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If n is an odd integer, then (1+I)6n+(1-i)6n is equal to |
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Answer» (1+i)6n+(1-i)6n = (1+2i+i2)3n+(1-2i+i2)3n = (1+2i-1)3n+(1-2i-1)3n = (+2i)3n+(-2i)3n = +(2i)3n-(2i)3n = 0 |
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