This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ससंदर्भ भाव स्पष्ट कीजिए :कुछ भी बन बस कायर मत बन।ठोकर मार पटक मत माथा,तेरी राह रोकते पाहन।कुछ भी बन बस कायर मत बन॥ |
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Answer» प्रसंग : प्रस्तुत पद्यांश हमारी पाठ्य पुस्तक ‘साहित्य गौरव’ के आधुनिक कविता ‘कायर मत बन’ से लिया गया है जिसके रचयिता नरेन्द्र शर्मा हैं। संदर्भ : कवि मनुष्य को कायर न बनने का संदेश एवं मानवता को अत्यधिक महत्व देते हुए दुष्टों के सम्मुख आत्मसमर्पण न करने के लिए कहते हैं। व्याख्या : प्रस्तुत पद्यांश में कवि मनुष्य को संबोधित करते हुए कहते हैं कि हे मानव तुम सब कुछ बनो किन्तु डरपोक या कायर मंत बनो। मार्ग में यदि पत्थर भी तुम्हारे मार्ग को रोकते हैं, तो ठोकर मार कर उन्हें वहाँ से हटा दो, किन्तु उनके सामने तुम झुको नहीं। माथा पटकना अर्थात् जीवन में आनेवाली कठिनाइयों से निराश होना व्यर्थ हैं। विशेष : भाषा – शुद्ध साहित्यिक खड़ी बोली। |
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| 2. |
अबकी कौन घर लौटा? |
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Answer» अबकी कवि (कुँवर नारायण) घर लौटे। |
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| 3. |
देश को किससे बचाना है? |
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Answer» देश को दुश्मनों से बचाना है। |
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| 4. |
वृक्ष की पगड़ी कैसी है? |
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Answer» वृक्ष की पगड़ी फूल और पत्तीदार है। |
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| 5. |
सूखी डाल कैसी है? |
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Answer» सूखी डाल राइफिल-सी है। |
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| 6. |
What is the name of a line which intersects a circle at two distinct points ? |
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Answer» A line intersecting the circle at two distinct points is calIed a secant. |
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| 7. |
Write the effects of the World War II. |
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Answer» Second World War caused horrible destruction the world:
Communism in China:
The Beginning of Cold War – long term effects:
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| 8. |
Who was the trustworthy person for Nanasaheb Peshwa ? |
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Answer» Tatya Tope was the trustworthy person for Nanasaheb Peshwa. |
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| 9. |
Where did Nanasaheb stay in Gujarat ? |
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Answer» It is believed that Nanasaheb Peshwa stayed in village Shihor of Bhavnagar district in Gujarat. |
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| 10. |
Who undertook the leadership of the revolt in Kanpur? |
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Answer» Nanasaheb Peshwa undertook the leadership of the revolt in Kanpur. |
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| 11. |
When did the revolt of 1857 C.E. start? |
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Answer» The revolt of 1857 C.E. started on 10th May. |
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| 12. |
Which day was fixed for the start of the 1857 revolt?A. 20th MayB. 31st MayC. 1st JuneD. 10th July |
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Answer» Answer is B. 31st May |
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| 13. |
Who undertook the leadership of Nanasaheb Peshwa’s army in Kanpur ?A. Mangal PandeyB. Tatya TopeC. Bapu GaekwadD. Birsa Munda |
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Answer» B. Tatya Tope |
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| 14. |
Which were the centres of the revolt in North Gujarat ? |
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Answer» The centres of revolt in North Gujarat were Ahmedabad, Patan, Kheralu, Vijapur, Mudeti and Chandup (Chandap). |
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| 15. |
Who started the revolt of 1857 C.E. in Gujarat and when? |
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Answer» The 7th battalion of the British army joined the revolt in Ahmedabad, Gujarat, in June 1857 |
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| 16. |
Who started the revolt in Gujarat in June, 1858?A. Garbad Das Patel, the headman of Anand in Kheda districtB. 7th battalion of British Army in AhmedabadC. The Rajpipla battalion of Indian soldiers of NandodD. Jodha Manek of Umarpur |
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Answer» B. 7th battalion of British Army in Ahmedabad |
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| 17. |
When did the revolt of 1857 C.E. actually start?A. 12th JanuaryB. 15th AugustC. 10th NovemberD. 10th May |
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Answer» Answer is D. 10th May |
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| 18. |
Which prominent leader of the revolt stayed in Gujarat for approximately 15 days ?A. Nanasaheb PeshwaB. Bahadur Shah ZafarC. Tatya TopeD. Kunwarsingh |
