of 144 = 2 × 2 × 2 × 2 × 3 × 3

By taking option (c),

Factor of 72 = 2 × 2 × 2 × 3 × 3

If we take the value of x is 72, then HCF of the given numbers becomes 36

∴ The value of x will not be 72.

Largest number which divides 438 and 606, leaving remainder 6 in each case is actually 

the largest number which divide 432 (438 – 6) and 600 (606 – 6). 

The largest number which divides 432 and 600 is HCF (432, 600). 

Now, write 432 and 600 into prime factorization form, 

432 = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 2⁴ × 3³ . 

600 = 6 × 10² = 2× 3 × 2 × 5 × 2 × 5 = 2³ × 3 × 5² . 

HCF (432, 600) = product of smallest power of each common factor in the prime 

factorization of numbers = 2³ × 3 = 8 × 3 = 24. 

Thus, the largest number which divides 438 and 606, leaving remainder 6 is 24.

Given:

48 Persons make a bridge in 15 days working 6 hours a day.

Concept Used:

M₁ × H₁ × D₁ = M₂ × H₂ × D₂

Where,

M = No of persons

H = Hours of working in a day

D = No of days to complete the work

Calculation:

M₁ × H₁ × D₁ = M₂ × H₂ × D₂

⇒ 48 × 15 × 6 = 30 × 8 × D₂

⇒ D₂ = 18 days

∴ 30 men working 8 hours a day can complete in 18 days.

Given:

The given number = 1936

Concept:

Calculation skills trick

Calculation:

Step(1):

The unit digit in this number is 6, which can be a unit digit of its square root number such as 4 or 6. Because 4 x 4 is 16 and 6 x 6 is 36.

Step(2):

Now let us consider the first two digits that is 19 which comes between the squares of 4 and 5 because 16 < 19 < 25

Step(3):

We can assume that the ten’s digit of the square root of 1936 is the lowest among the two numbers i.e. 4

Step(4):

Now, we need to find among 44 and 46 which is the square root of 1936.

Step(5):

Since the ten’s digit is 4 and the next number is 5, we need to multiply both the numbers like 4 x 5 = 20 and since 20 is greater than 19.

Step(6):

Square root of 1936 will be the smaller number among 44 and 46 i.e. 44.

∴ √1936 = 44

Given:

The given number = 2401

Concept:

Calculation skills trick

Calculation:

Step(1):

The unit digit in this number is 1, which can be a unit digit of its square root number such as 1 or 9. Because 1 x 1 is 1 and 9 x 9 is 81.

Step(2):

Now let us consider the first two digits that is 24 which comes between the squares of 4 and 5 because 16 < 24 < 25

Step(3):

We can assume that the ten’s digit of the square root of 2401 is the lowest among the two numbers i.e. 4

Step(4):

Now, we need to find among 41 and 49 which is the square root of 2401.

Step(5):

Since the ten’s digit is 4 and the next number is 5, we need to multiply both the numbers like 4 x 5 = 20 and since 20 is smaller than 24.

Step(6):

Square root of 2401 will be the greater number among 41 and 49 i.e. 49.

∴ √2401 = 49

Let z=r(cosθ+isinθ)

arg(z)=θ<0

−z=−r(cosθ+isinθ)

=r(cos(π+θ)+isin(π+θ))

arg(−z)=π+θ

∴ arg(−z)−arg(z)=π+θ−θ=π

The points are awarded by the following method. First, Second and Third position holders get 5-3-1 points respectively and in Relay races 16-6-2 points are awarded to first, second and third position holders.

Let z = a+ib
|z+1| = z+2(1+i)
=> |(a+ib) + 1|                                     =        a+ib+2+2i
=> |(a+1) + ib|                                     =        a+2 + i(b+2)
=> root[(a+1)² +b²]                        =        (a+2) + i(b+2)

comparing imaginary parts 
b+2                                                     =         0
=> b                                                    =         -2
comparing real parts
root[(a+1)² + b²]                            =        (a+2)
=> root(a²+1+2a +b²)                    =        a+2
putting b=-2 here 
=> root( a²+1+2a + 4)                      =         a+2
=> root(a²+2a + 5)                           =         a+2
squaring both sides
=> a²+2a + 5                                    =         a²+4+4a
​=> 1                                                    =         2a
=> a                                                    =         1/2

W.K.T -> z= a+ib
substituting a=1/2 and b=-2 in z= a+ib
​we get,  z = 1/2 - 2i 

Rules For Swimming:

1. The swimmer who obstructs any other swimmer during the swim shall be disqualified.
2. If a foul endangers the chance of success of a swimmer, the judges shall have the right to allow him to compete in the next round. If a foul occurs in the finals, the referee can allow him to swim again.
3. On return a competitor shall touch the end of the pool or end of the track with one or both hands. Diving from the bottom of the pool is not allowed.
4. A swimmer who stands on the both shall not be declared disqualified, but he shall not move.
5. Only the swimmer who covers the entire course shall be declared the winner.
6. In relay race, the competitor whose feet have lost touch with the starting block before his or her partner, going ahead of him or her touches.

Basket-Ball court is 28 metres in length and 15 metres in breadth.

There are twelve players in a Basket-ball game. Out of which 5 are taking part and seven are the substitutes.

