Energy of electron in the first Bohr orbit of H atom is -13.6 eV; then – InterviewSolution

1.

Energy of electron in the first Bohr orbit of H atom is -13.6 eV; then the energy in second Bohr orbit will be:A) -3.4 eVB) -6.8 eVC) -13.12 eVD) +3.4 eV

Answer»

Correct Answer is: A) -3.4 eV

The energy in second Bohr orbit will be

-13.6 eV/n² = -13.6 eV/(2)²

= -13.6/4

= -3.4 eV

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