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Answer» C. Tatya Tope |
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| 19. |
Which leader chopped off his hand from the elbow himself and offered it to river Ganges ?A. Nanasaheb PeshwaB. Bahadur Shah ZafarC. Tatya TopeD. Kunwarsingh |
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Answer» D. Kunwarsingh |
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| 20. |
Which one of the following does not increase while moving down the group of the periodic table? (a) Atomic radius (b) Metallic character(c) Valence (d) Number of shells in an element |
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Answer» The answer is (c) Valence Valency remain same in a group. ANSWER : c) Valence Valence electrons increase from left to right in a period and remain same from top to bottom in a group. |
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| 21. |
Which one of the following depicts the correct representation of the atomic radius(r) of an atom?(a) (i) and (ii) (b) (ii) and (iii) (c) (iii) and (iv) (d) (i) and (iv) |
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Answer» The answer is (b) (ii) and (iii) Atomic radius is the distance between the nucleus and outermost orbital is shown clearly in images ii) and iii) where as in image i) and iv) it is not depicted. |
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| 22. |
Three elements B, Si and Ge are (a) metals (b) non-metals (c) metalloids(d) metal, non-metal and metalloid respectively |
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Answer» The answer is (c) metalloids
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| 23. |
The element with atomic number 14 is hard and forms acidic oxide and a covalent halide. To which of the following categories does the element belong? (a) Metal (b) Metalloid (c) Non-metal (d) Left-hand side element |
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Answer» The answer is (b) Metalloid
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| 24. |
Which of the following elements will form an acidic oxide? (a) An element with atomic number 7 (b) An element with atomic number 3 (c) An element with atomic number 12(d) An element with atomic number 19 |
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Answer» The answer is (a) An element with atomic number 7
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| 25. |
Which of the following elements will form an acidic oxide?A. An element with atomic number 7 B. An element with atomic number 3 C. An element with atomic number 12 D. An element with atomic number 19 |
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Answer» If we see the options in (a) at. No 7 is nitrogen which forms 5 types of oxides in which some of them are neutral so we can’t say it forms acidic oxide and option (b) is at. no 3 which is lithium, it is a metal it forms basic oxide and same goes with option (c) it is magnesium which forms basic oxide too. In option (d) at. no 19 which is chlorine which forms all acidic oxides. |
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| 26. |
The element with atomic number 14 is hard and forms acidic oxide and a covalent halide. To which of the following categories does the element belong?A. Metal B. Metalloid C. Non-metal D. Left-hand side element |
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Answer» It is written that it forms acidic oxide so it is confirmed that the element is nonmetal and atomic number 14 element is carbon (C). |
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| 27. |
Is the function sin(sin1n) bijective? Which is defined on [-1, 1] to [-1, 1]. |
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Answer» Let f (n) = sin(sin-1n) let n1 n2 ∈ [-1, 1] f(n1) = f(n2) ⇒ sin(sin-1n1) = sin[sin1(n2)] ⇒ n1= n2 hence f is one-one let y = sin (sin-1 n) = n ∀ y ∈ [-1,1] ∃ [-1, 1] f(n) = n hence f is onto since f is one-one and onto it is bijective. |
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| 28. |
Which of the following is not a natural reflex action?(a) Knee-jerk(b) Blinking o f eyes due to strong light(c) Salivation at the sight of food(d) Sneezing when any irritant enters the nose |
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Answer» (c) Salivation at the sight of food |
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| 29. |
Explain the term Reflex action. |
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Answer» Reflex action is an action which is nearly instantaneous and not under the control of the will. The impulse passes from the sensory cells of the receptor organ along the dorsal root into the spinal cord. From here two messages pass simultaneously—one to the brain and the other travels out along the ventral root to reach the muscle which immediately responds. |
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| 30. |
Explain the term Natural reflex. |