(1+i)⁶ⁿ+(1-i)⁶ⁿ

= (1+2i+i²)³ⁿ+(1-2i+i²)³ⁿ

= (1+2i-1)³ⁿ+(1-2i-1)³ⁿ

= (+2i)³ⁿ+(-2i)³ⁿ

 = +(2i)³ⁿ-(2i)³ⁿ

= 0

p(x) = kx² + 2x – 5

If (x – 1) is a factor, then p(1) = 0

p(1) = k(l)² + 2 x 1 – 5

= k + 2 – 5 = k – 3

k – 3 = 0 k = 3

The correct option is (C) 2 cos A cos B

Explanation:

cos (A + B) + cos (A – B)

⇒ cosAcosB – sinAsinB + cosAcosB + sinAsinB 

⇒ 2cosAcosB

The correct option is (D) sin B

Explanation:

Given A + B + C = 90° 

cos (A + C) ⇒cos (90 – B) {∵ cos (90 – θ) = sinθ} 

⇒ sinB

Angle subtended by the diameter of a circle at a point on the circumference is Right angle (90°)

Given equation x² – 9x = 0

⇒ x(x – 9) = 0 

⇒ x = 0 , x = 9

Given equation 4x² – x + 1 = 0

for given equation D = b² – 4ac

D = (– 1)² – 4(4) (1)

= 1 – 16 = – 15

∵ D < 0

∴ roots are imaginary.

If the coordinate of any point is (0, 5) then the point will lie on the y = axis axis.

The correct option is (C) 75°

Explanation:

Δ SQR ~ Δ RQP

∠ SQR = ∠ RQP = 51° 

∠ QRS =∠ QPR = 180° – (102 + 51°) = 27° 

∠ RSQ = ∠ PRQ = 102° 

Now ∠ PRS =∠ PRQ – ∠ SRQ 

= 102° – 27° = 75

sin²θ + cosec²θ + 2sinθ + cosecθ + cos²θ + sec²θ + 2cosθ secθ. 

1 + cosec²θ + 2 + 2 + sec²θ. 

1 + 1 + cot²θ + 2 + 2 + 1 + tan²θ 

7 + tan²θ + cot²θ.

The tax which is levied on a person’s income received from all sources is called Income tax

Correct answer is: (c) x = \(\cfrac{ay}{a+b}\)

AE/AC=DE/BC = a/a + b = x/y

X=ay/(a + b)

Correct answer is: (d) (3,5)

(2x4+1x1)/3 , (2x6+1x3)/3 =(3,5)

(b) are disturbing

Correct answer is

a. group of numbers or letters used by the post office to identify a region

b. Zoom Bar

You can change the magnification of the page (i.e., make it bigger or smaller) using Zoom Bar option.

d. External motivation

Sunil goes to the gym daily for 4 hours and does weightlifting as he wants to win the body-building competition. This is External motivation.

(a) Internal

Prakash goes to the gym and does weightlifting to stay healthy and fit. Internal type of motivation he has.

(c)    wants

1. Father suggests that they see the land.

2. Grandfather does not want to see the land because it is inherited and is his prized possession.

Given:

The expression is (1!)¹ × (2!)² × (3!)³ × (4!)⁴ × … × (15!)¹⁵

Concept used:

To find the number of zeroes at the end of the product, we need to calculate the number of 2’s and number 5’s or number of pairs of 2 and 5.

2 × 5 = 10 ⇒ Number of zeroes = 1 (number of pair = 1)

The number of pairs of 2 and 5 is same as the number of zeroes at the end of the product

Calculation:

(1!)¹ × (2!)² × (3!)³ × (4!)⁴ × … × (15!)¹⁵

In the above expression, number of 2’s is more than number of 5’s. So we need to calculate the number of 5’s only

(1!)¹ × (2!)² × (3!)³ × (4!)⁴

There are so many 2’s and 5 is absent here, then number of zeroes = 0

(5!)⁵ = (5 × 4 × 3 × 2 × 1)⁵ ⇒ Number of 5’s = 5

(6!)⁶ = (6 × 5 × 4 × 3 × 2 × 1)⁶ ⇒ Number of 5’s = 6

Similarly, (7!)⁷ ⇒ Number of 5’s = 7

And up to (9!)⁹, number of 5’s is successively increased by 1

(10!)¹⁰ = (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)¹⁰ ⇒ Number of 5’s =  20

And up to (14!)¹⁴, number of 5’s is successively increased by 2

(15!)¹⁵ = (15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)¹⁵ ⇒ Number of 5’s = 45

Total number of 5’s = 5 + 6 + 7 + 8 + 9 + 20 + 22 + 24 + 26 + 28 + 45 = 200

Total number of pairs of 2 and 5 = 200

Given:

The expression is 1⁵ × 2⁵ × 3⁵ × 4⁵ × … × 38⁵

Concept used:

To find the number of zeroes at the end of the product, we need to calculate the number of 2’s and number 5’s or number of pairs of 2 and 5.

2 × 5 = 10 ⇒ Number of zeroes = 1 (number of pair = 1)

The number of pairs of 2 and 5 is same as the number of zeroes at the end of the product

Calculation:

1⁵ × 2⁵ × 3⁵ × 4⁵ × … × 38⁵

In the above expression, number of 2’s is more than the number of 5’s. So we need to calculate the number of 5’s only

Number of 5’s

Total number of 5’s = 5 + 5 + 5 + 5 + 10 + 5 + 5 =40

There are only 40 pairs of 2 and 5 are possible.

1. disappointed

2. borrow.