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Range and quatile deviation measure the dispersion by calculating the spread within which the values lie.

Writing observallons In ascending order
2. 3. 5. 8. 11, 15. 20
Here. n = 7
First quartile:
Q₁ = Value of (\(\frac{n+1}{4}\))th observation
= Value of (\(\frac{7+1}{4}\))
= 2nd observatIon
= 3

Third quartile:
Q₃ = Value of 3(\(\frac{n+1}{4}\)) th observation
= Value of 3 (2) = 6th observatIon
= 15

Coefficient of quartile deviation:
Coefficient of Q_d = \(\frac{Q_3−Q_1}{Q_3+Q_1}=\frac{15−3}{15+3}\)
= \(\frac{12}{18}=\frac{2}{3}\) = 0.67

Advantages of Mean Deviation:

• Its definition is clear.
• All the observations are used in its computation.
• Its value is less affected by the extreme observations as compared to other measures of dispersion.
• The total variations of the observations from their mean is considered in its computation.
• It is a better measure than range and Quartile deviation.
• It is useful as a measure of dispersion for the study of social sciences.

Disadvantages of Mean Deviation:

• Its computation is difficult as compared to the computation of range and Quartile deviation.
• It is not a suitable measure for other algebraic manipulations.
• It is less useful measure for the higher study of Statistics because of its dependence on the absolute value of deviation from the mean.
• It cannot be computed for open-ended frequency distribution.

Advantages of Standard Deviation:

• Its definition is clear and precise.
• All observations of the data are used in its computation.
• It is a more efficient measure of dispersion among the other measures of dispersion.
• If Mean and Standard deviations are given for two data sets, combined Standard deviation of new data set can be obtained. Thus, it is a suitable measure for other algebraic manipulations.
• It is widely used as basic measure in higher study of Statistics.

Disadvantages of Standard Deviation:

• Its computation is difficult as compared to other measures of dispersion.
• Extreme observations enjoy more weightage in its computations.
• It is not easy to understand for a common man.
• It cannot be obtained for the open-ended frequency distribution.

Advantages of Quartile Deviation:

• It’s definition is clear and it is easy to compute.
• Extreme observations do not affect its value.
• Quartile deviation can also be computed for the open-ended frequency distribution.

Disadvantages of Quartile Deviation:

• All the observations of the data are not used in its computation.
• It is not a suitable measure for other algebraic manipulations.
• It is widely affected by the fluctuations of sampling.
• This measure is less used for higher study in Statistics.

If the data of heights of 10 students are given in centimeter, the unit of its variance is (Centimeter)².

When each worker is given a hikes of 10% in wages both the mean and standard deviation values will be affected.

New Mean = Rs. 200 + 10 % of Rs. 200

= Rs. 200 + \(\frac{10}{100}\) x 200 = Rs. 220

New Standard Deviation

= Rs. 40 + 10% of Rs. 40 = Rs. 40 + \(\frac{10}{100}\) x 40 = Rs. 44.

 Here, largest value 

(L) = 40, smallest value (S) 

= 10 

∴ Range = L – S 

= 40 – 10 

= 30

Here, largest value 

(L) = 203, smallest value (S) = 114 

∴ Range = L – S 

= 203 – 114 

= 89

Correct Answer is: (C) Oligosaccharide 

Oligosaccharides are the carbohydrates which yield three to ten monosaccharide units upon hydrolysis

(B) Oligo-saccharide

(iv) Assertion is wrong statement but reason is correct statement. 

Phenol is more easily nitrated as compared to benzene. This is due to presence of –OH group in benzene ring in phenol, which activates the benzene ring for electrophilic substitution reaction sucha as nitration. 

Because it is accompanied by the formation of alkenes and is not a suitable method for the preparation of ether from acid catalyzed dehydration of 2° and 3°alcohol, as this reaction involve SN² mechanism, but dehydration of 2° and 3° alcohol, it follows SN¹ due to steric hindrance and tend to form alkenes preferably.

Due to presence of lone pair of electrons in the oxygen atom in ether, it acts as a lewis base.

Diethyl ether does not contain any active hydrogen.  

Alcohols phenols and ethers are a significant part of organic chemistry. Work your direction around these questions posed in the Alcohols, Phenols and Ethers Class 12 Mock Test. The topics Alcohols, Phenols and Ethers in the class 12 CBSE syllabus. For students who are looking to supplier their best presentation for the coming up board tests, it is vital that students study and update with the assistance of significant Questions. These significant Questions are known to practice throughout the long term and still represent a shot at coming in the impending test. 

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Click here for regular practice: - Class 12 The Haloalkanes and Haloarenes Mock Test

Alcohols are soluble in water due to formation of H-bond with water molecules. In the same way ether can also form H-bond with water molecules.

Due to electron withdrawing effect (-I effect)of the benzene ring, the C-O bond in phenol is less polar but in case of methanol due to electron-donating (+I effect) effect of CH₃ group, C-O bond is more polar.

a. Because of hydrogen bonding. 

b. With increase in molecular mass the non-polar alkyl group becomes more predominant. 

(iv) Assertion is wrong statement but reason is correct statement. 

(i) Due to electron withdrawing effect of phenyl group, the C— O bond in phenol is less polar, whereas in case of methanol the methyl group has electron releasing effect and hence C—O bond in it is more polar. 

(ii) C—O bond in phenols has partial double bond character due to resonance and hence is difficult to cleave. 

(i) Assertion and reason both are correct and reason is correct explanation of assertion. 

This is due to the fact that— 

(i) In phenol, conjugation of unshared electron pair over oxygen with aromatic ring results in partial double bond character in carbonoxygen bond. 

(ii) In phenol, oxygen is attached to a sp² hybridised carbon atom while in methanol, it is attached to a sp³ hyrbidised carbon atom. The bond formed between oxygen and sp² hybridised carbon is more stable than that formed between oxygen and sp³ hybridised carbon.

(b) Propanone

(a) Methanal

(b)  4 3 1 2

(a)  2 4 1 3

(a)  2 3 4 1

(a)  4 3 1 2

(a)  4 1 2 3

(a)   2 3 4 1

(a)  3 4 1 2

(b) Phenol is more acidic than ethanol

(a) protonatlon of alcohol

1. Ethylene glycol is used as an antifreeze in automobile radiator

2. Its dinitrate is used as an explosive with DNG.

(a)  2 3 4 1

(a)  CH₂ = CHI

 कमरे के ताप पर  मर्करी द्रव होती है |

(a)  4 1 2 3

Aniline l is heated with ammonia in the presence of anhydrous ZnCl₂

(a)  3 1 4 2

(c) Acetaldehyde

If the position of the shadow on the wall moves towards the north, the location of sunrise or sunset will shift southwards.

(c) The end of life

The correct answer is (A) North.

In 1734, Nawab Kapur Singh divided the Sikh soldiers into two groups, Buddha Dal and Tarun Dal.