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Answer» A natural reflex is the one in which no previous experience or learning is required and are inborn and protective, e.g., the sucking of milk of an infant from the breast of the mother or reflex of the eyelid. |
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| 31. |
A substance X, which is an oxide of a group 2 element, is used intensively in the cement industry. This element is present in bones also. On treatment with water, it forms a solution that turns red litmus blue. Identify X and also write the chemical reactions involved. |
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Answer» The X is Calcium oxide CaO(s) + H2O(l) → Ca(OH)2 (aq) |
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| 32. |
Give reason: Adsorption of hydrogen on glass is an endothermic process. |
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Answer» Adsorption of hydrogen on glass is an endothermic process because heat is absorbed during the process due to dissociation of hydrogen. |
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| 33. |
The following salts are formed by the reaction of an acid with a base :(i) Sodium chloride(ii) Ammonium nitrate.Identify the acid and the base and tabulate your answer in the format given below :S. No.SaltAcidBaseNature(i)Sodium chloride(ii)Ammonium nitrate |
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| 34. |
Which of the following quantities increase when wavelength is increased ? Consider only the magnitudes.(a) The power of a converging lens.(b) The focal length of a converging lens.(c) The power of a diverging lens.(d) The focal length of a diverging lens. |
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Answer» (b) The focal length of a converging lens. (d) The focal length of a diverging lens. |
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| 35. |
Which of the following quantities related to a lens depend on the wavelength or wavelengths of the incident light ?(a) Power(b) Focal length.(c) Chromatic aberration.(d) Radii of curvature. |
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Answer» (a) Power. (b) Focal length. (c) Chromatic aberration. |
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| 36. |
Which of the following quantities related to a lens depend on the wavelength or wavelengths of the incident light ? (a) Power (b) Focal length. (c) Chromatic aberration. (d) Radii of curvature. |
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Answer» The focal length, power and chromatic aberration are dependent on the refractive index of the lens, which itself is dependent on the wavelength of the light. |
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| 37. |
Energy of electron in the first Bohr orbit of H atom is -13.6 eV; then the energy in second Bohr orbit will be:A) -3.4 eVB) -6.8 eVC) -13.12 eVD) +3.4 eV |
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Answer» Correct Answer is: A) -3.4 eV The energy in second Bohr orbit will be -13.6 eV/n2 = -13.6 eV/(2)2 = -13.6/4 = -3.4 eV |
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| 38. |
For n-type Germaniums impurity, doped in GermaniumA) TrivalentB) TetravalentC) PentavalentD) None of these |
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Answer» Correct Answer is: C) Pentavalent Pure germanium may be converted into an n-type semiconductor by ‘’doping” it with any donor impurity having 5 valence electrons in its outer shell. |
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| 39. |
β rays deflected inA) Gravitational; fieldB) Only in magnetic fieldC) Only in electrical fieldD) In magnetic and electrical field both |
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Answer» Correct Answer is: D) In magnetic and electrical field both A magnetic field (only one pole is shown) affects radioactive rays differently depending on the type of ray. Alpha rays (heavy, positively charged particles) are deflected slightly in one direction. Beta rays (light, negatively charged electrons) are deflected strongly in the opposite direction. |
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| 40. |
β rays produces A) Isobar B) Isotopes C) Isotones D) All of these |
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Answer» The correct option is B) Isotopes. Radioactive isotopes (also called radioisotopes) have unstable nuclei. These isotopes disintegrate to form atoms with stable nuclei by the release of subatomic particles and gamma rays (akin to X-rays). Beta particles originate in the nucleus, presumably by breakdown of a neutron into its proton-electron components. |
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| 41. |
Let R be a relation defined as α RB if α is perpendicular to β, where α,β are straight line in a plane, then relation R is :(a) reflexive(b) symmetric(c) transitive(d) none of these |
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Answer» Answer is (b) symmetric |
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| 42. |
Find the acute angle between two straight lines whose direction ratios are (1,1,0) and (2,1,2). |
