If 2x/3 - y/2 + 1/6 = 0 and x/2 + 2y/3 = 3 then(a) x = 2, y = 3 (b) x

1.	If 2x/3 - y/2 + 1/6 = 0 and x/2 + 2y/3 = 3 then(a) x = 2, y = 3 (b) x = - 2, y = 3 (c) x = 2, y = - 3 (d) x = - 2, y = - 3
Answer» correct answer is (a) x = 2, y = 3 The given system of equations is \(\frac{2x}3-\frac{y}2+\frac{1}6=0\).......(i) \(\frac{x}2+\frac{2y}3=3\).........(ii) Multiplying (i) and (ii) by 6, we get 4x – 3y = –1 ……..(iii) 3x + 4y = 18 ………(iv) Multiplying (iii) by 4 and (iv) by 3 and adding, we get 16x + 9x = –4 + 54 ⇒ x = 50/25 = 2 Now, putting x = 2 in (iv), we have 3 × 2 + 4y = 18 ⇒ y = 18−6/4 = 3 Thus, x = 2 and y = 3.

If 2x/3 - y/2 + 1/6 = 0 and x/2 + 2y/3 = 3 then(a) x = 2, y = 3 (b) x = - 2, y = 3 (c) x = 2, y = - 3 (d) x = - 2, y = - 3

Answer»

correct answer is (a) x = 2, y = 3

The given system of equations is

\(\frac{2x}3-\frac{y}2+\frac{1}6=0\).......(i)

\(\frac{x}2+\frac{2y}3=3\).........(ii)

Multiplying (i) and (ii) by 6, we get

4x – 3y = –1 ……..(iii)

3x + 4y = 18 ………(iv)

Multiplying (iii) by 4 and (iv) by 3 and adding, we get

16x + 9x = –4 + 54

⇒ x = 50/25 = 2

Now, putting x = 2 in (iv), we have

3 × 2 + 4y = 18 ⇒ y = 18−6/4 = 3

Thus, x = 2 and y = 3.