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Answer» Let L1 direction ratio is a = 1, b = 1, c = 0 and L2 direction ratio a2 = 2, b2 = 1, c2 = 2 Hence line L1 and L2 has acute angle, cos θ = |(a1a2 + b1b2 + c1c2)/(√(a21 + b21 + c21) x √(a22 + b22 + c22))| cos θ = |(1 x 2 + 1 x 1 + 0 x 2)/(√(12 + 12 + 02) x √(22 + 12 + 22))| cos θ = |(2 + 1 + 0)/√(1 + 1) x √(4 + 1 + 4)| cos θ = |3/(√2 x √9)| cos θ = |3/3√2| cos θ = 1/√2 cos θ = cos π/4 θ = π/4 |
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| 43. |
If x = 2α+1 and y = α-1 is a solution of the equation 2x-3y+5=0, find the value of α. |
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Answer» Given, x = 2α+1 and y = α-1 is a solution of the equation 2x - 3y + 5= 0 ⇒ 2 × (2α + 1) – 3(α – 1) + 5 = 0 ⇒ 4α + 2 – 3α + 3 + 5 = 0 ⇒ α = -10 |
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| 44. |
If x = 1 and y = 6 is a solution of the equation 8x - ay + a2=0, find the values of a. |
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Answer» Given, x = 1 and y = 6 is a solution of the equation 8x - ay + a2 = 0 ⇒ 8 × 1 – a × 6 + a2 = 0 ⇒ a2 – 6a + 8 = 0 ⇒ a2 – 4a – 2a + 8 = 0 ⇒ a(a – 4) – 2(a – 4) = 0 ⇒ (a – 2)(a – 4) = 0 ⇒ a = 2, 4 |
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| 45. |
If x = 1;y = 1 is a solution of the equation 3x + ay = 6, find the value of ‘a’. |
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Answer» Given that x = 1; y = 1 is a solution of 3x + ay = 6. Thus 3(1) + a(1) = 6 ⇒ 3 + a = 6 ⇒ a = 6 – 3 = 3 |
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| 46. |
If x = 2 – α and y = 2 + α is a solution of the equation 3x – 2y + 6 = 0, find the value of ‘α’. Find three more solutions of the resultant equation. |
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Answer» Given that x = 2 – α and y = 2 + α is a solution of 3x – 2y + 6 = 0 Thus 3 (2 – α) – 2 (2 + α) + 6 = 0 ⇒ 6 – 3α – 4 – 2α + 6 = 0 ⇒ -5α + 8 = 0 ⇒ -5α = -8 ∴ α = 8/5 Three more solutions are
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| 47. |
A number consisting of two digits is seven times the sum of its digits. When 27 is subtracted from the number, the digits are reversed. Find the number. |
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Answer» Let the tens and the units digits of the required number be x and y, respectively. Required number = (10x + y) 10x + y = 7(x + y) 10x + 7y = 7x + 7y or 3x – 6y = 0 ……….(i) Number obtained on reversing its digits = (10y + x) (10x + y) - 27 = (10y + x) ⇒10x – x + y – 10y = 27 ⇒9x – 9y = 27 ⇒9(x – y) = 27 ⇒x – y = 3 ……..(ii) On multiplying (ii) by 6, we get: 6x – 6y = 18 ………(iii) On subtracting (i) from (ii), we get: 3x = 18 ⇒ x = 6 On substituting x = 6 in (i) we get 3 × 6 – 6y = 0 ⇒ 18 – 6y = 0 ⇒ 6y = 18 ⇒ y = 3 Number = (10x + y) = 10 × 6 + 3 = 60 + 3 = 63 Hence, the required number is 63. |
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| 48. |
If 2x/3 - y/2 + 1/6 = 0 and x/2 + 2y/3 = 3 then(a) x = 2, y = 3 (b) x = - 2, y = 3 (c) x = 2, y = - 3 (d) x = - 2, y = - 3 |
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Answer» correct answer is (a) x = 2, y = 3 The given system of equations is \(\frac{2x}3-\frac{y}2+\frac{1}6=0\).......(i) \(\frac{x}2+\frac{2y}3=3\).........(ii) Multiplying (i) and (ii) by 6, we get 4x – 3y = –1 ……..(iii) 3x + 4y = 18 ………(iv) Multiplying (iii) by 4 and (iv) by 3 and adding, we get 16x + 9x = –4 + 54 ⇒ x = 50/25 = 2 Now, putting x = 2 in (iv), we have 3 × 2 + 4y = 18 ⇒ y = 18−6/4 = 3 Thus, x = 2 and y = 3. |
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| 49. |
A number consisting of two digits is seven times the sum of its digits. When 27 is subtracted from the number, the digits are reversed. Find the number. |
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Answer» Let us consider, one’s digit of a two digit number = x and ten’s digit = y The number is x + 10y After reversing the digits, One’s digit = y and ten’s digit = x The number is y + 10x As per the statement, x + 10y – 27 = y + 10x y + 10x – x – 10y = -27 9x – 9y = -27 x – y = -3 …(1) Again, 7 (x + y) = x + 10y 7x + 7y = x+ 10y 7x – x = 10y – 7y 6x = 3y 2x = y …(2) Using Substitution method: Substituting the value of y in (1) x – 2x = -3 -x = -3 or x = 3 From (2): y = 2(3) = 6 Answer: Number = x + 10y = 3 + 10( 6) = 63 |
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| 50. |
The sum of the digits of a two-digit number is 15. The number obtained by interchanging the digits exceeds the given number by 9. Find the number. |
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Answer» Let us consider, one’s digit of a two digit number = x and ten’s digit = y The number is x + 10y After interchanging the digits, One’s digit = y and ten’s digit = x The number is y + 10x As per the statement, x + y= 15 ………….(1) And, y + 10x = x + 10y + 9 y + 10x – x – 10y = 9 9x – 9y = 9 x – y = 1 …(2) On adding, we get 2x = 16 Or x = 8 On subtracting (2) from (1) 2y = 14 y = 7 Answer: Number = x + 10y = 8 + 10( 7) = 78 |
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